How does one link two datasets using the compare.linkage function in the
RecordLinkage package? This is to follow-up on my original posting earlier
today:
https://stat.ethz.ch/pipermail/r-help/2016-January/435736.html
I suggested then that I should perhaps have added the identity argument.
But if
# only a update the R code (with strange behavior)
library( tcltk ); tclRequire( "Tktable" )
top <- tktoplevel()
tcl('variable', 'myarray')
tcl('array', 'unset', 'myarray')
x <- 0
tabCmd <- function() {
x <<- x + 1
return( as.tclObj( paste(x) ) )
}
tab <- tkwidget( top, 'table', rows=2,
How to capture the output from the "command" option of tktable and how
to send input to it?
As far as I understand, the most appropriate way to use the tktable is
through the flag usecommand and command.
It fires the string information and cell coordinates and wait for a new
string to set a
You may use the "caret" package.
At the following link 2-classes and 3-classes examples:
http://www.inside-r.org/node/86995
--
GG
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Dear Colleagues
I need someone to kindly help me solving this problem.
A sample of 89 patients was tested for 4 tumor types (T1, T2, T3, T4).
The results of the operative predicted T stage and those of the pathology
tests are tabulated in the following table:
This looks like homework to me and this list has a No-Homework policy. Now,
once you have done your homework (and that includes reading the documentation
of the functions you are using), and you are still confused about details, you
are welcome to ask again. Please keep the following in mind:
Dear R list,
I am trying to plot the curve of a function.
Here's the R code:
library(mvtnorm)
p <- function(x, mu){
mu <- c(mu, 0)
dmvnorm(c(x, 1), mu, diag(2))
}
> curve(p(x, 2), from = 0, to =1)
Error in dmvnorm(c(x, 1), mu, diag(2)) :
mean and sigma have non-conforming size
I
Never mind, I figured it out.
You need to use sapply(), for instance, curve(sapply(x, p), from = 0, to
=10)
Thanks all!
On Tue, Oct 27, 2015 at 11:14 AM, C W wrote:
> Dear R list,
>
> I am trying to plot the curve of a function.
>
> Here's the R code:
>
> library(mvtnorm)
>
Hi All:
I am trying to use the dwish function in the MCMCpack in R
dwish(W, v, S) where
Arguments
W-Positive definite matrix W
v-Degrees of freedom (scalar).
S-Inverse scale matrix
How do I determine W, the positive definite matrix. The matrix provided in
the documentation doesnot help.
I put in the matrix at which I want the density as S. I was wondering what
is W then?
Thanks
Anamika
On Thu, Sep 3, 2015 at 12:28 PM, Duncan Murdoch
wrote:
> On 03/09/2015 9:29 AM, Anamika Chaudhuri wrote:
> > Hi All:
> >
> > I am trying to use the dwish function in
On 03/09/2015 9:29 AM, Anamika Chaudhuri wrote:
> Hi All:
>
> I am trying to use the dwish function in the MCMCpack in R
>
> dwish(W, v, S) where
>
> Arguments
> W-Positive definite matrix W
> v-Degrees of freedom (scalar).
> S-Inverse scale matrix
>
> How do I determine W, the positive
On 03/09/2015 12:41 PM, Anamika Chaudhuri wrote:
> I put in the matrix at which I want the density as S. I was wondering
> what is W then?
You need to read the help page. The matrix at which you want the
density is W. S is a parameter of the distribution.
Duncan Murdoch
>
> Thanks
> Anamika
Dear experts,
i want to use nlme or plm to analysis mixed effect model, my data has the
format :
city year area y x
1 2010 A 1.2 2
1 2011 A 3 3
2 2010 A 5 4
2 2011 A 2.1 1.8 3 2010 B 1.7 2
I
Hi Philippe,
Ah! Thanks for pointing out the pesky ifelse() issue. I have only recently
been learning (the hard way) that ifelse() is not a tool for the uninformed
like me, but it is ever so tempting!
