Re: [R] parsing files for plot

Great, works perfect!!! Thanks a lot Maxim 2010/1/30 baptiste auguie > Hi again, > > Below are two versions, depending on whether you want to use scan or > read.table, > > ## with scan > library(reshape) > listOfFiles <- list.files() > d <- llply(listOfFiles, scan) > names(d) <- basename(l

Re: [R] parsing files for plot

Hi again, Below are two versions, depending on whether you want to use scan or read.table, ## with scan library(reshape) listOfFiles <- list.files() d <- llply(listOfFiles, scan) names(d) <- basename(listOfFiles) melt(d) ## with read.table listOfFiles <- list.files() names(listOfFiles) <- base

Re: [R] parsing files for plot

Hi, my data is really not spectacular, each of the 6 files (later several hundred) contains correlation coefficients in plain text format like: 0.923960073 0.923960073 0.612571344 0.064183275 0.007733399 -0.315444372 -0.064591277 -0.268336142 ... with between 1000-13000 rows. Scanning f

Re: [R] parsing files for plot

Hi, Hadley recently proposed a strategy using plyr for a very similar problem, listOfFiles <- list.files() names(listOfFiles) <- basename(listOfFiles) library(plyr) d <- ldply(listOfFiles, scan) Even if you don't want to use plyr, it's always better to group things in a list rather than clutter

[R] parsing files for plot

Hi, I have many files containing one column of data. I like to use the scan function to parse the data. Next I like to bind to a large vector. I try this like: count<-1 files <- list.files() # all files in the working directory for(i in files) { tmp <- scan(i) assign(files[count],