Since you are loading lubridate it is enough to do
Atest$ddate1 <- dmy(Atest$ddate)
On Sun, Jun 9, 2024 at 11:59 PM Duncan Murdoch wrote:
>
> On 2024-06-09 4:39 p.m., Val wrote:
> > HI all,
> >
> > My
> > I am trying to convert character date (mm/dd/yy) to -mm-dd date
> > format in one of
On 2024-06-09 4:39 p.m., Val wrote:
HI all,
My
I am trying to convert character date (mm/dd/yy) to -mm-dd date
format in one of the columns of my data file.
The first few lines of the data file looks like as follow
head(Atest,10);dim(Atest)
ddate
1 19/08/21
2 30/04/18
Those a
Às 21:39 de 09/06/2024, Val escreveu:
HI all,
My
I am trying to convert character date (mm/dd/yy) to -mm-dd date
format in one of the columns of my data file.
The first few lines of the data file looks like as follow
head(Atest,10);dim(Atest)
ddate
1 19/08/21
2 30/04/18
3 28/0
HI all,
My
I am trying to convert character date (mm/dd/yy) to -mm-dd date
format in one of the columns of my data file.
The first few lines of the data file looks like as follow
head(Atest,10);dim(Atest)
ddate
1 19/08/21
2 30/04/18
3 28/08/21
4 11/10/21
5 07/09/21
6 15/08/21
7
And you will probably want to read the details of the ?round help, so
you understand how it handles 5 rounding. It is a little more
complicated than some of us learned in school.
On 11/22/2022 4:24 AM, Steven T. Yen wrote:
Thanks to all. And yes, Ivan, round() did it:
> dput(head(Mean))
c(
Thanks to all. And yes, Ivan, round() did it:
> dput(head(Mean))
c(afactfem = 0.310796641158209, afactblk = 0.188030178893171,
age = 45.3185794338312, nodiscfem = 0.506637018185968, discfem =
0.493362981814032,
notradgrol = 0.702915000493879)
> dput(head(Std.dev))
c(afactfem = 0.462819715443265
On Tue, 22 Nov 2022 08:15:57 +0800
"Steven T. Yen" wrote:
> Thanks to all, but no, signif() did not work:
It worked, just didn't do what you wanted it to do. I think you want
round(), not signif(). Some of your numbers (45.3185794) will be rounded
to 4 significant digits and others (0.096) w
???
> vals <- signif(cbind(c(.123,.0123), c(1.23,.00123)), digits = 2)
> print(vals)
[,1] [,2]
[1,] 0.120 1.2000
[2,] 0.012 0.0012
2 *significant* digits, but enough digits to right of decimal point to
**allow** the two significant digits to appear and have all numbers in
a column line up
Andrew's example works for him and for me.
If you want help, provide the output of
dput(head(Mean))
dput(head(Std.dev))
On November 21, 2022 4:15:57 PM PST, "Steven T. Yen" wrote:
>Thanks to all, but no, signif() did not work:
>
>> print(signif(cbind(Mean,Std.dev),digits=2))
> Mean Std.
Thanks to all, but no, signif() did not work:
> print(signif(cbind(Mean,Std.dev),digits=2))
Mean Std.dev
[1,] 0.310 0.46
[2,] 0.190 0.39
[3,] 45.000 16.00
[4,] 0.510 0.50
[5,] 0.490 0.50
[6,] 0.700 0.46
On 11/22/2022 5:41 AM, Andrew Simmons wrote:
For print()
,] 45.32 16.31
Regards
Duncan Mackay
-- Original Message --
From: "Jim Lemon"
To: "Steven T. Yen"
Cc: "R-help Mailing List"
Sent: Tuesday, 22 Nov, 2022 At 8:09 AM
Subject: Re: [R] Format printing with R
Hi Steven,
I thought that the problem might be in the
For print(), digits is the minimal number of significant digits. In
your case, rounding the first column to the 3rd decimal place gives at
least 2 sigfigs and rounding the second column to the 2nd decimal
place.
If you want to print all numbers to two significant digits, regardless
of what other n
For better reproducibility, use dput to share data. A matrix and a data frame
look similar, but they can act differently.