I would like to offer another way to speed things up. findInterval() can be
quite fast,
Also note that ifelse() should be avoided as much as possible. To define a
piecewise function you can use this trick:
func - function (x, min, max) 1/(max-min) * (x = min x = max)
The performances are much better. This has no impact here, but it is a good
habit to take in case you manipulate
On 31 Jan 2015, at 09:39 , Rolf Turner r.tur...@auckland.ac.nz wrote:
On 31/01/15 21:10, C W wrote:
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
}
curve(func(min = 0.5, max = 1.3), from = 0, to = 2)
curve() wants an expression, but I have a constant. And I
On 31/01/15 21:10, C W wrote:
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
}
curve(func(min = 0.5, max = 1.3), from = 0, to = 2)
curve() wants an
Hello,
The following will work, but I don't know if it's what you want. func2
will get x and y from the global environment.
func2 - function(mu){
x + y + mu ^ 2
}
curve(func2, from = 0, to = 10)
Hope this helps,
Rui Barradas
Em 29-01-2015 21:02, C W escreveu:
Hi all,
I want to graph
Hi all,
I want to graph a curve as a function of mu, not x.
Here's the R code:
x - rnorm(10)
y - rnorm(10)
func - function(x, y, mu){
x + y + mu ^ 2
}
curve(f = func(x = x, y = y, mu), from = 0, to = 10)
I know I can change variable mu to x, but is there a way to tell R that mu
is the
Hi Rui,
Thank you for your help. That works for now, but eventually, I need to be
pass in x and y.
Is there a way to tell the curve() function, x is a fix vector, mu is a
variable!
Thanks,
Mike
On Thu, Jan 29, 2015 at 5:25 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
The following
Does
help(curve)
talk about its 'xname' argument?
Try
curve(10*foofoo, from=0, to=17, xname=foofoo)
You will have to modify your function, since curve() will
call it once with a long vector for the independent variable
and func(rnorm(10), rnorm(10), mu=seq(0,5,len=501)) won't
work right.
Hi Bill,
You solved by problem. For some reason, I thought xname was only referring
to name of the x-axis.
I remember last time I fixed it, it was something about xname, couldn't get
it right this time.
Thanks! Saved me hours from frustration.
Mike
On Thu, Jan 29, 2015 at 9:04 PM, William
Dear All!!
I'll try to plot a barplot using aggplot2
head(alt)
as.factor.data...7..Col ColMat Fastq miseq
1 189158158158104
2 190 54272 54272 54272 32122
3 191 301574 301574 301574 152625
4 192 161620
(aa)))
p1 - p1 + geom_bar(stat = identity)
p1
John Kane
Kingston ON Canada
-Original Message-
From: jarod...@libero.it
Sent: Wed, 26 Nov 2014 18:04:21 +0100 (CET)
To: r-help@r-project.org
Subject: [R] How to use ggplot2
Dear All!!
I'll try to plot a barplot using aggplot2
Dear expeRts,
Now i have a train dataset a and test dataset b , i using the
following codes:
rp-rpart(y~.,data=a,method=class)
plot(rp)
text(rp)
but how can i use the trained model to predict b?
TKS.
--
PO SU
mail: desolato...@163.com
Majored in Statistics from SJTU
On Nov 11, 2014, at 7:47 PM, PO SU rhelpmaill...@163.com wrote:
Dear expeRts,
Now i have a train dataset a and test dataset b , i using the
following codes:
rp-rpart(y~.,data=a,method=class)
plot(rp)
text(rp)
but how can i use the trained model to predict b?
?predict
--
HI,
Try this:
results - predict(rp,b,type = vector)
Regards,
Bharat
On 12 November 2014 09:17, PO SU rhelpmaill...@163.com wrote:
Dear expeRts,
Now i have a train dataset a and test dataset b , i using the
following codes:
rp-rpart(y~.,data=a,method=class)
plot(rp)
text(rp)
OK , i tried predict(rp,b) but showed me a result which i can't understand, now
it's the argument type=vector worked.
