\r with cat performs a carriage return and line feed in R-GUI.
> for (i in 1:10) { cat("\rFoo",i) }
Foo 1
Foo 2
Foo 3
Foo 4
Foo 5
Foo 6
Foo 7
Foo 8
Foo 9
Foo 10
> _
Performs a carriage return only on the console.
> for (i in 1:10) { cat("\rFoo",i) }
Foo 10> _
Cheers,
Martin
On 18/03/2006
G'day Rolf,
> "RT" == Rolf Turner <[EMAIL PROTECTED]> writes:
RT> Is there a way of calculating the derivative of a function
RT> returned by splinefun()?
Yes, of course. :)
As somebody else once said: "this is R, anything can be done, the
question is just how easy it is to do so".
It
Hello, I would like to call a function that can take infinite time to
be executed in some circumstances (which can not be easily detected).
So, I would like that once the function is being executed for more
than two seconds it is stopped. I have found documentation for timers
but i did not found ho
Hello!
I am testing if my data are distributed under Laplace's distribution,
which I managed to do with:
> library(rmutil)
> ks.test(jitter(x), "plaplace", mean(x), sd(x))
Nevertheless, I am trying to bootstrap ks.test without any success.
Something is wrong in my commands:
> data = read.table("da
Gabor Grothendieck wrote:
> If you are just looking for something simple that may be good enough
> then assign the largest one to group 1, the second largest to group 2,
> ..., the 8th largest to group 8 and then start over again with group 1
> and so on.
>
> # test data
> set.seed(1)
> x <- sampl
On 3/18/06, Dan Bolser <[EMAIL PROTECTED]> wrote:
> Gabor Grothendieck wrote:
> > If you are just looking for something simple that may be good enough
> > then assign the largest one to group 1, the second largest to group 2,
> > ..., the 8th largest to group 8 and then start over again with group
> "BeT" == Berwin A Turlach <[EMAIL PROTECTED]>
> on Sat, 18 Mar 2006 17:08:47 +0800 writes:
BeT> G'day Rolf,
> "RT" == Rolf Turner <[EMAIL PROTECTED]> writes:
RT> Is there a way of calculating the derivative of a function
RT> returned by splinefun()?
BeT> Yes, of
Hi,
I have a function of the second grade, with 2 parameters:
y~A^2 + A + B^2 + B
The response y is a measurement for the precision of the analytical method,
where A en B are method parameters. As its neccesary to keep the precision of
the analytical methad as good as possible, its usefull
Mathias Ehrich wrote:
> Hi all,
>
> this might be a very stupid question, but I tried for several hours now
> and I'm helpless. I'm running windows and R 2-2-1. Recently, every time
> when I have an error in my code a message box pops up telling me the
> error message. The code won't continue bef
pau carre wrote:
> Hello, I would like to call a function that can take infinite time to
> be executed in some circumstances (which can not be easily detected).
> So, I would like that once the function is being executed for more
> than two seconds it is stopped. I have found documentation for time
Where did you find the function "forecast"? It is NOT a standard R
function.
I just tried 'methods(class="ar")', which produced the following:
[1] predict.ar* print.ar*
Non-visible functions are asterisked
The documentation for 'predict.ar' includes the follo
Have you considered the Bioconductor project (www.bioconductor.org)?
If you are not already familiar with their capabilities, I suggest you
review their capabilities and consider posting a question to their
listserve if you don't find the answer without that.
hope this hel
Hi everybody,
let us assume i have the following matrixX and vectorY
matrixX <- runif(100)
dim(matrixX) <- c(10,10)
vectorY <- as.matrix(as.character(seq(1,10)))
if I define:
subsample<-c("2")
i can extract the rows from matriX based on the elements in vectorY which
are listed in subsample
matri
On 3/18/06, Uwe Ligges <[EMAIL PROTECTED]> wrote:
> pau carre wrote:
> > Hello, I would like to call a function that can take infinite time to
> > be executed in some circumstances (which can not be easily detected).
