What do you get from the following:
max(with(df1, table(Subj, Time)))?
With cases like this, "lme" gives an answer with a bogus distinction
between variance components for "time" and "residuals". I don't know
about "aov" or "JMP", but I know that "varcomp" in S-Pl
Hi..
I pass a lm() object to step() but after a few steps it stops with the
error message.
say:
x1<-lm(y~.,data=z)
x2<-step(x1)
i have 516 observations and 299 variables.
after a few steps i get the error message:
Error in one %*% x : requires numeric matrix/vector arguments
Thanks to all who helped me with this problem, especially Bill Venables
and Gabor Grothendieck. I hope one day to learn more about the advanced
features of the language used by Bill.
From a practical standpoint I think I will just avoid doing things like
this in my teaching. It is hard enough
Finn Sandø fs-analyse.dk> writes:
>
> When I try to import an spss sav file with read.spss() I am getting the
> following error
> 'Error in read.spss("X:\\.sav") : error reading system-file header'
> and the import process is aborted.
> I have tried in v. 2.3.0 and 2.3.1
> The sav-file loa
On 8/3/06, John Fox <[EMAIL PROTECTED]> wrote:
> Levene's test tests the null hypothesis that the variance are equal, so a
> small p-value suggests that they are not. Looking at your output, it seems
> odd that you have as many as 96 groups.
Thanks again, John. I have 4 factors with 3, 4, 4 and 2
Dear Paul,
Levene's test tests the null hypothesis that the variance are equal, so a
small p-value suggests that they are not. Looking at your output, it seems
odd that you have as many as 96 groups.
John
John Fox
Department of Sociology
McMaster University
Hamil
On 8/2/06, Walker, Sam <[EMAIL PROTECTED]> wrote:
> How do I change the font size in the facet labels along the edges of the
> plot?
>
> For example (from the ggplot help file):
> p<-ggplot(tips, sex ~ smoker, aesthetics=list(x=tip/total_bill))
> gghistogram(p)
>
> In this plot, the facet l
Does anyone know of a way of dealing with unbalanced mixed effects
(fixed and random factors) for fully factorial designs.
An example of such data is given below;
The response variable is SQRTRECRUITS
SEASON is a random factor
DENSITY is a fixed factor
Thus DENSITY:SEASON is a fixed factor.
The
On Wed, 02 Aug 2006 17:12:53 -0400, Chuck Cleland wrote:
> Why not do it this way?
>
> Df$bat <- replace(Df$bat, Df$bat >=50, 100)
Is that any different, performancewise, than the following?
Df$bat[Df$bat >= 50] <- 100
Gerald Jansen
...
John Kane wrote:
> Simple example
>
> cat <- c( 3,5,6,8
Does anyone know how summary.Design in Hmisc selects the baseline level
for an odds ratio? Does it select the level of the factor variable with
the largest number of observations?
Regards, -Cody
This e-mail, facsimile, or letter and any files or attachmen...{{dropped}}
If you set it through par.settings then it will affect both the
drawing and the legend:
xyplot(Sepal.Length ~ Petal.Length, iris, groups = Species, auto.key = TRUE,
par.settings = list(superpose.symbol = list(pch = "*", cex = 1)))
On 8/2/06, Kaushik Katari <[EMAIL PROTECTED]> wrote:
> I am doi
On 8/2/06, John Fox <[EMAIL PROTECTED]> wrote:
> The argument y is the response variable and group is a factor defining
> groups (as ?levene.test says). If you have more than one factor, then you
> can use interaction() to create from them a factor with levels given by the
> product set of the leve
I am doing a xyplot: (x~y, groups = z, pch=8, auto.key=T). This changes
the symbol in the graph to an asterisk (*), but not in the legend, which
is still an open circle. I have found out how to manipulate the position
and the color of the letters in the legend, but cannot change the legend
symbol
--- roger koenker <[EMAIL PROTECTED]> wrote:
> it is the well-known wicked which problem: if you
> had (grammatically
> incorrectly)
> thought "... which I want to change" then you might
> have been led
> to type (in another window):
>
> ?which
>
> and you would have seen the light. M
--- Chuck Cleland <[EMAIL PROTECTED]> wrote:
> John Kane wrote:
> > Simple problem but I don't see the answer. I'm
> trying
> > to clean up some data
> > I have 120 columns in a data.frame. I have one
> value
> > in a column named "blaw" that I want to change.
> How do
> > I find the coordinates
Dear all,
I am using the PLS package for PLSR analysis. And I have a basic question
about the standardize procedure, which I feel the PLS manual does not
explain clearly. I am hoping that I could get some help from the list.
