Hi,
i found tis message in the archive and have
got the same problems ?
John, perhaps you have found now a way
install RPgSQL for windows2000, or anybody other ?
many thanks for advance
christian
[SNIP]
I wonder whether anyone has succeeded in building either the RPgSQL or the
Rdbi.PGSQL
Hey, All
Now I generate a data vector X (d-dimension column vector) from a Gaussian
Mixture Model (GMM).
That is, the pdf of vector X is
f(X) = a1*N(u1, Cov1) + a2*(u2, Cov2)
where a1+a2 = 1, N is multidimensional normal distribution, ui is the mean
vecotr, Covi is the covariance matrix, i=1, 2.
Dr Mccarter and Dr Gentleman,
Thank you for your reply. I reinstalled the system and found out that you
can not install R on FreeBSD 5.0 (I mean in the default setting when
installing R and also I tried to open the --enable-R-shlib. I chose
installing full binary, kernel src, & X during the instal
In co-operation with Markus Hegland and myself, Zhongwen Ding
has written a package, based partly on Markus Hegland's code,
that provides a parallel processing interface to a remote
multi-processsor system. Pyro (Python Remote Objects) and R
must both be installed, both on the client machine and o
Is `D' the original matrix or a `geodata' object? You need to assign the
output of `as.geodata to another variable and pass that to `variog'. For
example,
B <- as.geodata(D, coords.col=1:2, data.col=3)
variog(B, option = "cloud", max.dist = 1)
It seems like the problem is that you're passing th
Hi,
I'm a new R user. My goal is to do a variogram using geoR.
I started by trying to do the example in the geoR Illustrative Session
using my own data.
I am able to read in my Ascii data using: D <- matrix(scan("file.dat",
n=530*3), 530,3, byrow=TRUE).
Then I use: as.geodata(D, coords.col=1:2
On Mon, 10 Feb 2003, Christian Schulz wrote:
> hi,
> for working with the simseg/acm approach i need multilm and it seems
> that the last version is 0.1-4.tar ?
> What's wrong in the description file, if i attempt install the package ?
>
> c:\DataMining\rw1062\bin>Rcmd Install multilm
> Malforme
hi,
for working with the simseg/acm approach i need multilm and it seems
that the last version is 0.1-4.tar ?
What's wrong in the description file, if i attempt install the package ?
c:\DataMining\rw1062\bin>Rcmd Install multilm
Malformed DCF file (file multilm/DESCRIPTION, line 6)
[R1.6.2 /W2
On Mon, 10 Feb 2003 21:51:50 +0100
Fan <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I've read in the past a thead in the R discussion list
> about the multi-valued type variable (what was called checklist).
> At the moment Gregory had intention to add some general code
> in his gregmisc package.
>
> I'm
Dear All,
Reverting to RODBC 0.9.1 that I had archived resolved the problem.
Thanks to Professor Ripley for noting
that I had a non-release version of RODBC (how I might have obtained it
is still beyond me ;)).
Pijus
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Hi,
I've read in the past a thead in the R discussion list
about the multi-valued type variable (what was called checklist).
At the moment Gregory had intention to add some general code
in his gregmisc package.
I'm wondering if there's some general code / packages available ?
A general class for
Professor Ripley,
> There is no statement 3 in the released version of sqlGetResults ...
In other words, I have an outdated/wrong version of RODBC?
> You can. R are RODBC and Open Source, so why not open it and read it?
Because I don't know C/C++. I realise I should learn it, but I hope that
t
On Mon, 10 Feb 2003, Pijus Virketis wrote:
> I've encountered a curious problem. I am trying to run an SQL query
> using sqlQuery() function in RODBC.
> The query works fine when run in a stand-alone SQL browser (Microsoft
> Query Analyzer, in particular).
> However, when I use the exact same th
Dear all,
I've encountered a curious problem. I am trying to run an SQL query
using sqlQuery() function in RODBC.
The query works fine when run in a stand-alone SQL browser (Microsoft
Query Analyzer, in particular).
