Hi
Well, R does exactly what it says. From help page.
Otherwise, x and y must be vectors or factors of the same length
I do not know SAS but I presume that
tables bloodtype*state
gives you something like
tab - table(bloodtype, state)
and
chisq.test(tab)
shall give you the expected
On Thu, 2007-11-22 at 16:16 +0500, Shoaaib Mehmood wrote:
hi,
is there a way of calculating of measuring dependence between two
categorical variables. i tried using the chi square test to test for
independence but i got error saying that the lengths of the two
vectors don't match. Suppose
prettyR
--- Shoaaib Mehmood [EMAIL PROTECTED] wrote:
i cant find help for xtab. Which package contains
this function
On Nov 24, 2007 12:16 PM, G Ilhamto
[EMAIL PROTECTED] wrote:
hi shohaib,
have you tried xtab instead of chisq.test?
Ilham
On Nov 22, 2007 6:16 AM, Shoaaib
i cant find help for xtab. Which package contains this function
On Nov 24, 2007 12:16 PM, G Ilhamto [EMAIL PROTECTED] wrote:
hi shohaib,
have you tried xtab instead of chisq.test?
Ilham
On Nov 22, 2007 6:16 AM, Shoaaib Mehmood [EMAIL PROTECTED] wrote:
hi,
is there a way of
hi,
is there a way of calculating of measuring dependence between two
categorical variables. i tried using the chi square test to test for
independence but i got error saying that the lengths of the two
vectors don't match. Suppose X and Y are two factors. X has 5 levels
and Y has 7 levels. This
Hi,
When testing whether random variables X and Y are
independent the usual assumption is that you have n
pairs of outcomes - (X1,Y1), (X2,Y2), ... , (Xn,Yn)
and you are basically checking whether the value of X
affects the value of Y.
If you have 7 observations of X and 5 separate
observations
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