On 12-02-10 12:48 PM, Justin Haynes wrote:
You can add
if(is.na(tab[i])) browser()
or
if(is.na(tab[i])) break
see inline
You can also do this temporarily. Supposing that you used
source(foo.R) to enter a function with that code in it, and you want
the check on line 10, you'd enter
Hi,
I'd like to debug in a loop (using debug() and browser() etc but not print()
). I'am looking for the first occurence of NA.
For instance:
tab = c(1:300)
tab[250] = NA
len = length(tab)
for (i in 1:len){
if(i != len){
tab[i] = tab[i]+tab[i+1]
}
}
I do not want to do Browse[2] n
You can add
if(is.na(tab[i])) browser()
or
if(is.na(tab[i])) break
see inline
On Fri, Feb 10, 2012 at 7:22 AM, ikuzar raz...@hotmail.fr wrote:
Hi,
I'd like to debug in a loop (using debug() and browser() etc but not
print()
). I'am looking for the first occurence of NA.
For instance:
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