On November 21, 2022 1:09:55 PM PST, Jim Lemon wrote:
>Hi Steven,
>I thought that the problem might be in the two large numbers, but
>using a subset (I didn't want to edit ou
Hi Steven,
I thought that the problem might be in the two large numbers, but
using a subset (I didn't want to edit out all the line numbers), I get
what I expected:
sydf<-read.table(text="Mean Std.dev
[1,] 0.3107966 0.462820
[2,] 0.1880302 0.390736
[3,] 45.3185794 16.313635
[4,] 0.50663
Hi, I have two variables with 86 observations each. Below I print with
the print command with digit=2. But, I am getting three decimal places
for my first variable and two for the second. Please help. Thanks.
> cbind(Mean,Std.dev)
Mean Std.dev
[1,] 0.3107966 0.462820
[2,] 0.1
Got it, thanks!
On Tue, Dec 14, 2021 at 11:59 AM Ivan Krylov wrote:
>
> On Tue, 14 Dec 2021 11:54:08 +0100
> Luigi Marongiu wrote:
>
> > "9/29/2021"
>
> > format = "%d/%m/%y"
>
> > Why the conversion did not work?
>
> The according to the format, the date above is 9th of month No. 29 in
> the ye
On 14/12/2021 12:54, Luigi Marongiu wrote:
Hello,
I have these kind of dates:
```
ori[[n[3]]]
they look to me as month, date, year so I formatted them as:
```
Looks like that to me also.
as.Date(ori[[n[3]]], format = "%D")
# or: as.Date(ori[[n[3]]], format = "%d/%m/%y")
But you form
On Tue, 14 Dec 2021 11:54:08 +0100
Luigi Marongiu wrote:
> "9/29/2021"
> format = "%d/%m/%y"
> Why the conversion did not work?
The according to the format, the date above is 9th of month No. 29 in
the year 2020, followed by junk characters "21". Swap %m and %d to make
them follow the actual o
Dear Luigi,
Quickly, I spot two problems:
1) "09/20/2021" can only be month/day/year (and not day/month/year as
you specified).
2) The year is given with century, so it should be upper case Y
So
as.Date(ori[[n[3]]], format = "%m/%d/%Y")
should work.
HTH,
Ivan
--
Dr. Ivan Calandra
Imaging lab
Hello,
I have these kind of dates:
```
> ori[[n[3]]]
[1] "9/20/2021" "9/20/2021" "9/20/2021" "9/20/2021" "9/20/2021" "9/20/2021"
[7] "9/20/2021" "9/20/2021" "9/20/2021" "9/20/2021" "9/21/2021" "9/21/2021"
[13] "9/21/2021" "9/21/2021" "9/21/2021" "9/21/2021" "9/21/2021" "9/21/2021"
[19] "9/21/2021"
On 29/10/2021 1:21 p.m., Sam Albers wrote:
Hi all,
Does anyone know of a way to force utils::bibentry to mimic the BibTex
behaviour of using double { to force a "corporate name" in the author
field to print correctly? For example take this bibentry:
Enter it like this:
entry <- utils::bibentr
Maybe use \{ for the second one?
On Fri, Oct 29, 2021 at 11:22 AM Sam Albers
wrote:
> Hi all,
>
> Does anyone know of a way to force utils::bibentry to mimic the BibTex
> behaviour of using double { to force a "corporate name" in the author
> field to print correctly? For example take this biben
Hi all,
Does anyone know of a way to force utils::bibentry to mimic the BibTex
behaviour of using double { to force a "corporate name" in the author
field to print correctly? For example take this bibentry:
entry <- utils::bibentry(
bibtype = "Manual",
title = "The Thing",
author = "The Dat
Dear R-er,
I would like format integer number as characters with leading 0 for a
fixed width, for example:
1 shoud be "01"
2 shoud be "02"
20 should be "20"
Now I use:
x <- c(1, 2, 20)
gsub(" ", "0", format(x, width=2))
But I suspect more elegant way could be done directly with format
opt
Marc Girondot via R-help writes:
> I would like format integer number as characters with leading 0 for a
> fixed width, for example:
>
> 1 shoud be "01"
> 2 shoud be "02"
> 20 should be "20"
formatC(x, width=2, flag="0")
signature.asc
Description: PGP signature
___
On Thu, Jan 04, 2018 at 09:12:12PM +0100, Marc Girondot via R-help wrote:
> Dear R-er,
>
> I would like format integer number as characters with leading 0 for a
> fixed width, for example:
>
> 1 shoud be "01"
> 2 shoud be "02"
> 20 should be "20"
>
> Now I use:
>
> x <- c(1, 2, 20)
>
> gsub("
Dear R-er,
I would like format integer number as characters with leading 0 for a
fixed width, for example:
1 shoud be "01"
2 shoud be "02"
20 should be "20"
Now I use:
x <- c(1, 2, 20)
gsub(" ", "0", format(x, width=2))
But I suspect more elegant way could be done directly with format
opt
Hi Pedro,
Try this:
par(mar=c(5,5,4,2))
plot(seq(0,9000,1000),yaxt="n",ylab="")
axis(2,seq(1000,9000,1000),
labels=formatC(seq(1000,9000,1000),format="f",
big.mark=",",digits=2),las=2)
Jim
On Sun, Jun 4, 2017 at 7:11 PM, Pedro páramo wrote:
> Hi all,
>
> I have been looking on documentation
Hi all,
I have been looking on documentation but I´m not able to find how to
customize format on y axis so that for example:
y value goes from 1000 to 9000 it appears on thousand position a 1,000 and
on the comas with "," and two decimals.