However, when I use the exact same thing from sqlQuery() function, I get
the fo
Hello to everybody:
Im starting to use R and this is my first message to the list. My first
question is: Can R-Program calculate hierarchical partitioning analysis
to
measure the "independent effect" of each independent variable in a
multiple
regression (lm, glm)
Thanks in
advance
--
David Nogué
Many thanks to Kjetil Halvorsen for explaining me the reason I got
different results.
Regarding the second point, Both Kjetil and Brian Ripley suggest to go
through debugging and see what the reason for the message.
I'm not so expert to fully understand why, but I have found a patch that
makes the
Laurent Gautier <[EMAIL PROTECTED]> writes:
> ...sorry for the spam, but answers I get to my previous
> question suggest that I should specify that the
> machine has a *lot* of memory and should be able
> to the instanciation...
>
> Anybody with an IBM mainframe, R-1.6.2 and large
> matrices ?
F
On Mon, Feb 10, 2003 at 05:25:33PM +0100, Ott Toomet wrote:
> ind <- c(1, 3) # indices you need
> varcov <- matrix(0, 4, 4)
> varcovar[ind,ind] <- solve(hessian[ind,ind])
>
> I.e. invert only parameter-depending part of the hessian and put it
> into the corresponding elements in the full varcovar
R per se does not have lda() function. Package MASS does, and MASS (the
book) describes it in detail.
If you use a package supporting a book (there are several) do expect to
read the book for the fine details
On Mon, 10 Feb 2003, Luis Silva wrote:
> There are some versions of lda. I would
Hi,
| From: Timur Elzhov <[EMAIL PROTECTED]>
| Date: Mon, 10 Feb 2003 19:06:18 +0300
|
| Dear R experts!
|
| I try to minimize a function with external C fitting function.
| I get the hessian matrix. Here it is:
|
| [,1] [,2] [,3] [,4]
| [1,] 1.88166310 0.885980
my name is Tomer Maimon,
and i'm a student in the israeli Institue for
science ( "Technion") .i have some problem with the R program. i want
to write formula with two factors to predict(in rpart algorithm). i'll
be more then thankfull if you could send me an answer & internet link,
where can i find
On 10 Feb 2003 at 15:40, Luca Scrucca wrote:
I am not sure about this, but lqs have an extra argument `adjust'.
from the help page:
adjust:
should the intercept be optimized for each sample? Defaults to TRUE
When you use formula, the estimation algorithm knows
the columns of 1's is the intercep
Martin Biuw <[EMAIL PROTECTED]> writes:
> Hello,
> I'm trying to fit a linear mixed effects model of the form:
>
> lme(y ~ x * Sex * Year, random=x|subject)
Did you mean
lme(y ~ x * Sex * Year, random= ~ x|subject)
The random argument should be a formula or a list.
> where Sex and Year are f
Dear helpers
There are some versions of lda. I would like to know which one
is behind R's lda function.
Luis
--
Ofereça a si uma prenda no Dia dos Namorados: SAPO.ADSL.PT, e receba ainda uma oferta
especial para a sua cara-metade. Tudo só por 50
http://adsl.sapo.pt/destaque_namorados.html
__
Dear R experts!
I try to minimize a function with external C fitting function.
I get the hessian matrix. Here it is:
[,1] [,2] [,3] [,4]
[1,] 1.88166310 0.88598030
[2,] 0.0000 0.0000
[3,] 0.88598030 0.48599830
[4,] 0.0000 0.000
On Mon, 10 Feb 2003, Luca Scrucca wrote:
> I found a strange behaviour in the lqs function.
Why is this strange? It *is* covered in the Note on the help page: please
read it and the reference there.
> Suppose I have the following data:
[...]
> Now, instead of using the formula, I want to prov
Ernesto Jardim wrote:
Hi
It's a bootstrap empirical distribution and has 1000 replicates.
EJ
On Mon, 2003-02-10 at 15:33, Richard A. Bilonick wrote:
It depends on how non-Normal the distribution and the size of the
sample. A t-distribution with df = 30 isn't Normal but it is close to
bein
Ernesto Jardim wrote:
Ok, let me put it the other way around.
On another test I have W = 0.9907, p-value = 6.024e-06. The same
question stands, with such huge W should it be expected to be normal ?
