Dear R-helpers,
Ive got a summary of results from a by() call that I am making with a list
of more than two of factors not very different from the example in the by()
help page
require(stats)
by(warpbreaks[, 1], warpbreaks[, -1], summary)
The result of the command gives a
Hello,
Try
do.call(data.frame, by.list)
Hope this helps,
Rui Barradas
Em 09-10-2012 17:53, Jesus Frias escreveu:
Dear R-helpers,
I've got a summary of results from a by() call that I am making with a list
of more than two of factors not very different from the example in the by()
On Tue, Oct 9, 2012 at 11:42 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Try
do.call(data.frame, by.list)
I don't think data.frame inside do.call works in this context. May need it
on the outside to do the job (Only OK here since there is no mixture of
numeric and character/factors
Ilai, et. al:
Yes. The OP might also look at the result of:
t(simplify2array (by.list))
The only wrinkle here (with either rbind or simplify2array) is getting
the labels correct if the design is not fully crossed -- i.e. if some
groups are missing so that expand.grid() won't work. Then you
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter gunter.ber...@gene.com wrote:
The only wrinkle here (with either rbind or simplify2array) is getting
the labels correct if the design is not fully crossed -- i.e. if some
groups are missing so that expand.grid() won't work. Then you might
have to
You're right, I was in a hurry. This one works.
x - rnorm(100)
a - sample(letters[1:4], 100, T)
by.list - by(x, a, summary)
do.call(rbind, as.list(by.list))
(I would also prefer aggregate.)
Rui Barradas
Em 09-10-2012 19:46, ilai escreveu:
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter
6 matches
Mail list logo
