Re: [R] randomForest outlier return NA

.org [mailto:r-help-boun...@r-project.org] > On Behalf Of Pau Carrio Gaspar > Sent: Wednesday, July 14, 2010 6:36 AM > To: r-help@r-project.org > Subject: [R] randomForest outlier return NA > > Dear R-users, > > I have a problem with randomForest{outlier}. > Afte

Re: [R] randomForest outlier return NA

anks for reporting. Best, Andy -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Pau Carrio Gaspar Sent: Wednesday, July 14, 2010 6:36 AM To: r-help@r-project.org Subject: [R] randomForest outlier return NA Dear R-users, I have a problem

[R] randomForest outlier return NA

Dear R-users, I have a problem with randomForest{outlier}. After running the following code ( that produces a silly data set and builds a model with randomForest ): ### library(randomForest) set.seed(0) ## build data set X <- rbind( matrix( runif(n=400,min=-1,max=1), ncol =

Re: [R] randomForest outlier

e a bit unusual as a similarity measure. -Original Message- From: Birgit Lemcke [mailto:[EMAIL PROTECTED] Sent: Wednesday, July 16, 2008 8:55 AM To: Liaw, Andy Cc: R Hilfe Subject: Re: [R] randomForest outlier Thanks anyway for your answer. That was also an option that I took into account (no pot

Re: [R] randomForest outlier

Thanks anyway for your answer. That was also an option that I took into account (no potential outliers) and I will have a look at the "value" section of ?outliers. B. Am 16.07.2008 um 14:11 schrieb Liaw, Andy: Perhaps if you follow the posting guide more closely, you might get more (useful

Re: [R] randomForest outlier

Perhaps if you follow the posting guide more closely, you might get more (useful) replies, but without looking at your data, I doubt there's much anyone can do for you. The fact that the range of the outlying measures is -1 to 2 would tell me there are no potential outliers by this measure. Pleas

Re: [R] randomForest outlier

Still the same question: Birgitle wrote: > > I try to use ?randomForest to find variables that are the most important > to divide my dataset (continuous, categorical variables) in two given > groups. > > But when I plot the outlier: > > plot(outlier(rfObject, cls=groupingVariable), > type="p"

[R] randomForest outlier

I try to use ?randomForest to find variables that are the most important to divide my dataset (continuous, categorical variables) in two given groups. But when I plot the outliers: plot(outlier(FemMalSex_NAavoid88.rf33, cls=FemMalSex_NAavoid88$Sex), type="h",col=c("red","green")[as.numeric(FemMa