EJ
You have it backwards. The null hypothesis is that the distribution is
Normal. You reject
Ok, let me put it the other way around.
On another test I have W = 0.9907, p-value = 6.024e-06. The same
question stands, with such huge W should it be expected to be normal ?
EJ
On Mon, 2003-02-10 at 14:47, Richard A. Bilonick wrote:
> Ernesto Jardim wrote:
>
> >Hi
> >
> >The shapiro.test func
...sorry for the spam, but answers I get to my previous
question suggest that I should specify that the
machine has a *lot* of memory and should be able
to the instanciation...
Anybody with an IBM mainframe, R-1.6.2 and large
matrices ?
L.
__
[EMAIL PR
Before I'm reinventing the wheel: did anyone already work on an E-Prime
(experiment presentation and data collection tool used in Psychology,
http://www.pstnet.com/e-prime/default.htm) data import function?
- Hedderik.
(Googling with "e-prime site:r-project.org" didn't result in any hits.)
Dear List-members,
I found a strange behaviour in the lqs function.
Suppose I have the following data:
y <- c(7.6, 7.7, 4.3, 5.9, 5.0, 6.5, 8.3, 8.2, 13.2, 12.6, 10.4, 10.8,
13.1, 12.3, 10.4, 10.5, 7.7, 9.5, 12.0, 12.6, 13.6, 14.1, 13.5, 11.5,
12.0, 13.0, 14.1, 15.1)
x1 <- c(8.2, 7.6,, 4.6, 4.3,
Ernesto Jardim wrote:
Hi
The shapiro.test function outputs a value of the W statistic, which
should be 1 if the distribution is normal, and a p-value for the test
(as the documentation states).
I'm a bit confused with some results. I'm getting a W=0.9977 and a
p-value=0.1889.
I was expecting t
Hi
The shapiro.test function outputs a value of the W statistic, which
should be 1 if the distribution is normal, and a p-value for the test
(as the documentation states).
I'm a bit confused with some results. I'm getting a W=0.9977 and a
p-value=0.1889.
I was expecting that a W of 0.9977 would
Dear R users,
the preliminary program for the 3rd international workshop on
'Distributed Statistical Computing' (DSC 2003) is now available at
http://www.ci.tuwien.ac.at/Conferences/DSC-2003/
The workshop will take place at the Technische Universität Wien in
Vienna, Austria from March 20-22.
Dear Gregory,
As Brian Ripley pointed out (and as the help page for nls mentions), you
shouldn't test nls on zero-residual data. But, in any event, you can fit
this model with linear least squares, as lm(y ~ I(1/x) - 1).
I hope that this helps,
John
At 10:11 AM 2/10/2003 +0100, Gregory BENMEN
Hello,
I'm trying to fit a linear mixed effects model of the form:
lme(y ~ x * Sex * Year, random=x|subject)
where Sex and Year are factors with two and three levels respectively. I
want to compare the fixed effects for each level to the overall mean, but
the default in R is to compare to the f
Dear,
Do hashmaps or hashtables exist in R?
If so how can I implement them?
Kind Regards,
Steffen
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http://www.stat.math.ethz.ch/mailman/listinfo/r-help
Dear all,
I compiled R-1.6.2 for IBM-AIX (using the native compilers)
and I am facing problems to instanciate (rather) large
matrices.
I have:
> m <- matrix(0, 640*640, 102)
Error: cannot allocate vector of size 326400 Kb
I am not truly familiar with AIX, but this does not
seem t
Don't use nls for exact fits, as that's not what it is intended for, and
you are trying to achieve a fit to machine accuracy with rounding errors.
You will find several discussions of this in the archives.
On Mon, 10 Feb 2003, Gregory BENMENZER wrote:
> I want to estimate parameters of the model
Hello,
I want to estimate parameters of the model y=a/x with x=1:10 and y=3/x.
I tested the NLS function.
Could you tell me why it doesn't converge ?
Regards,
Grégory Benmenzer
> x=1:10
> y=3/x
> nls(y~a/x, start=list(a=2), control=nls.control(maxiter=100))
Error in nls(y ~ a/x, start = list(a
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