Hi Sarah,
this is a neat solution. Thanks very much for your help, and your
patience with my poorly posed questions. I've learned a lot from your
approach.
best regards,
Aidan
On Wed, Dec 7, 2011 at 1:40 PM, Sarah Goslee wrote:
> Hi,
>
> If you really wanted precision (significant figures) rath
Hi,
If you really wanted precision (significant figures) rather than decimal places,
it would be easy: format() handles that, I believe.
Your original email said you'd been reading about regular expressions;
continuing
that reading will lead you to the meaning of the cryptic ^ and all the \.
As
Hi Sarah,
apologies for the excess. A smaller example:
f<-structure(list(c("GDP per capita (LCU)", "Ratio to EZ GDP Per Cap"
), `2005` = c(32128, 0.1), `2009` = c(52163, 0.1), `2010` = c(63100,
0.1), `2011` = c(72461, 0.1), `2012` = c(81313, 0.1)), .Names = c("",
"2005", "2009", "2010", "2011", "
Hi,
Example data is crucial, but small simple example data is even better.
I'm too lazy to figure out which bits I need from your data, so here's
a simple example of one way to approach your question. You could
use gsub() in very much the same manner if you need more complex
output.
> testdata <-
Dear all,
I'm trying to remove some text after the period (a decimal point) in
the data frame 'hi', below. This is one step in formatting a table. So
I would like e.g.
"2.0" to become "2"
and "5.3" to be "5.3",
where the variable digordered contains the number of digits after the
decimal that I
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