Is there a more efficient/elegant way to obtain the result z below.
a - c('pink','pink','blue','blue','gold','gold')
b - c(5,8,9,12,7,4)
agg - aggregate(x=b,by=list(a), FUN='mean')
m - match(a, agg[,1])
z - agg[m,2]
z
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On Fri, Aug 13, 2010 at 12:26 PM, Eva Nordstrom eva.nordst...@yahoo.com wrote:
Is there a more efficient/elegant way to obtain the result z below.
a - c('pink','pink','blue','blue','gold','gold')
b - c(5,8,9,12,7,4)
agg - aggregate(x=b,by=list(a), FUN='mean')
m - match(a, agg[,1])
z -
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