If DF is a data frame with the variables, try this:
lm(l ~. , DF[c("l", "b", "j", "x"))
On Thu, Feb 12, 2009 at 11:11 AM, wrote:
> dear r-experts: there is probably a very easy way to do it, but it eludes
> me right now. I have a large data frame with, say, 26 columns named "a"
> through "z".
The predictors and outcomes in lm can be matrices, so you could use something
like the following:
x.mat=cbind(x1=rnorm(20),x2=rnorm(20))
y.mat=cbind(y1=rnorm(20),y2=rnorm(20))
lm(y.mat~x.mat)
David Freedman
ivowel wrote:
>
> dear r-experts: there is probably a very easy way to do it, but it e
Missed a bracket:
lm(l ~. , DF[c("l", "b", "j", "x")])
On Thu, Feb 12, 2009 at 11:21 AM, Gabor Grothendieck
wrote:
> If DF is a data frame with the variables, try this:
>
> lm(l ~. , DF[c("l", "b", "j", "x"))
>
>
> On Thu, Feb 12, 2009 at 11:11 AM, wrote:
>> dear r-experts: there is probably a
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