(For the previous answers many thanks)
[[altern
Have you looked at the High Performance Computing Task View on CRAN?
Whatever you do, keep in mind that the algorithms you intend to apply will
have a strong impact on which data management approach is going to work best.
Start small before diving in with all your data, and try successively lar
What do you hope to do with this data while it is in R?
E.g., do you want to plot it, fit a model to it, to select a few
rows or columns from it, sort it, summarize lots of small subsets
of it, or something else?
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Dec 28, 2015 at 1:39 PM, Mark F
The problem is common, I have 100GB of data, but only 8GB of RAM. I was
thinking of transforming the 100GB of data, which right now is in a nonCSV,
fixed row format, to something that R could load quickly and easily in
chunks - sort of like pages perhaps.
I might be able to do this with some SQL s
:
Dear all,
I am a beginner in R and want to ask a simple question. I have a
code file in text format which I need to change to .r format
only. For example now it is RHtestsV4.r.txt which needs to be
changed to just RHtestsV4.r. I tried this
sub("^([^.]*).*", "\\1", &
ch I need to change to .r format only. For example now it
> is RHtestsV4.r.txt which needs to be changed to just RHtestsV4.r. I tried
> this
>
> sub("^([^.]*).*", "\\1", 'RHtestsV4.r.txt')
> [1] "RHtestsV4"
>
> But this didn't see
question. I have a code
>file
>in text format which I need to change to .r format only. For example
>now it
>is RHtestsV4.r.txt which needs to be changed to just RHtestsV4.r. I
>tried
>this
>
>sub("^([^.]*).*", "\\1", 'RHtestsV4.r.txt')
>[1]
nction using
source("RHtestsV4.r")
The error message is
Error in file(filename, "r", encoding = encoding) :
cannot open the connection
In addition: Warning message:
In file(filename, "r", encoding = encoding) :
cannot open file 'RHtestsV4.r': No such file o
Dear all,
I am a beginner in R and want to ask a simple question. I have a code file
in text format which I need to change to .r format only. For example now it
is RHtestsV4.r.txt which needs to be changed to just RHtestsV4.r. I tried
this
sub("^([^.]*).*", "\\1", &
The R Foundation is pleased to announce that our website
http://www.r-project.org/ has under gone a nice retouch (and
thus arrived in the 21st century :-)
Thanks to a working group of Dirk Eddelbuettel, Simon Urbanek and
Hadley Wickham.,
the current page sources are in markdown, and the html
Of course you could have created them as character vectors in the first
place:
dfx <- data.frame(
group = c(rep('A', 8), rep('B', 15), rep('C', 6)),
sex = sample(c("M", "F"), size = 29, replace = TRUE),
age = runif(n = 29, min = 18, max = 54),
stringsAsFactors=FALSE
)
But if that is no
Try as.character like the following shows.
> dfx <- data.frame(
+ group = c(rep('A', 8), rep('B', 15), rep('C', 6)),
+ sex = sample(c("M", "F"), size = 29, replace = TRUE),
+ age = runif(n = 29, min = 18, max = 54))
> dfx
group sex age
1 A M 41.35554346
2 A F 47.7
Dear R-List,
#I have a df with the first two cols formatted as factor.
dfx <- data.frame(
group = c(rep('A', 8), rep('B', 15), rep('C', 6)),
sex = sample(c("M", "F"), size = 29, replace = TRUE),
age = runif(n = 29, min = 18, max = 54))
# now I want to format both factor VARs as character
# I
ginal Message-
> From: David Winsemius [mailto:dwinsem...@comcast.net]
> Sent: Monday, October 20, 2014 11:04 PM
> To: PIKAL Petr
> Cc: Marc Girondot; r-help@r-project.org
> Subject: Re: [R] format negative numbers
>
>
> On Oct 20, 2014, at 4:32 AM, PIKAL Petr wrote:
>
&g
; already invented clever way how to deal with such numbers.
