After reading the documentation, I believe the problem may be specific to
me. Either way, I'll have to investigate further, and I'll provide more
details next time, if I'm unable to get things to work. In the meantime,
suggestions & tips are always welcome.
Thanks again.
Samir.
-Original Mes
I'm working in WinXP. Is it the case that RSPython does not work on Win32
platforms? I believe I read this somewhere... I'd appreciate confirmation.
Either way, I wasn't able to get RSPython to work for me, this was some time
ago, and at that time I was very new to Python.
Thanks.
-Original
I am new to R. I run it under MS Windows.
My goal is to interface an existing R program (500 lines) with a commercial software.
That one
can be used as an OLE-Server. Ideally I would be able to reference and control the
R-program
and components of the other software out of one VBA program. To ma
This should be fixed in R-patched and R-devel (and has been since
Saturday). Certainly it has gone away for me.
On Mon, 23 Dec 2002, Hedderik van Rijn wrote:
> >>> cat(paste(rep("123456789!",1000),collapse=""))
> >> Program received signal SIGSEGV, Segmentation fault.
> >> 0x4207a4cb in strlen (
cat(paste(rep("123456789!",1000),collapse=""))
Program received signal SIGSEGV, Segmentation fault.
0x4207a4cb in strlen () from /lib/i686/libc.so.6
(The cat(...) call being obtained with up-arrow command recall)
To be precise, it happens *next* time I press "up"
This is the same behavior I e
Agustin Lobo wrote:
>
> A question for a (experienced) user of the RPython package on
> linux.
>
> I'm trying to call R from python on a linux (Suse 7.3) box.
Since you are calling R from Python, you could try Walter Moreira's
excellent RPy module. I found it much easier to install than RSPython
> Could you please tell me how to call R from Perl and call Perl
> functions from R?
Please see http://www.omegahat.org/RSPerl
Dirk
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Hi,
Could you please tell me how to call R from Perl and call Perl
functions from R?
Thanks,
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Hi all,
I make a censored model using survreg from survival package. But the deviance
values are too high, it is possible that must be a error in my model?
> summary(completo)
conc peso dv w temp
Min. :0.7 Min. : 5.00 Min. : 1
I remember reading somewhere that locations on plots (in my case, arguments
x and y for legend()) can be specified in several scales besides the usual
data scale. I would like to set x and y as proportions of total plot size
or something similar. Can anyone steer me to documentation on how to
I'd like to thank the R Core Team for making the
parameters clearer for me on how to solve this
problem.
I think for now I will try to do most data management
tasks in SAS (from Oracle) and then use PROC EXPORT in
SAS to create a csv file that R can read and then I
can do my graphics, for publicat
"Anon." wrote:
>
> Moi!
>
> I'm trying to add a rather long label to a y-axis, and it's so long that
> it won't fit into one line. However, things get strange when I try and
> split it over 2 lines. The problem seems to be the plus/minus symbol,
> which means I have to use expression(). I'm us
Moi!
I'm trying to add a rather long label to a y-axis, and it's so long that
it won't fit into one line. However, things get strange when I try and
split it over 2 lines. The problem seems to be the plus/minus symbol,
which means I have to use expression(). I'm using R1.6.1 on Windoze
2000.
A
Using R 1.6.1 on Windows 2000. As always, a big THANK YOU to the R team.
(1) Can the legend position be specified in barplot()?Right now, we are
doing this with a separate call to legend().
(2) For a stacked bar, we wish to show both positive and negative values,
rather than taking an alge
Here is a version of pooled-adjacent-violators in R, which
does weighted mean, weighted median, and weighted p-fractile.
===
pava<-function(x,w=rep(1,length(x)),block=weighted.mean){
nblock<-n<-length(x); blocklist<-array(1:n,c(n,2)); bl
On Sun, 22 Dec 2002, John Miyamoto wrote:
>
> I discovered from this interchange that I did not quite state my problem
> correctly, but the discussion solved the real problem as well as the
> stated problem. What started me on these questions was the desire to
> write a function that would conver
Is it really necessary to use "\"?
On my Windows 2000 system here at work, it appears that the "dos" shell
interprets "/" as "\", even though "\" is the "official" Windows folder
delimiter. For instance, I can type "C:/Program
Files/R/rw1061/bin/Rgui.exe" (quotes included) and R opens. Using "/
On Sat, 21 Dec 2002, Shuangge Ma wrote:
> Dear Sir/Madam:
> this is shuangge Ma, graduate student in UW-Madison statistics department.
> I have a computational question.
> I have a function f(x,y). I want to find the y(x) that maximize f(x,y)
> under the constraint y(x) is a non-decreasing step fu
My immediate guess is that you do not have R compiled as a shared
library, i.e. libR.so. Without this, you cannot use R within Python,
but only Python within R. libR.so is where R_GlobalEnv will come
from.
So check for libR.so in the directory `R RHOME`/bin.
If it is not there, you will have to
Hi,
Does anyone know if it is possible to extract the whole data set from an
nls object?
I tried
'nls.object'$data
but it only provides the name of the data frame with no direct access to
content of this data frame.
Do you have an idea??
Thanks in advance.
Florent BATY
--
__
A question for a (experienced) user of the RPython package on
linux.
I'm trying to call R from python on a linux (Suse 7.3) box.
After installing R CMD INSTALL -c RSPython_0.5-2.tar.gz
I start python and do:
>>> import sys
>>> sys.path.append('/usr/local/lib/R/library/RSPython')
>>> sys.path.a
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