>From the example in the "Standardization of Data Matrices" section, I c
John Kane wrote:
> Simple problem but I don't see the answer. I'm trying
> to clean up some data
> I have 120 columns in a data.frame. I have one value
> in a column named "blaw" that I want to change. How do
> I find the coordinates. I can find the row by doing a
> subset on the data.frame but ho
it is the well-known wicked which problem: if you had (grammatically
incorrectly)
thought "... which I want to change" then you might have been led
to type (in another window):
?which
and you would have seen the light. Maybe that() should be an alias
for which()?
url:www.econ.uiu
--- jim holtman <[EMAIL PROTECTED]> wrote:
> ?which
>
> > which(Df >= 50, arr.ind=T)
> row col
> 5 5 4
I knew it was going to be blinding obvious! I even
read
?which somehow misunderstood arr.ind.
Thanks again.
>
> On 8/2/06, John Kane <[EMAIL PROTECTED]> wrote:
> >
> > Simple probl
?which
> which(Df >= 50, arr.ind=T)
row col
5 5 4
On 8/2/06, John Kane <[EMAIL PROTECTED]> wrote:
>
> Simple problem but I don't see the answer. I'm trying
> to clean up some data
> I have 120 columns in a data.frame. I have one value
> in a column named "blaw" that I want to change. How
Simple problem but I don't see the answer. I'm trying
to clean up some data
I have 120 columns in a data.frame. I have one value
in a column named "blaw" that I want to change. How do
I find the coordinates. I can find the row by doing a
subset on the data.frame but how do I find out here
"blaw "
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello!
I want to create a messagebox whenever the user wants to destroy the window
(e.g. or the 'x' in the right top corner) and ask if a modified file
should be saved or not.
If 'cancel' is chosen then nothing should happen and the windows still should
be
existing. This doesn't work. When I
On Wed, 2 Aug 2006, Christian Hennig wrote:
> Thank you Brian!
>
> > > I'm updating my fpc package at the moment and will add some new functions.
> > > I learned that there should be print and summary methods for the key
> > > functions.
> >
> > for 'classes', I think.
>
> Yes.
>
> > > But in s
On 2 Aug 2006 at 13:48, R Heberto Ghezzo, Dr wrote:
> HI, just my 2 cents. Bonferroni et al, assume independent tests, thus
> p ~ p*k with k the number of tests, in repeated measures, each measure
> is correlated with the previous, so k is not 2 but 2-q. I do not know
> q but it should be a functi
How do I change the font size in the facet labels along the edges of the
plot?
For example (from the ggplot help file):
p<-ggplot(tips, sex ~ smoker, aesthetics=list(x=tip/total_bill))
gghistogram(p)
In this plot, the facet labels are "smoker: No", "smoker: Yes", "sex:
Female", "sex: Ma
I'm trying to use the lmeSplines package together with lme4.
Below is (1) an example of lmeSplines together with nlme (2) an
attempt to use lmeSplines with lme4 (3) then a comparison of the
random effects from the two different methods.
(1)
require(lmeSplines)
data(smSplineEx1)
dat <- smSplineEx
Thank you Brian!
>> I'm updating my fpc package at the moment and will add some new functions.
>> I learned that there should be print and summary methods for the key
>> functions.
>
> for 'classes', I think.
Yes.
>> But in some cases the print method will make use of more or less all the
>> out
On Wed, 2 Aug 2006, Christian Hennig wrote:
> Hi list,
>
> I'm updating my fpc package at the moment and will add some new functions.
> I learned that there should be print and summary methods for the key
> functions.
for 'classes', I think.
> The purpose of the summary methods seems to be to
HI, just my 2 cents. Bonferroni et al, assume independent tests, thus p ~ p*k
with k the number of tests, in repeated measures, each measure is correlated
with the previous, so k is not 2 but 2-q. I do not know q but it should be a
function of the correlation between measures, ie the Sigma in ge
I seem to be on a roll of being dumb today. Sorry for posting my previous
silly solution to Erin's permutation problem. Please **do** ignore it.
-- Bert
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Berton Gunter
> Sent: Wednesday, August 02,
Erin:
You got 2 (so far) pre-packaged functions .Here's an obscenely inefficient
but short un-prepackaged way to do it:
k<-4
z<- do.call('expand.grid',as.data.frame(matrix(rep(1:k,k),nc=k)))
results<- z[apply(z,1,function(x)length(unique(x))==k),]
It is too inefficient to make public, though.
--
Dear all,
I am using different multiple regression models (OLS and principal
component regression (PCR)) to make prediction of my test set. And those
models come from the same training set, except that the number of
variables or descriptors (columns of X) used in OLS is less than those
used in PCR
not very-well hidden:
permutations in (e1071)
permn in (combinat)
David L. Reiner
Rho Trading Securities, LLC
Chicago IL 60605
312-362-4963
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Erin Hodgess
Sent: Wednesday, August 02, 2006 11:57 AM
To: r-hel
Dear R People:
Suppose I have the 4 numbers: 1,2,3,4.
I would like to create a listing of the permutations
of 4 items taken 4 at a time.
Is there a built in function for that, please?