>
> Cheers
> Petr
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
>> project.org] On Behalf Of Marc Girondot
>> Sent: Monday, October 20, 2014 12:5
You could do it with minimal use of regular expressions, along the lines
of this example:
x <- c('123','2.31','2.313-', '45-')
is.neg <- grepl('-',x)
xn <- x
xn[is.neg] <- paste0( '-', substring(x[is.neg],1, nchar(x[is.neg])-1))
xn <- as.numeric(xn)
I made a copy, 'xn', so that
d clever way how to deal with such numbers.
Cheers
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Marc Girondot
> Sent: Monday, October 20, 2014 12:53 PM
> To: r-help@r-project.org
> Subject: Re: [R] form
Is it what you want?
> st <- "0.123-"
> gsub("(.+)(-)", "\\2\\1", st)
[1] "-0.123"
> st <- "0.123"
> gsub("(.+)(-)", "\\2\\1", st)
[1] "0.123"
Sincerely
Marc
Le 20/10/2014 09:03, PIKAL Petr a écrit :
Dear all.
Before I start fishing in (for me) murky regular expression waters I try to ask
co
Maybe not the most elegant way but at least works:
library( stringr )
x <- as.factor( "123.4-" )
x <- -as.numeric( str_replace( as.character( x ), "-", "" ) )
x
[1] -123.4
On Monday 20 October 2014 09:03:36 PIKAL Petr wrote:
> Dear all.
>
> Before I start fishing in (for me) murky regular expr
Dear all.
Before I start fishing in (for me) murky regular expression waters I try to ask
community about changing format of negative numbers.
For some reason I get a file with negative numbers formatted with negative sign
at end of number.
something like
0.123-
It is imported as factors and
Dear all,
I wasn't successful in finding any related "bug" or "wish" report on
bugs.r-project.org, svn.R-project.org/R/trunk/doc/NEWS.Rd, or RSeek
regarding the following:
The code of stats:::print.aov contains the two commands
cat("Residual standard error: ", sapply(sqrt(ss/rdf), format), "
ime(as.character(dat1$Date), "%Y-%m-%d")
dat1$Date1txt <- format(dat1$Date1, "%Y%m%d")
Stefano
Da: arun [smartpink...@yahoo.com]
Inviato: martedì 4 marzo 2014 17.06
A: r-help@r-project.org
Cc: Stefano Sofia
Oggetto: Re: [R] format
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Stefano Sofia
> Sent: Tuesday, March 04, 2014 11:58 AM
> To: r-help@r-project.org
> Subject: [R] format for as.Date and inserting missing rows in a data
Hi,
May be this helps:
dat <- read.table(text="Raingouge_number Station_number Year Month Day Rainfall
2004 2230 1951 1 1 2.60
2004 2230 1951 1 2 0.40
2004 2230 1951 1 3 0.00
2004 2230 1951 1 4 0.00
2004 2230 1951 1 5 0.20
2004 2230 1951 1 6 0.00
2004 2230 1951 1 7 0.00
2004 2230 1951 1 9 0.00
2004
Dear R users,
I have a very long data frame (50 years, more than 1.5 million rows) of daily
rainfall data from about 80 raingouges.
The data frame that I have been given looks like
Raingouge_number Station_number Year Month Day Rainfall
2004 2230 1951 1 1 2.60
2004 2230 1951 1 2 0.40
2004 2230 19
Hi,
Would this work?
format(Sys.time(), "%Y_%m_%d_%I_%M_%p")
A.K.
On Wednesday, January 15, 2014 10:37 AM, "Yuan, Rebecca"
wrote:
Hello all,
I know that the following code will give me the format of the Sys.time() till
hour (%I), how can I get that till min? what shall I add between %I and
ot;)
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Yuan, Rebecca
> Sent: Wednesday, January 15, 2014 3:56 PM
> To: R help
> Subject: [R] Format Sys.time()
>
> Hello all,
>
> I know that the follo
HI !!
try it
format(Sys.time(), "%Y_%m_%d_%X")
Best regards
...
