Thanks a lot!
Best,
Sara
-Ursprungligt meddelande-
Från: istaz...@gmail.com [mailto:istaz...@gmail.com] För Ista Zahn
Skickat: den 12 maj 2011 16:46
Till: Sara Sjöstedt de Luna
Kopia: r-help@r-project.org; Katie Andrle (katie.and...@gmail.com)
(katie.and...@gmail.com)
Ämne: Re: [R] lm
On May 12, 2011, at 15:30 , Paul Chatfield wrote:
> anova uses sequential sums of squares (type 1),
Yes.
> summary adjusted sums of
> squares (type 3)
No. Type III SS is a considerably stranger beast.
summary() looks at the s.e. of individual coefficients. For 1 DF effects, this
is often eq
anova uses sequential sums of squares (type 1), summary adjusted sums of
squares (type 3)
Take for example the first line of each output. In summary this tests
whether vole1 is needed ASSUMING volelag and year are already in the model
(conclusion would then be: it isn't needed p=.89). Whereas in
Hi Sara,
As the help page for anova.lm says,
"Specifying a single object gives a sequential analysis of variance table".
That most likely also the answer to your second question.
The anova function can be used to compare nested models, and this
provides the flexibility to test arbitrary hypothes
Hi!
We have run a linear regression model with 3 explanatory variables and get the
output below.
Does anyone know what type of test the anova model below does and why we get so
different result in terms of significant variables by the two tables?
Thanks!
/Sara
> summary(model)
Call:
lm(formul
Hi!
We have run a linear regression model with 3 explanatory variables and get the
output below.
Does anyone know what type of test the anova model below does and why we get so
different result in terms of significant variables by the two tables?
Thanks!
/Sara
> summary(model)
Call:
lm(formul
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