Hi,
I have a vector and a matrix. For example,
A = [
12
3
4];
B = [
4 13
10 2
4 8];
I am comparing A to each column of B using AB[,ii], so the expected result
is
C = [
10
01
00];
I am looking for a way to do this quickly instead of going through the for
On 10/30/2011 02:51 PM, Wendy wrote:
Hi,
I have a vector and a matrix. For example,
A = [
12
3
4];
B = [
4 13
10 2
4 8];
I am comparing A to each column of B using AB[,ii], so the expected result
is
C = [
10
01
00];
I am looking for a way to do this quickly
Hi Wendy,
Most of the binary operators can deal with matrices and vectors natively:
A-c(12,3,4)
B-matrix(c(4,10,4,13,2,8),3,2)
B
[,1] [,2]
[1,]4 13
[2,] 102
[3,]48
BA
[,1] [,2]
[1,] TRUE FALSE
[2,] FALSE TRUE
[3,] FALSE FALSE
Cheers,
Tsjerk
On Sun, Oct 30,
Given that you want to compare
columns, you can just do:
A B
If you wanted to compare rows, then
it is more troublesome. One approach
would be:
rep(A, each=nrow(B)) B
On 30/10/2011 03:51, Wendy wrote:
Hi,
I have a vector and a matrix. For example,
A = [
12
3
4];
B = [
4 13
10
Hi,
To compare row wise is merely to compare column wise using the transpose matrix:
t(B) A
or
t(t(B)A)
if the result needs to be a matrix with dimensions equal to B.
Cheers,
Tsjerk
On Sun, Oct 30, 2011 at 9:44 AM, Patrick Burns pbu...@pburns.seanet.com wrote:
Given that you want to
The recycling rule should apply here (see 'An Introduction to R', Sec.
5.4.1; and ?Comparison, under 'Value').
x - -5:5
A - cbind(x, x, x)
vec - numeric(length(x))
A vec ### recycling
apply(A,2,``,vec) ### using apply
vec - numeric(11) + 3; vec[1] - -6
A vec ###
On 30.10.2011 04:51, Wendy wrote:
Hi,
I have a vector and a matrix. For example,
A = [
12
3
4];
B = [
4 13
10 2
4 8];
I am comparing A to each column of B using AB[,ii], so the expected result
is
C = [
10
01
00];
This list is about R rather than Matlab
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