Tanvir Ahamed
Göteborg, Sweden
From: "Yuan, Rebecca"
To: R help
Sent: Wednesday, 15 January 2014, 15:56
Subject: [R] Format Sys.time()
Hel
Hi
format(Sys.time(), "%Y_%m_%d_%I_%M%p")
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Yuan, Rebecca
> Sent: Wednesday, January 15, 2014 3:56 PM
> To: R help
> Subject: [R] Format Sys
Hello all,
I know that the following code will give me the format of the Sys.time() till
hour (%I), how can I get that till min? what shall I add between %I and %p?
format(Sys.time(), "%Y_%m_%d_%I_%p")
Thanks very much!
Cheers,
Rebecca
I find that google is usually a better search engine for R topics
Google on "R fractions".
(I got, e.g.
http://stackoverflow.com/questions/5046026/print-number-as-reduced-fraction-in-r
)
-- Cheers,
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Informa
library(MASS)
fractions(outer(1/seq(1:3), 1/seq(1:3)))
# [,1] [,2] [,3]
#[1,] 1 1/2 1/3
#[2,] 1/2 1/4 1/6
#[3,] 1/3 1/6 1/9
A.K.
On Tuesday, December 31, 2013 10:27 AM, Michael Friendly
wrote:
Is there some way to format a matrix of fractions as fractions? I think
I've seen
Is there some way to format a matrix of fractions as fractions? I think
I've seen this somewhere,
but search on Rseek came up empty.
Example:
> outer(1/seq(1:3), 1/seq(1:3))
[,1] [,2] [,3]
[1,] 1.000 0.500 0.333
[2,] 0.500 0.250 0.167
[3,] 0.333
-
From: Mathieu Basille [mailto:basille@ase-research.org]
Sent: Thursday, August 01, 2013 10:31 AM
To: R help
Cc: William Dunlap
Subject: Re: [R] 'format' behaviour in a 'apply' call depending on
'options(digits = K)'
Nicely spotted, Bill! You went much far
a R bug, or a OS-related bug, I don't know). Should I forward it to R-devel,
or some other place where R gurus may have a chance to look at it?
Mathieu.
Le 07/30/2013 02:34 PM, arun a écrit :
Hi Mathieu
yes, the original problem occurs in my system too. I am using R 3.0.1 on
linux mint 15. I
mint 15. I guess the default case would be trim=FALSE, but still it
>> looks very strange especially in ?apply(), as it starts from " 5"
>> onwards.
>>
>> sessionInfo()
>> R version 3.0.1 (2013-05-16)
>> Platform: x86_64-unknown-linux-gnu (64-bit)
&g
William Dunlap
> Subject: Re: [R] 'format' behaviour in a 'apply' call depending on
> 'options(digits = K)'
>
> Nicely spotted, Bill! You went much farther than I could have. We can
> basically summarize the problem with the following simple example:
&g
arun a écrit :
Hi Mathieu
yes, the original problem occurs in my system too. I am using R 3.0.1 on linux
mint 15. I
guess the default case would be trim=FALSE, but still it looks very strange
especially in
?apply(), as it starts from " 99995" onwards.
sessionInfo()
R version 3.0.1 (2013-05-16
quot; " 4" " 5" " 6" " 7" " 99998" " 9"
> print(x[i], digits=3)
[1] 1e+04 1e+04 1e+04 1e+04 1e+04 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05
[13] 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+05 1e+0
t attached):
[1] plyr_1.8tools_3.0.1
- Original Message -
From: Mathieu Basille
To: arun
Cc: R help
Sent: Tuesday, July 30, 2013 2:29 PM
Subject: Re: [R] 'format' behaviour in a 'apply' call depending on
'options(digits = K)'
Thanks Arun for you
ached):
[1] plyr_1.8 tools_3.0.1
- Original Message -
From: Mathieu Basille
To: arun
Cc: R help
Sent: Tuesday, July 30, 2013 2:29 PM
Subject: Re: [R] 'format' behaviour in a 'apply' call depending on
'options(digits = K)'
Thanks Arun for your ans
c = FALSE,trim=TRUE)
id2[0:100010]
# [1] "0" "1" "2" "3" "4" "5" "99996" "7"
#[9] "8" "9" "10" "11" "12" &
06" "17" "18" "19" "100010"
id2 <- format(1:11, scientific = FALSE,trim=TRUE)
id2[0:100010]
# [1] "0" "1" "2" "3" "4" "5" "6&quo
Thanks David for your interest. I have to admit that your answer puzzles me
even more than before. It seems that the underlying problem is way beyond
my R skills...
