[R] sampling rows from a list

Hi: I'm sure this seems like a rudimentary question, but I am not well versed with R syntax for lists. I have a ragged array from which I've removed records (entire rows) with missing data. The functions I used to remove the missing cases resulted in the generation of an R list class object,

Re: [R] sampling rows from a list

?? Something like: lapply(mydata, function(x){ nr - nrow(x) x[sample(seq_len(nr),nr,rep=TRUE),] }) maybe. The idea is to use the sampled rows as your row index. -- Bert On Mon, Apr 2, 2012 at 11:24 AM, Bcampbell99 briand.campb...@ec.gc.ca wrote: Hi: I'm sure this seems like a rudimentary

Re: [R] sampling rows from a list

## recreating your data mydata-list(matrix(1:9, nrow=3, byrow=T), matrix(10:15, nrow=2, byrow=T), matrix(16:30, nrow=5, byrow=T)) ## get the shortest matrix in your list n - min(unlist(lapply(mydata, nrow))) ## subset the list into random samples of length n