--
PO SU
mail: desolato...@163.com
Majored in Statistics from SJTU
At 2014-11-12 11:55:08, Bharat Bargujar bharatbargu...@gmail.com wrote:
HI,
Try this:
results -
Tks for all your help, finally i choose the way in Rstudio ctrl+shift+C, and
do twice to cancel those comments. It's enough for me now. BTW, I also like the
way:
if(FALSE) {} :)
--
PO SU
mail: desolato...@163.com
Majored in Statistics from SJTU
At 2014-09-10 02:15:49, Gjalt-Jorn
I don't understand what's your meaning, do you mean that i should do some file
processing,(like writing a script) ,so that i could add # in any line i
wanted.
I think it is not convenient.
And, it does seems that there is no way to multi line comment in R. But when i
turn to using Rstudio,
On 09-09-2014, at 08:25, PO SU rhelpmaill...@163.com wrote:
I don't understand what's your meaning, do you mean that i should do some
file processing,(like writing a script) ,so that i could add # in any line i
wanted.
I think it is not convenient.
And, it does seems that there is
No I don't mean this. Did you at least try the small example I provided?
On Tue, Sep 9, 2014 at 3:25 PM, PO SU rhelpmaill...@163.com wrote:
I don't understand what's your meaning, do you mean that i should do some
file processing,(like writing a script) ,so that i could add # in any line i
On 08/09/2014, 11:14 PM, Jeff Newmiller wrote:
There are no multi line comment markers in R. However, since you are always
referring to RStudio you might want to look into roxygen, since their editor
supports that tool.
RStudio has a command to comment a block: it's in the Code menu. (On
PS == PO SU rhelpmaill...@163.com
on Tue, 9 Sep 2014 10:49:32 +0800 writes:
PS Dear expeRts, I find it's terrible when i want to
PS comment multi paragraph (e.g. a 30 lines function) , i
PS have to comment each line with #, is there any good way
PS to do that ? I
-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of PO SU
Sent: Monday, September 08, 2014 10:50 PM
To: R. Help
Subject: [R] How to use multi paragraph comment like /* and */ in cpp?
Dear expeRts,
I find it's terrible when i want to comment multi paragraph (e.g
In R-studio, you can also select whatever you want to comment out, and
press CTRL-SHIFT-C to comment the selection in one go.
To uncomment it all in one go again, you can select it again and press
CTRL-SHIFT-C again.
Gjalt-Jorn
On 2014-09-09 5:51, Pascal Oettli wrote:
A workaround is to
One way I know to do this is (in bash) to use a dummy variable and make the
comment a multiline character string:
dummy - c(
This is my multiline
comment or code block.
)
or if printing does not disturb you, just use:
...
Use ' if you have in the block.
Other workarounds are here, which you
Dear expeRts,
I find it's terrible when i want to comment multi paragraph (e.g. a 30
lines function) , i have to comment each line with #, is there any good way to
do that ?
I investgate it, but found no easy way, may you help me ?
--
PO SU
mail: desolato...@163.com
Majored in
There are no multi line comment markers in R. However, since you are always
referring to RStudio you might want to look into roxygen, since their editor
supports that tool.
I would also suggest making more functions that are smaller.
A workaround is to escape the evaluation of the lines. For example:
tt - 0
while(tt 0){
cat('rr\n')
}
Regards,
Pascal
On Tue, Sep 9, 2014 at 11:49 AM, PO SU rhelpmaill...@163.com wrote:
Dear expeRts,
I find it's terrible when i want to comment multi paragraph (e.g. a 30
lines
Dear list-members,
I discover recently bbmle package from an answer in r-list. It makes
some analyses more easily to solve. However I have one problem using
fixed parameter of mle2 and one question about parametrization of mle2.
I send the question directly to the maintainer of the package but
Hi Boris,
yes I tried this way and it worked. The fact is that I wanted to be
compliant with the old code, I did not want to change anything. So I wanted
to find a new way to rewrite the code.