The generation of id2 is indeed quite demanding, especially compared to a
simple 'as.character' call. Anyway, since it seems to b
On Jul 30, 2013, at 9:01 AM, Mathieu Basille wrote:
> Dear list,
>
> Here is a simple example in which the behaviour of 'format' does not make
> sense to me. I have read the documentation and searched the archives, but
> nothing pointed me in the right direction to understand this behaviour. L
Dear list,
Here is a simple example in which the behaviour of 'format' does not make
sense to me. I have read the documentation and searched the archives, but
nothing pointed me in the right direction to understand this behaviour.
Let's start with a simple data frame:
df1 <- data.frame(x = r
University of Michigan):
-- snip ---
ICPSR releases new datasets in R format
ICPSR is pleased to announce that most new datasets we release will now be
available in R format. Along with data files readable by software packages
SAS, SPSS and Stata, data can now be downloaded as R
o: R help
Cc:
Sent: Friday, February 15, 2013 1:41 AM
Subject: [R] Format Integers
Dear all,
I would like to format the following numbers
xLabel
[1] 10 1000153846 1000307692 1000461538 1000615385 1000769231
[7] 1000923077 1001076923 1001230769 1001384615 1001538462 1001692308
[1
Dear all,
I would like to format the following numbers
xLabel
[1] 10 1000153846 1000307692 1000461538 1000615385 1000769231
[7] 1000923077 1001076923 1001230769 1001384615 1001538462 1001692308
[13] 1001846154 100200 1002153846 1002307692 1002461538 1002615385
[19] 1002769231 1002923
"array
bound exceeded". Does it has to do anything with the operating system? Does it
make any difference?
i hope there wont be any problemThanks in advance
Eliza
> From: macque...@llnl.gov
> To: eliza_bo...@hotmail.com; r-help@r-project.org
> Subject: Re: [R] FORMAT EDITING
You say, "Š use the R output file in Fortran Š "
I guess that means that R is writing an output file which will then be
used as an input file for a fortran program.
In that case, you need to go back to how R is writing the output file,
find out why it is writing blank lines, and correct it. As far
4 445.000
1924.11. 5 449.000
1924.11. 6 442.000
1924.11. 7 445.000
",sep="",header=FALSE,stringsAsFactors=FALSE)
dat1
# V1 V2 V3
#1 1901.11. 1 447
#2 1901.11. 2 445
#3 1901.11. 3 445
#4 1924.11. 4 445
#5 1924.11. 5 449
#6 1924.11. 6 442
#7 1924.11. 7 445
---
Dear R users,[IF THE FORMAT OF MY EMAIL IS NOT CLEAR, I HAVE ATTACHED A TEXT
FILE FOR A CLEAR VIEW]
I would like to use the R output file in Fortran. my file Is exactly in the
following format.
ELISA/BOTTO wATER INN
FROM 1900 11 1 TO 1996 12 31
1901.11. 1 447.000
1901.11. 2
ges
> Cc: r-help@r-project.org
> Subject: Re: [R] Format of numbers in plotmath expressions.
>
>
>
> Thanks Uwe. I think your recipe is substantially sexier than mine.
>
> However I will, I believe, ***NEVER*** understand how to put together
> plotmath con
Thanks Uwe. I think your recipe is substantially sexier than mine.
However I will, I believe, ***NEVER*** understand how to put together
plotmath constructs. They seem to require some subset of:
* expression()
* bquote()
* substitute()
* parse()
* paste()
* as.express
On 05.10.2012 09:30, Rolf Turner wrote:
I want to do something like:
TH <- sprintf("%1.1f",c(0.3,0.5,0.7,0.9,1))
plot(1:10)
legend("bottomright",pch=1:5,legend=parse(text=paste("theta ==",TH)))
Notice that the final "1" comes out in the legend as just plain "1" and NOT
as "1.0" although TH i
I want to do something like:
TH <- sprintf("%1.1f",c(0.3,0.5,0.7,0.9,1))
plot(1:10)
legend("bottomright",pch=1:5,legend=parse(text=paste("theta ==",TH)))
Notice that the final "1" comes out in the legend as just plain "1" and NOT
as "1.0" although TH is
[1] "0.3" "0.5" "0.7" "0.9" "1.0"
I can
> as.POSIXct("5/1/2012 8:00:00 PM", format = "%m/%d/%Y %I:%M:%S %p")
[1] "2012-05-01 20:00:00 EDT"
On Mon, Jul 16, 2012 at 9:26 AM, Lauren Vogric
wrote:
> How do I format "5/1/2012 8:00:00 PM" into a date?