> > So, I would like that once the function is being executed for more
> > than tw
matrixX[vectorY %in% subsample,]
?"%in%"
Roberto Furlan wrote:
> Hi everybody,
> let us assume i have the following matrixX and vectorY
>
> matrixX <- runif(100)
> dim(matrixX) <- c(10,10)
> vectorY <- as.matrix(as.character(seq(1,10)))
>
> if I define:
> subsample<-c("2")
>
> i can extract th
daer list,
i want to save a result as mentioned above.
for (i in 1:100) {
a[i] <- write.table(a[i], "C:/.../result"i"")
}
how is the correct way to save the results?
thank you
stefan
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/
On 3/17/2006 9:44 AM, Jeffrey Racine wrote:
> Hi, and thanks in advance for your time.
>
> Background - I am working on a package and wish to have a routine's
> progress reported. The routine can take some time, and I would like to
> inform the user about the routine's progress. I have scoured the
Is there any possibility to divide too long text in a plot to two or more
lines, when using labels-parameter in the text()-command?
Here is an example picture:
http://users.utu.fi/attenka/253.jpeg
My example script is something like this:
text(1,0.7,labels=Chordnames[fnid(pcs%%12)]) # according
See ?sprintf and/or ?paste.
/Henrik
On 3/18/06, Stefan Semmeling <[EMAIL PROTECTED]> wrote:
> daer list,
>
> i want to save a result as mentioned above.
>
> for (i in 1:100) {
> a[i] <- write.table(a[i], "C:/.../result"i"")
> }
>
> how is the correct way to save the results?
>
> thank you
>
>
Hi,
I have read about the use of symbols() to draw circles of different
sizes, but I have not been able to find out how to add a legend to
such a graph, legend that would display some specific sizes and their
meaning.
Before finding the symbols function in Paul Murrell's book, I had
rolle
Hi All,
I have the following adjacency matrix for a directed graph:
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,]00000000
[2,]00000000
[3,]10000000
[4,]00100000
[5,
Denis Chabot wrote:
> Hi,
>
> I have read about the use of symbols() to draw circles of different
> sizes, but I have not been able to find out how to add a legend to
> such a graph, legend that would display some specific sizes and their
> meaning.
>
> Before finding the symbols function i
On Sat, 18 Mar 2006, Denis Chabot wrote:
> Hi,
>
> I have read about the use of symbols() to draw circles of different
> sizes, but I have not been able to find out how to add a legend to
> such a graph, legend that would display some specific sizes and their
> meaning.
>
> Before finding
On Sat, 18 Mar 2006, Atte Tenkanen wrote:
> Is there any possibility to divide too long text in a plot to two or more
> lines, when using labels-parameter in the text()-command?
>
> Here is an example picture:
>
> http://users.utu.fi/attenka/253.jpeg
>
> My example script is something like this
On 3/18/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
> Is there any possibility to divide too long text in a plot to two or more
> lines, when using labels-parameter in the text()-command?
>
> Here is an example picture:
>
> http://users.utu.fi/attenka/253.jpeg
>
> My example script is something li
Thank you for answering, both Roger and Henrik
There are only 5 cases which need divisions, so I inserted \n to them and
now everything works.
Atte
> On 3/18/06, Atte Tenkanen <[EMAIL PROTECTED]> wrote:
>> Is there any possibility to divide too long text in a plot to two or
>> more
>> lines, whe
You might find the 2nd part of the following response useful
https://stat.ethz.ch/pipermail/r-help/2006-March/090611.html
And if you want to RTFM, I guess sections 2.5, 2.7, 5.1, 5.2 of
http://cran.r-project.org/doc/manuals/R-intro.html might be useful.
PS:
1) R-help is designed for and by unp
Do you by any chance want to sample from each group equally to get an
equal representation matrix ? Here is an example of the input :
mydf <- data.frame( value=1:100, value2=rnorm(100),
grp=rep( LETTERS[1:4], c(35, 15, 30, 20) ) )
which has 35 observations from A, 15 from B,
Berton,
What you say makes sense and helps. I could do a parametric
bootstrapping. However, I cannot make predict.nlme work at all, even
without the se's. It would save me a lot of time to be able to use
the predict as the statistic in boot.
Does "predict.nlme" work at all? It is a listed me
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