Thanks
~ Francesco Brundu
On 19 April 2014 23:18, Boris Steipe boris.ste...@utoronto.ca wrote:
Have
Thanks Boris for the detailed answer. I thought to make it backward
compatible because I did not know if gamma parameter would change the
result if absent. As far as I can see changes in my results are not
relevant, so I think to follow your advice to update the old code.
Thanks
~ Francesco
Hi all,
I am using an old code (probably written for R 2.5) and it stops when
calling rainbow() with gamma argument. I saw that gamma argument is not
present in newer version of R rainbow function. How can I translate this
line of code:
rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75,
Have you looked at ?rainbow ?
Is there a reason why you don't simply leave the gamma parameter away?
Try:
pie(rep(1,100), col=rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75))
Cheers,
B.
On 2014-04-19, at 6:05 AM, Francesco Brundu wrote:
Hi all,
I am using an old code (probably
If it MUST be parameter-compatible with the old call, you could just add ...
to your local version of rainbow. The unused parameter will then be dropped.
Here's how:
# The original creates an error ...
rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75, gamma = 1.5)
Error in rainbow(100,
Hi,
May be this helps:
stations - LETTERS[1:4]
set.seed(42)
PM2.5 - data.frame(DateTime=seq(as.POSIXct(2010-01-10
01:00:00),length.out=10,by= 1 day), station=
sample(LETTERS[1:4],10,replace=TRUE))
for(i in 1:length(stations))
Hi,
It is not clear what you really want. Now, you mentions ?merge() etc. If you
don't want to use ?assign(),
lst - list(as.data.frame(matrix(1:40,ncol=5)),
as.data.frame(matrix(1:20,ncol=4)),
as.data.frame(matrix(1:25,ncol=5)),as.data.frame(matrix(21:30,ncol=2)))
stations -
Hello,
I used PBC data set included in the survival package to fit a cox
model. The model included a restricted cubic spline transformation on
age. Then I tried using survfit function to predict a survival curve
using the first row of the original data. I got an error message. The
R code and
, March 05, 2014 10:52 PM
To: r-help@r-project.org
Cc: therneau.te...@mayo.edu
Subject: [R] How to use restricted cubic spline in survfit.cph function in
survival package?
Hello,
I used PBC data set included in the survival package to fit a cox
model. The model included a restricted cubic spline
I have never used R-help to pose a question to the R-users community; is
sending this Email the right way to do so?
I am trying to use the ddply function in the plyr package to accomplish the
following:
I have a data frame of the type:
ticker monthend_n wgtdiff ret
156 AA
Hi,
Try:
ddply(test,.(monthend_n),mutate,quintiles=cut(wgtdiff,5))
A.K.
On Monday, January 13, 2014 5:32 PM, Amitabh Dugar cleverc...@yahoo.com wrote:
I have never used R-help to pose a question to the R-users community; is
sending this Email the right way to do so?
I am trying to use the
On Jan 13, 2014, at 1:29 PM, Amitabh Dugar wrote:
I have never used R-help to pose a question to the R-users community; is
sending this Email the right way to do so?
I am trying to use the ddply function in the plyr package to accomplish the
following:
I have a data frame of the type:
Hi all:
Assume that I have variables, say v1, v2,...,v100 and I want to use one
variable in each roop. How can I do this? See below
for (i in 1:100){
f(vi)
}
Thanks
David
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
Hi,
If the variables described are the columns in a data.frame,
set.seed(24)
dat1 - as.data.frame(matrix(sample(100,100*10,replace=TRUE),ncol=100))
f1 - function(x) mean(x,na.rm=TRUE)
sapply(1:100,function(i) f1(dat1[,i]))
#or
sapply(colnames(dat1),function(x) f1(dat1[,x]))
#IF these are
Hi David,
On 12/14/2013 01:06 PM, Marino David wrote:
Hi all:
Assume that I have variables, say v1, v2,...,v100 and I want to use one
variable in each roop. How can I do this? See below
for (i in 1:100){
f(vi)
}
for (i in 1:100){
f(get(paste0(v, i)))
}
Cheers,
H.
