If df is the data.frame with values and you want nn samples, then this
is a slightly different approach:
# example data.frame:
df = data.frame(a1 = sample(1:20,50, replace = TRUE),
a2 = sample(seq(0.1,10,length.out =
30),50, replace = TRUE),
Hi Jean,
Thanks!
Daniel,
Yes, you are absolutely right. I want sampled vectors to be as different
as possible.
I added a little more to the earlier data set.
x1 x2 x3
[1,] 1 3.7 2.1
[2,] 2 3.7 5.3
[3,] 3 3.7 6.2
[4,] 4 3.7 8.9
[5,] 5 3.7 4.1
[6,] 1 2.9 2.1
[7,] 2 2
On 6/22/2015 9:42 AM, C W wrote:
Hello R list,
I am have question about sampling unique coordinate values.
Here's how my data looks like
dat <- cbind(x1 = rep(1:5, 3), x2 = rep(c(3.7, 2.9, 5.2), each=5))
dat
x1 x2
[1,] 1 3.7
[2,] 2 3.7
[3,] 3 3.7
[4,] 4 3.7
[5,] 5 3.7
Mike,
There may be a more efficient way to do this, but this works on your
example.
# mix up the order of the rows
mix <- dat[order(runif(dim(dat)[1])), ]
# get rid of duplicate x1s and x2s
sub <- mix[!duplicated(mix[, "x1"]) & !duplicated(mix[, "x2"]), ]
sub
Jean
On Mon, Jun 22, 2015 at 11:42
Hello R list,
I am have question about sampling unique coordinate values.
Here's how my data looks like
> dat <- cbind(x1 = rep(1:5, 3), x2 = rep(c(3.7, 2.9, 5.2), each=5))
> dat
x1 x2
[1,] 1 3.7
[2,] 2 3.7
[3,] 3 3.7
[4,] 4 3.7
[5,] 5 3.7
[6,] 1 2.9
[7,] 2 2.9
[8,] 3 2.9
5 matches
Mail list logo
