inal Message -
From: cowboy
To: r-help@r-project.org
Cc:
Sent: Monday, June 18, 2012 11:32 PM
Subject: [R] how to use by function
hi all,
Assume I have data like
data<-rbind(c(1,2),c(1,3),c(2,1),c(3,2),c(3,4))
I want to get some matrix like
1,2,3
2,NA,NA
3,2,4
I'm using by
mat<-matrix(
Hello,
Your code is not working because you are not understanding what's
written in the help page for 'by'.
'by' breaks its first argument, a data.frame, (could be matrix) into
sets of rows using 'index' to do the breaking. Each set of rows is the
argument for FUN, a function that already ex
hi all,
Assume I have data like
data<-rbind(c(1,2),c(1,3),c(2,1),c(3,2),c(3,4))
I want to get some matrix like
1,2,3
2,NA,NA
3,2,4
I'm using by
mat<-matrix(NA,3,3)
by(data,data[,1],mat[data[,1],]<-c(data[,2]))
but it doesn't work.
Any ideas?
thanks,
cowboy
_
Jim Moon ohsu.edu> writes:
> How might one accomplish this using the by() function?
> m1 is a data frame.
>
> # populate column "m1$major_allele"
> for ( i in 1:length(m1$major_allele)) {
> if ( m1$Freq1[i] == m1$MAF[i]){
> m1$major_allele[i] = m1$Al1[i]
> }
> else{
> m1$major_alle
... or slightly less verbose:
m1 <- within(m1,major_allele <- ifelse( Freq1 == MAF, Al1, Al2 ))
?within
Cheers,
Bert
On Mon, Nov 29, 2010 at 10:25 AM, Greg Johnson wrote:
> Jim Moon ohsu.edu> writes:
>
>> How might one accomplish this using the by() function?
>> m1 is a data frame.
>>
>> #
Jim Moon ohsu.edu> writes:
> How might one accomplish this using the by() function?
> m1 is a data frame.
>
> # populate column "m1$major_allele"
> for ( i in 1:length(m1$major_allele)) {
> if ( m1$Freq1[i] == m1$MAF[i]){
> m1$major_allele[i] = m1$Al1[i]
> }
> else{
> m1$major_all
Hello, All!
How might one accomplish this using the by() function?
m1 is a data frame.
# populate column "m1$major_allele"
for ( i in 1:length(m1$major_allele)) {
if ( m1$Freq1[i] == m1$MAF[i]){
m1$major_allele[i] = m1$Al1[i]
}
else{
m1$major_allele[i] = m1$Al2[i]
}
}
Jim
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