Thanks
David
Thanks Hervé Pagès and A. K.. It works.
Thank you!
David
2013/12/14 Hervé Pagès hpa...@fhcrc.org
Hi David,
On 12/14/2013 01:06 PM, Marino David wrote:
Hi all:
Assume that I have variables, say v1, v2,...,v100 and I want to use one
variable in each roop. How can I do this? See below
how to use the readBin ?
i want to write the extended ascii character `Å` into a file named c:/testbin,
and read it in the R console ,display it as `Å` in R console.
now i can write it .
zz - file(c:/testbin, wb)
writeBin(charToRaw(\u0152), zz)
close(zz)
when i open the file with
dataorder.csv http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv I
have a set of data as attached.Like (181,246,378).(180,228,378)And I
want to use test for trend in proportions using (400,500,600) as denominator
and get 119 p-valuesSo I use the code as
On Dec 9, 2013, at 9:46 AM, celebrex wrote:
dataorder.csv http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv
I have a set of data as attached.Like (181,246,378).(180,228,378). And I
want to use test for trend in proportions using (400,500,600) as denominator
and get 119
Hi,
I guess the trouble is here:
lapply(1:4,function(i) {paste((file_,i,.txt),sep=)})
Error: unexpected ',' in lapply(1:4,function(i) {paste((file_,
lapply(1:4,function(i) {paste(file_,i,.txt,sep=)}) #works
#or
lapply(1:4,function(i) {paste0(file_,i,.txt,sep=)})
A.K.
Hi guys im having
I forgot to delete the `sep` from the 2nd option:
lapply(1:4,function(i) {paste0(file_,i,.txt)})
A.K.
On Thursday, November 21, 2013 1:43 AM, arun smartpink...@yahoo.com wrote:
Hi,
I guess the trouble is here:
lapply(1:4,function(i) {paste((file_,i,.txt),sep=)})
Error: unexpected ',' in
for example I have data frame m as below:
m=as.data.frame(outer(1:5,6:9))
colnames(m)=c('a','b','c','d')
and I define the function
myf=function(df, colname){
suppose colname is a, then:
how can I get the column 'a'
and how to get the colname as a string, 'a'
}
Thank you!
m=as.data.frame(outer(1:5,6:9))
colnames(m)=c('a','b','c','d')
tf=function(df, col){list(mean(eval(substitute(col),df,parent.frame())),col
)}
tf(m,a) will issue error: Error in tf(m, a) : object 'a' not found
How can I replace the col as char 'a' in the function?
Thank you
Please don't post in HTML format... it messes with code examples.
Use character indexing (please read the Introduction to R... again if
necessary).
myf - function(df, colname){
df[ ,colname ]
}
colname - a
myf(m,colname)
Until you learn simple R syntax, I strongly recommend avoiding
Characters in R are zero terminated (although I couldn't find that in
the R extensions manual). So, you could use:
void dealWithCharacter(char **chaine, int *size){
Rprintf(The string is '%s'\n, chaine[0]);
}
Jan
On 05/10/2013 03:51 PM, cgenolin wrote:
Hi the list,
I include some C
Hi the list,
I include some C code in a R function using .C. The argument is a character.
I find how to acces to the characters one by one:
--- 8 --- C
void dealWithCharacter(char **chaine, int *size){
int i=0;
for(i=0;i*size;i++){
Rprintf(Le caractere %i est
You may want to use C++ instead using Rcpp which string handling would
be easier:
http://gallery.rcpp.org/articles/strings_with_rcpp/
On 10 May 2013 15:51, cgenolin cgeno...@u-paris10.fr wrote:
Hi the list,
I include some C code in a R function using .C. The argument is a character.
