Re: [R] sapply puzzlement

2011-01-27 Thread Dario Strbenac
:45 +0100 >From: r-help-boun...@r-project.org (on behalf of nfdi...@gmail.com (Ernest >Adrogué i Calveras)) >Subject: [R] sapply puzzlement >To: r-help@r-project.org > >Hi, > >I have this data.frame with two variables in it, > >> z > V1 V2 >1 10 8 >2 NA

Re: [R] sapply puzzlement

2011-01-27 Thread Pete Brecknock
In addition to what has already been suggested you could use .. mapply(function(x,y) x-y, z,means) which returns V1 V2 [1,] 0.333 -2.7142857 [2,] NA 7.2857143 [3,] -0.667 -3.7142857 [4,] -6.667 NA [5,] NA -0.7142857 [6,] 1.333

Re: [R] sapply puzzlement

2011-01-27 Thread David Winsemius
On Jan 27, 2011, at 7:16 PM, Ernest Adrogué i Calveras wrote: Hi, I have this data.frame with two variables in it, z V1 V2 1 10 8 2 NA 18 3 9 7 4 3 NA 5 NA 10 6 11 12 7 13 9 8 12 11 and a vector of means, means <- apply(z, 2, function (col) mean(na.omit(col))) means V1

Re: [R] sapply puzzlement

2011-01-27 Thread David A. Johnston
sapply(z, function(row) ...) does not actually grab a row at a time out of 'z'. It grabs a column (because 'z' is a data.frame) You may want: t(apply(z, 1, function(row) row - means)) or: t(t(z) - means) Hope that helps, -David Johnston -- View this message in context: http://r.789695.n4.n

[R] sapply puzzlement

2011-01-27 Thread Ernest Adrogué i Calveras
Hi, I have this data.frame with two variables in it, > z V1 V2 1 10 8 2 NA 18 3 9 7 4 3 NA 5 NA 10 6 11 12 7 13 9 8 12 11 and a vector of means, > means <- apply(z, 2, function (col) mean(na.omit(col))) > means V1V2 9.67 10.714286 My intention was substracting mean