Carlos Nasher via R-help r-help at r-project.org writes:
[snip]
I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
confluent hypergeometric function). Therefore I'm using the kummerU
function from the fAsianOptions package. It seems to me that kummerU is
giving wrong
Hello R helpers,
I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
confluent hypergeometric function). Therefore I'm using the kummerU
function from the fAsianOptions package. It seems to me that kummerU is
giving wrong results. Here's an example:
library(fAsianOptions)
To view the source of (most) functions, simply type funcname without
parentheses: here, you get
dmvt
function (x, delta, sigma, df = 1, log = TRUE, type = shifted)
{
if (df == 0)
return(dmvnorm(x, mean = delta, sigma = sigma, log = log))
if (is.vector(x)) {
x - matrix(x,
Thanks for your advice. I actually meant to ask about the pmvt for the
distribution function. Viewing the source code pmvt uses the function
mvt which uses the function probval which sources the fortran code:
Fortran(mvtdst, N = as.integer(n), NU = as.integer(df),
LOWER =
On 19-03-2012, at 16:54, statfan wrote:
Thanks for your advice. I actually meant to ask about the pmvt for the
distribution function. Viewing the source code pmvt uses the function
mvt which uses the function probval which sources the fortran code:
No it doesn't source. It call a
Is there any way to know how the dmvt function computes the hypergeometric
function needed in the calculation for the density of multivariate t
distribution?
--
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Sent from the R
Hi,
I hope somebody can help me on how to use the hypergeometric function. I did
read through the R documentation on hypergeometric but not really sure what it
means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
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