I find
Hi all,
I want to transform a dCgMatrix from package Matrix into a matrix.csr from
package SparseM, and I found out this link :
http://stat.ethz.ch/R-manual/R-devel/library/Matrix/html/SparseM-conv.html
But there's no informaion about usage/description/arguments, so how do I
use this
I have a big data set that includes character variables of many different
values. I'm trying to read the data as big.matrix and then use
biglm.big.matrix to build linear models. However, since big.matrix will
convert all character vectors to factors and the character labels will be
lost, I
I realize this is an old post, but thought it's good to answer for other
folks that hit it during a search.
RExcel is fantastic. However, it requires all the users to install RExcel.
So the VBA approach may still be a good alternative in some simple cases,
like the example question.
I think what
On Tue, 26-Mar-2013 at 05:05PM +0900, Pascal Oettli wrote:
| Hi,
|
| You are right. The following should solve that problem:
|
| plot(0, 0, pch = )
| text(0, .5, expression(Temperature~(degree*C)))
It's not *exactly* the same. It uses a different font family for the
brackets, evidently from
I'm interested in using a regular bracket with the degree symbol as an
axis label but it's somewhat simpler to show what I mean in a text
statement.
plot(0, 0, pch = )
If I'm easy to please, this would suffice:
text(0, .5, expression(Temperature * degree ~ C))
But I'm not that easily pleased.
Hi,
Is it what you are looking for?
plot(0, 0, pch = )
text(0, .5, expression(Temperature~(degree ~ C)))
text(0, .4, substitute(paste(Temperature, B * degree, C)), list(B =
()))
Hope this help,
Pascal
On 26/03/13 16:12, Patrick Connolly wrote:
I'm interested in using a regular bracket
On Tue, 26-Mar-2013 at 04:20PM +0900, Pascal Oettli wrote:
| Hi,
|
| Is it what you are looking for?
|
| plot(0, 0, pch = )
| text(0, .5, expression(Temperature~(degree ~ C)))
That produces an unwanted space between the degree symbol and the C.
The search continues.
Thanks
| text(0, .4,
Hi,
You are right. The following should solve that problem:
plot(0, 0, pch = )
text(0, .5, expression(Temperature~(degree*C)))
HTH,
Pascal
On 26/03/13 16:55, Patrick Connolly wrote:
On Tue, 26-Mar-2013 at 04:20PM +0900, Pascal Oettli wrote:
| Hi,
|
| Is it what you are looking for?
|
|
On Tue, 26-Mar-2013 at 05:05PM +0900, Pascal Oettli wrote:
| Hi,
|
| You are right. The following should solve that problem:
|
| plot(0, 0, pch = )
| text(0, .5, expression(Temperature~(degree*C)))
That does it, and is perfectly readable. Now why didn't I think of that?
I knew there had to
You're welcome.
On 26/03/13 17:12, Patrick Connolly wrote:
On Tue, 26-Mar-2013 at 05:05PM +0900, Pascal Oettli wrote:
| Hi,
|
| You are right. The following should solve that problem:
|
| plot(0, 0, pch = )
| text(0, .5, expression(Temperature~(degree*C)))
That does it, and is perfectly
Hello,
I have a serialized Multilayer Perceptron trained using weka.
I would like to use R to re-evaluate the model.
How can I do this? I could not find an example of RWeca that applies
to Multilayer Perceptron.
Thanks,
Rui
__
R-help@r-project.org
Dear Patrick,
This is indeed a nice post to address the three dot issues.
It is definitely much clearer to me now
Thanks!
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
Thanks Bert for your example.
I wouldn't say that I understand why everything happens the way it does,
but at least I now know what happens!
I think I now need to use it and try around!
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000
There is now a blog post that attempts to
answer the question in the subject line:
http://www.burns-stat.com/the-three-dots-construct-in-r/
Pat
On 17/01/2013 14:36, Ivan Calandra wrote:
Dear users,
I'm trying to learn how to use the
I have written a function (simplified here) that uses
Because R can be interactive, I find that a little exploring through
the use of strategically placed browser() calls (?browser if you are
unfamiliar with this handy debugging tool) is often the fastest way to
solve little R puzzles like this.
