[R] variation of the aggregate function

2010-08-13 Thread Eva Nordstrom
Is there a more efficient/elegant way to obtain the result z below. a - c('pink','pink','blue','blue','gold','gold') b - c(5,8,9,12,7,4) agg - aggregate(x=b,by=list(a), FUN='mean') m - match(a, agg[,1]) z - agg[m,2] z [[alternative HTML version deleted]]

Re: [R] variation of the aggregate function

2010-08-13 Thread Gabor Grothendieck
On Fri, Aug 13, 2010 at 12:26 PM, Eva Nordstrom eva.nordst...@yahoo.com wrote: Is there a more efficient/elegant way to obtain the result z below. a - c('pink','pink','blue','blue','gold','gold') b - c(5,8,9,12,7,4) agg - aggregate(x=b,by=list(a), FUN='mean') m - match(a, agg[,1]) z -