>
>
> [[alternative HTML version deleted]]
>
> ___
Ms Vogric,
as.POSIXct should be able to help there...
On 16 July 2012 06:40, Jessica Streicher wrote:
> ?Date
> ?POSIXct
>
> and here you can find the formatting symbols:
> http://stat.ethz.ch/R-manual/R-patched/library/base/html/strptime.html
>
>
> On 16.07.2012, at 15:26, Lauren Vogric wrote:
?Date
?POSIXct
and here you can find the formatting symbols:
http://stat.ethz.ch/R-manual/R-patched/library/base/html/strptime.html
On 16.07.2012, at 15:26, Lauren Vogric wrote:
> How do I format "5/1/2012 8:00:00 PM" into a date?
>
>
> [[alternative HTML version deleted]]
>
>
How do I format "5/1/2012 8:00:00 PM" into a date?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.ht
Thank you, that's very useful.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 6/19/12 1:11 PM, "baptiste auguie"
wrote:
>Have a look at this:
>
>http://stackoverflow.com/questions/7734535/control-font-thickness-without-
Have a look at this:
http://stackoverflow.com/questions/7734535/control-font-thickness-without-changing-font-size
and
http://stackoverflow.com/questions/10686054/outlined-text-with-ggplot2
which refers to a base graphics version.
HTH,
b.
On 20 June 2012 07:58, MacQueen, Don wrote:
> I'm usin
I'm using mtext() to annotate a plot. I would like, if possible, to have
the individual characters formatted with an outline or border, with a
contrasting fill color inside the borders.
I'd appreciate suggestions or pointers toward a way to do this.
The reason is because I'm creating a graphic wi
Duncan,
On 25 March 2012 15:28, Duncan Murdoch wrote:
> In case anyone is interested, I want to output code in a language (GLSL)
> that sees 1 and 1. as different types. I want a floating point value, so I
> need the decimal point.
GLSL, assuming it's the one that I'm looking at[1], supports im
On 12-03-25 10:45 AM, Marc Schwartz wrote:
On Mar 25, 2012, at 7:14 AM, Duncan Murdoch wrote:
On 12-03-24 10:47 PM, J Toll wrote:
On Sat, Mar 24, 2012 at 7:30 PM, Duncan Murdoch
wrote:
Do we have a format that always includes a decimal point and a given number
of significant digits, but o
On Mar 25, 2012, at 7:14 AM, Duncan Murdoch wrote:
> On 12-03-24 10:47 PM, J Toll wrote:
>> On Sat, Mar 24, 2012 at 7:30 PM, Duncan Murdoch
>> wrote:
>>> Do we have a format that always includes a decimal point and a given number
>>> of significant digits, but otherwise drops unnecessary charac
On 12-03-24 10:47 PM, J Toll wrote:
On Sat, Mar 24, 2012 at 7:30 PM, Duncan Murdoch
wrote:
Do we have a format that always includes a decimal point and a given number
of significant digits, but otherwise drops unnecessary characters? For
example, if I wanted 5 digits, I'd want the following:
On Sat, Mar 24, 2012 at 7:30 PM, Duncan Murdoch
wrote:
> Do we have a format that always includes a decimal point and a given number
> of significant digits, but otherwise drops unnecessary characters? For
> example, if I wanted 5 digits, I'd want the following:
>
> Round to 5 digits:
> 1.234567
Do we have a format that always includes a decimal point and a given
number of significant digits, but otherwise drops unnecessary
characters? For example, if I wanted 5 digits, I'd want the following:
Round to 5 digits:
1.234567 -> "1.2346"
Drop unnecessary zeros:
1.23 -> "1.23"
Force
Omitting the leading zero is dangerous, since the decimal point can disappear
in a poor hardcopy leading to later misinterpretation.
---
Jeff NewmillerThe . . Go Live...
DCN:B
quot; ".005" ".01" ".02" ".04" ".08" "-.005"
[8] "-.01" "-.02" "-.04" "-.08" "1000"
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
>
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