Steven Lacey [EMAIL PROTECTED] writes:
Dear R-help list,
I am trying to do a mixed ANOVA on a 8960 x 5 dataframe. I have 3 factors
for which I want to test all main effects and interactions : f1 (40 levels),
f2 (7 levels), and f3 (4 levels). I also have a subject factor, subject, and
a
En español (In Spanish)
Necesito calcular la en numeros de combinaciones de n cosas
tomando k al tiempo.
Como hago eso en R ???
Yo escribí mi propia función pero pienso que de esa forma no es
fácil para mis estudiantes .
He estado buscando en la ayuda y no he encontrado información
sobre una
Peter Dalgaard [EMAIL PROTECTED] writes:
- use a version of R compiled with a fast BLAS, on a fast computer
with a lot of RAM... (A ~2K square matrix inversion will take a
while, but hours sounds a bit excessive).
To wit:
system.time(aov(dv~f1*f2*f3+Error(subject/(f1+f3)),data=d))
[1]
Mario Morales wrote:
En español (In Spanish)
Necesito calcular la en numeros de combinaciones de n cosas
tomando k al tiempo.
Como hago eso en R ???
Yo escribí mi propia función pero pienso que de esa forma no es
fácil para mis estudiantes .
He estado buscando en la ayuda y no he encontrado
do you mean n choose k which is a built in function see
?choose
On Sat, 19 Mar 2005, Mario Morales wrote:
En español (In Spanish)
Necesito calcular la en numeros de combinaciones de n cosas
tomando k al tiempo.
Como hago eso en R ???
Yo escribí mi propia función pero pienso que de
XP Sun wrote:
hi, all,
how to decide the number of cluster before you use kmeans and hclust?
thank you in advance!
Depends on your criterion. Best idea is always to use the brain and
think about how many clusters are sensible for the particular
task/problem/data.
For hclust,
C function name not in load table means that youe DLL/SO file is not loaded.
You should use
.First.lib - function(lib, pkg)
{
library.dynam(your_pkg_name, pkg, lib)
}
Regads,
Samuel.
Duncan Murdoch [EMAIL PROTECTED] wrote:
On Wed, 9 Mar 2005 18:54:36 -0500, [EMAIL PROTECTED] wrote :
Try
choose(k,r)
choose(10,2)
[1] 45
JB
-Original Message-
From: Mario Morales [mailto:[EMAIL PROTECTED]
Sent: March 19, 2005 5:37 AM
To: r-help@stat.math.ethz.ch
Subject: [R] How I calculate nCr with R ? (Como calculo nCr con R? )
En español (In Spanish)
Necesito
I have problem with legend command. Please look this script:
dcbv.fm
Time Series:
Start = 1980
End = 2002
Frequency = 1
[1] 2994.023 3388.414 3111.762 2990.967 3077.438 3058.274 3049.934 2974.130
[9] 2889.659 2801.790 2631.391 2661.700 2312.526 2518.968 2567.044 2443.952
[17] 2117.638 2042.461
At 10:37 19/03/05, Mario Morales wrote:
En español (In Spanish)
Necesito calcular la en numeros de combinaciones de n cosas
tomando k al tiempo.
In English we usually read this as N choose r and with that clue you might
go ?choose
Incidentally your English is fine although I see the logic in
Hello, I'm new in R and I want to do one thing that is very easy in excel,
however, I cant do it in R.
Suppose we have the data frame:
data- data.frame(A=c(a1,a2,a3,a4,a5))
I need to obtain another column in the same data frame (lets say
B=c(b1,b2,b3,b4,b5) in the following way:
On Tuesday 15 March 2005 17:18, Patrick Connolly wrote:
I find the key and legend functions in Lattice very useful. Trouble
is, now I can see what else I'd like to be able to do with them.
If I put a title on a key, it appears too close to the key itself,
and if there's a line break in the
alexbri wrote:
Hello, I'm new in R and I want to do one thing that is very easy in excel,
however, I cant do it in R.
Suppose we have the data frame:
data- data.frame(A=c(a1,a2,a3,a4,a5))
I need to obtain another column in the same data frame (lets say
B=c(b1,b2,b3,b4,b5) in the following
Bernardo Rangel Tura wrote:
I have problem with legend command. Please look this script:
dcbv.fm
Time Series:
Start = 1980
End = 2002
Frequency = 1
[1] 2994.023 3388.414 3111.762 2990.967 3077.438 3058.274 3049.934
2974.130
[9] 2889.659 2801.790 2631.391 2661.700 2312.526 2518.968 2567.044
[EMAIL PROTECTED] wrote:
Hello, I'm new in R and I want to do one thing that is very easy in
excel, however, I cant do it in R.
Well, if you've deadened your brain by using Excel,
no wonder.
Suppose we have the data frame:
data- data.frame(A=c(a1,a2,a3,a4,a5))
Peter Dalgaard [EMAIL PROTECTED] writes:
- (not too sure of this, but R 2.1.0 will have some new code for
multivariate lm, with intra-individual designs, and
tests under the sphericity assumptions; it is possible that
your models can be reformulated in that framework. You'd have to
The suggestions by Uwe and Rolf use some of the subtler features of
R. A simpler (to me) if more tedious approach is provided by the
following:
Data - data.frame(a1=1:4, a2=5:8, a3=9:12)
Data$b1 - Data$a1/(Data$a1+Data$a2+Data$a3)
Data$b2 - Data$a2/(Data$a2+Data$a3)
Data
a1 a2 a3
Emma,
I am not an expert, but I have been trying to fit similar models.
Adding to Keith's reply to your question, I can suggest what I concluded was
the most reasonable model for my case. Based on Keith's Model1, you might
also want to allow for a correlation among years within each
hi everyone,
I'm still a newbie in statistics,
I have a question about beta distribution, that is,
On the ref/tutorials I've found on the net, why beta distribution always
have value p(x) more than 1?
As I know, any probability density function always have value not more
than 1?
is there any
A probability density must integrate to 1. The specific values of the density
can be either more or less than 1.
-roger
[EMAIL PROTECTED] wrote:
hi everyone,
I'm still a newbie in statistics,
I have a question about beta distribution, that is,
On the ref/tutorials I've found on the net, why
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