For example, try this (in an R GUI):
f2 -
Since this topic was mine originally, I supposed I can give my opinion,
for what it's worth!
First, it is true that there is some help in the manuals. The problem
with these manuals (or at least, my problem) is that there were much too
complicated when I started to learn R. Then I got used to
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help system. But
I suspect people who won't read the existing manuals won't read that
one, either.
Duncan, I assume you're being facetious. Every R user soon learns to use
help() and help.search() or their
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help system. But
I suspect people who won't read the existing manuals won't read that
one, either.
Duncan, I assume you're being facetious. Every R user soon learns to use
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help system. But
I suspect people who won't read the existing manuals won't read that
one, either.
Duncan, I assume you're being facetious. Every R user soon learns
On 13-01-20 2:56 PM, Steve Taylor wrote:
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help system. But
I suspect people who won't read the existing manuals won't read that
one, either.
Duncan, I assume you're being
Why are the help pages not right? The ... construct is a fundamental part of
the language syntax. Information about this fundamental construct should be
easily available!
John
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division
On 13-01-20 5:54 PM, John Sorkin wrote:
Why are the help pages not right? The ... construct is a fundamental
part of the language syntax. Information about this fundamental
construct should be easily available!
Yes, I agree it should be easily available. Why does that mean it has
to be on
On Sun, Jan 20, 2013 at 5:54 PM, John Sorkin
jsor...@grecc.umaryland.edu wrote:
Why are the help pages not right? The ... construct is a fundamental part of
the language syntax. Information about this fundamental construct should be
easily available!
This strikes me as a bit harsh. The
On Jan 20, 2013, at 11:46 AM, Duncan Murdoch wrote:
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help
system. But
I suspect people who won't read the existing manuals won't read that
one, either.
Duncan, I assume
On 13-01-20 6:23 PM, David Winsemius wrote:
On Jan 20, 2013, at 11:46 AM, Duncan Murdoch wrote:
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help
system. But
I suspect people who won't read the existing manuals won't
On Jan 20, 2013, at 3:52 PM, Duncan Murdoch wrote:
On 13-01-20 6:23 PM, David Winsemius wrote:
On Jan 20, 2013, at 11:46 AM, Duncan Murdoch wrote:
On 13-01-20 2:28 PM, Steve Taylor wrote:
From: Duncan Murdoch
Maybe we just need a manual on how to use the existing help
system. But
I
On 13-01-17 10:00 PM, John Sorkin wrote:
Rolf
Perhaps the philosophy of the help system needs to change . . .
And perhaps it doesn't. Who knows?
Maybe we just need a manual on how to use the existing help system. But
I suspect people who won't read the existing manuals won't read that
Dear users,
I'm trying to learn how to use the
I have written a function (simplified here) that uses doBy::summaryBy():
# 'dat' is a data.frame from which the aggregation is computed
# 'vec_cat' is a integer vector defining which columns of the data.frame
should be use on the right side
On Thu, Jan 17, 2013 at 2:36 PM, Ivan Calandra
ivan.calan...@u-bourgogne.fr wrote:
Dear users,
I'm trying to learn how to use the
I have written a function (simplified here) that uses doBy::summaryBy():
# 'dat' is a data.frame from which the aggregation is computed
# 'vec_cat' is a
On 17-01-2013, at 15:36, Ivan Calandra ivan.calan...@u-bourgogne.fr wrote:
Dear users,
I'm trying to learn how to use the
I have written a function (simplified here) that uses doBy::summaryBy():
# 'dat' is a data.frame from which the aggregation is computed
# 'vec_cat' is a integer
Ok, it is that simple... Actually I had tried it but messed up so that
it didn't work.
Do you know where I can find some documentation about it?
Regarding return(), I know that it's not necessary, but when the
function gets more complicated, I like to have it because it becomes
clearer to me.
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