See the Details section of ?lm where its all discussed.
On Sun, Nov 29, 2009 at 11:46 AM, Carl Witthoft wrote:
> Hi,
> A recent thread provided a (working) construct for lm:
>
> lm(as.matrix(freeny[ix]) ~., freeny[-ix])
>
>
> Can someone explain what is meant by the formula in that expression,
>
Sorry. Since . is commonly used but a matrix LHS less so I assumed you were
asking about the matrix part.
Dot means everything not on the LHS of the formula.
On Sun, Nov 29, 2009 at 12:18 PM, Carl Witthoft wrote:
> As others helpfully pointed out, the meaning of "." in a formula is
> provided i
The help page for lm says:
"If ‘response’ is a matrix a linear model is fitted separately by
least-squares to each column of the matrix."
-Ista
On Sun, Nov 29, 2009 at 11:46 AM, Carl Witthoft wrote:
> Hi,
> A recent thread provided a (working) construct for lm:
>
> lm(as.matrix(freeny[ix])
As others helpfully pointed out, the meaning of "." in a formula is
provided in the Details section of ?formula. (But NOT in ?lm)
Ista Zahn wrote:
The help page for lm says:
"If ‘response’ is a matrix a linear model is fitted separately by
least-squares to each column of the matrix."
-I
On Nov 29, 2009, at 11:46 AM, Carl Witthoft wrote:
Hi,
A recent thread provided a (working) construct for lm:
lm(as.matrix(freeny[ix]) ~., freeny[-ix])
Can someone explain what is meant by the formula in that expression,
that is, what does "mymatrix~." do?
It doesn't say my matrix, it sa
Hi,
A recent thread provided a (working) construct for lm:
lm(as.matrix(freeny[ix]) ~., freeny[-ix])
Can someone explain what is meant by the formula in that expression,
that is, what does "mymatrix~." do? I couldn't find any such example
in the lm() or formula() help pages.
thanks
Carl
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