On 7/30/06, Kartik Pappu <[EMAIL PROTECTED]> wrote:
> Hello All,
>
> I have a device that spews out experimental data as a series of text
> files each of which contains one column with several rows of numeric
> data. My problem is that for each trial it gives me one text file
> (and I run between
Spencer,
Thank you for the kind and elaborate reply to my previous post.
I did consider the option you suggested and many variations. Depending on the
order of the random factors, lme will either give the same output as the aov
model for soiltype or for habitat, but not both in the same model.
Michael Papenfus wisc.edu> writes:
>
> I have defined the following function:
>
> fr<-function(x) {
> u<-x[1]
> v<-x[2]
> sqrt(sum((plnorm(c(3,6),u,v)-c(.55,.85))^2))
> }
> which I then solve using optim
> y<-optim(c(1,1),fr)
>
> > y$par
> [1] 1.0029771 0.7610545
> This works fine
I have defined the following function:
fr<-function(x) {
u<-x[1]
v<-x[2]
sqrt(sum((plnorm(c(3,6),u,v)-c(.55,.85))^2))
}
which I then solve using optim
y<-optim(c(1,1),fr)
> y$par
[1] 1.0029771 0.7610545
This works fine.
Now I want to use these two steps on a dataframe:
mydat<-data.
On 7/31/2006 12:36 AM, Kartik Pappu wrote:
> Hi all,
>
> I created three separate square matrices (lets say R, G, and B). each
> one contains a series of values between 0 and 1. I want to be able to
> take for example R[1], G[1], B[1] and create a rgb color value into a
> fourth matrix. I tried
Hi all,
I created three separate square matrices (lets say R, G, and B). each
one contains a series of values between 0 and 1. I want to be able to
take for example R[1], G[1], B[1] and create a rgb color value into a
fourth matrix. I tried using the rgb function but I must be doing
something w
Just to answer my own question I just discovered trellis.panelArgs()
and that can be used to give the following solution:
library(lattice)
library(grid)
x <- 1:10
xyplot(x ~ x | gl(2,1), layout = 1:2)
trellis.focus("panel", 1, 1)
grid.rect(w = 0.5, gp = gpar(fill = "light grey"))
# r
Try:
?sensory
str(sensory)
dput(sensory)
lapply(sensory, class)
lapply(sensory, dim)
to see what it looks like inside. Seems that sensory is a data frame
consisting of two columns each of which is a matrix except that each
has a class of "AsIs". Thus try this (where I(...) creates objects of
cl
Dear all,
I am trying to my dataframe for the PLS analysis using the PLS package.
However I have some trouble generating the correct dataframe. The main
problem is how to use one name to represent several columns in the
dataframe.
The example dataframe in PLS package is called "sensory". I cannot
Thanks. That's helpful.
I would be interested in the case where
1. one does not have a variable latticeplot, as per your example,
but just has the output of
xyplot(x ~ x | gl(2,1), layout = 1:2)
sitting on the screen, having been "printed" by a prior
function. We can assume that no other g
I am resubmitting my question from earlier today -- this time with the
proper plain text formatting.
I have a dataset in which I have identified a three-way interaction. Factor
A has 3 levels, factor B has 4 levels, and factor C has 3 levels. I would
like to produce the following:
1) A manova in
Hi
Gabor Grothendieck wrote:
> I am trying to create a lattice plot and would like to later, i.e. after
> the plot is drawn, add a grey rectangle behind a portion of it.
> The following works except that the rectrangle is on top of and
> obscures a portion of the chart. I also tried adding col =
"Marco Boks" <[EMAIL PROTECTED]> writes:
> Hi,
>
> I need to plot the beta as the symbol, followed by the index 3 as the title
> of a graph.
>
> This code works> main= bquote(paste("Results for ", beta ==.(b1))
>
> but I also need the index 3.
> I tried (simplified):
>
> >plot(x,y, main= bqu
I assume the 3 is supposed to be a subscript. Try this:
b1 <- x <- y <- 1
plot(x,y, main = bquote("Results for " ~ beta[3] ==.(b1)))
On 7/30/06, Marco Boks <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I need to plot the beta as the symbol, followed by the index 3 as the title
> of a graph.
>
> This
I have a dataset in which I have identified a three-way interaction. Factor
A has 3 levels, factor B has 4 levels, and factor C has 3 levels. I would
like to produce the following:
1) A manova in which I can test the effect of factor C for each
combination of factor A * factor B. I know
Hi,
I need to plot the beta as the symbol, followed by the index 3 as the title of
a graph.
This code works> main= bquote(paste("Results for ", beta ==.(b1))
but I also need the index 3.
I tried (simplified):
>plot(x,y, main= bquote(paste("Results for ", beta, "3", ==.(b1
and a few othe
> > Why do the results differ although the estimates (random
> effects and
> > thus their variances) are almost identical? I noticed that
> lme() does
> > not compute the standard errors of the variances of the
> random effects
> > - for several reasons, but if this is true, how does
> ran
The only references to this I can find searching the archives are to a
student who asked in relation to his course work on a stats course.
Promise I'm not doing that!
I have a situation in which we want to test proportions against an
expected proportion, binom.test() is great. I'd like to do some
Please provide reproducible examples (as discussed at end of each
posting):
Lines <- "Apple S 21.0
Apple A 21.6
Apple O 43.0
Orange A 45.0
Orange O 64.0
Orange S 32.5
Mango M 40.3
Mango A 32.6
Mango S 24.6
"
tb <- read.table(textConnection(Lines))
# alternative 1 - create a matrix
t
Hello :
I have matrix with dimensions(200 X 20,000). I
have another
file, a tab-delim file where first column
variables are row
names and second column variables are column
names. Tab-delim file has smaller values than the
matrix.
Matrix = tmat
tab-delim file read as data.frame = tb
My aim
Have you tried RSiteSearch("MLWin")? I just got 29 hits. I wonder
if any one of these might relate to your question?
If you would like more help on this issue from this listserve, please
submit another post, preferably illustrating your question with the
simplest possible
Have you tried using corARMA? Won't this give you the symmetric
Toeplitz form you desire, albeit in a different parameterization?
Hope this helps.
Spencer Graves
[EMAIL PROTECTED] wrote:
> I am trying to use nlme but instead of using one of the “identity” variance
You can have one observation per subject with multiple subjects nested in a
group. If you only have 1 observation per group, then there is no multilevel
structure to your data.
For example, 30 students in a classroom or 20 employees in an office division
are appropriate data structures. On the
[EMAIL PROTECTED] wrote:
> Kartik Pappu a écrit :
>
>
>>However I need to plot my data in a log transformed color scale. Is
>>this possible? I will be happy to explain further, but basically I
>>need to do this because there are large variations in the max and min
>>values of my raw data and I
nurza m wrote:
> Hello,
>
> I am struggling to find the root of a exponent
> function.
> "uniroot" is complaining about a values at end points
> not of opposite sign?
And you think it is not the case? Why?
We cannot help because you have not given a reproducible example (What
is w and gp?), whi
Kartik Pappu a écrit :
> However I need to plot my data in a log transformed color scale. Is
> this possible? I will be happy to explain further, but basically I
> need to do this because there are large variations in the max and min
> values of my raw data and I am trying to highlight the diffe
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