Thanks in advance!
R 2-3-1 for Windows or Linux
Sincerely,
Erin Hodgess
Associate Professor
Department of Compu
Hi list,
I'm updating my fpc package at the moment and will add some new functions.
I learned that there should be print and summary methods for the key
functions.
The purpose of the summary methods seems to be to reduce the
possibly incredibly complex information in the function's output and th
UseR's-
As this is slightly off-topic I will limit the discussion to only the
major points; for further information feel free to reply off-line.
DIA and FDA are hosting a forum to discuss (as per the Goal of the
announcement--see link below) "a vendor-neutral software product to
support validated
René J.V. Bertin gmail.com> writes:
> I have some data in a data.frame where for each of a number of
> subjects, I have scores for all of a number of symptoms.
>
> Subjects are subdivided in a number of groups, which have unequal sizes.
>
> I'd like to plot between-group differences in the scor
Boris:
Thankyou for this. All the RPAD links now appear to be dead. However, the
Reference Card is still available in the CONTRIBUTED link on CRAN, as I
said.
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
>
> Thanks for the resources, Berton. but unfortunately, that
Dear all,
I am using different multiple regression models (OLS and principal
component regression (PCR)) to make prediction of my test set. And those
models come from the same training set, except that the number of
variables or descriptors (columns of X) used in OLS is less than those
used in PCR
Assuming this data:
s <- structure(list(L.qol.0 = 83, L.qol.0.08 = 86, L.qol.0.17 = 89,
L.qol.0.25 = 92, L.qol.0.5 = 91, L.qol.0.42 = 87, L.qol.0.34 = 90),
.Names = c("L.qol.0", "L.qol.0.08", "L.qol.0.17", "L.qol.0.25",
"L.qol.0.5", "L.qol.0.42", "L.qol.0.34"),
class = "data.frame", r
On Wed, 2 Aug 2006, Thomas Kuster wrote:
Hello
When I read a SPSS *.por file with read.spss everything after a umlaut is
missing:
This sounds like a conflict between encodings -- eg if R is assuming UTF-8
and the file is encoding in Latin-1 then the sequence
U+00FC : LATIN SMALL LETTER U WI
Hello R users
Would somebody know how to estimate survival from a frailty cox model,
using the function survfit
and the argument newdata ? (or from any other way that could provide
individual expected survival
with standard error); Is the problem related to how the random term is
included in ne
Hi,
I am working on some longitudinal data in wide format and I am having a problem
ordering the data columns. To expand, a subset of what I am working on is as
follows;
>s
L.qol.0 L.qol.0.08 L.qol.0.17 L.qol.0.25 L.qol.0.5 L.qol.0.42 L.qol.0.34
1 83 86 89 92
Hello,
I have some data in a data.frame where for each of a number of
subjects, I have scores for all of a number of symptoms.
Subjects are subdivided in a number of groups, which have unequal sizes.
I'd like to plot between-group differences in the scores on the
various symptoms. Ideally, that
This is getting to be a faq -- here is a prior answer:
> No, but the objective function can be computed for any fitted
> rq object, say f, as
>
> rho <- function(u,tau=.5)u*(tau - (u < 0))
> V <- sum(rho(f$resid, f$tau))
>
> so it is easy to roll your own
I don't much like R1, or
Hi
I am following the model building strategy that is outlined in the Pinheiro and
Bates book wrt including covariates but am having a problem with the plot.
Basically I am using 4 covariates (1 of them is continuous) and 3 of them are
fine but the 4th one is being shown as a scatterplot despite
On 8/2/06, Sergio Martino <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I would like to realize in R a structure like the fortran common ie a way to
> declare some variable that can only be accessed by all the functions which
> need to.
>
> Browsing the archive it seems that the simplest way is to declare t
Dear R Users,
Did someone implemented the R1 (Pseudo R-2) and likelihood ratio
statistics for quantile regressions, which are some of the inference
procedures for quantile regression
found in Koenker and Machado (1999)?
I tried the Ox version, but my dataset is too large (> 50.000) and the
al
Hello
When I read a SPSS *.por file with read.spss everything after a umlaut is
missing:
> library("foreign")
> spssdaten <- read.spss("projets.por")
> attr(spssdaten$PROJETX, "value.labels")[1:20]
Bg Stammzellenforschung Bb
Hello
When I read a SPSS *.por file with read.spss everything after a umlaut is
missing:
> library("foreign")
> spssdaten <- read.spss("projets.por")
> attr(spssdaten$PROJETX, "value.labels")[1:20]
Bg Stammzellenforschung Bb
Thanks to all for their help. I am busy today but tomorrow I will have
time to digest all the feedback and follow up if necessary
Cheers, Murray
--
Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html
Department of Statistics, University of Waikato, Hamilton, New Zealand
Emai
dat[dat==9] <- NA
because the result of mean() is real and summary()'s output is a vector.
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax : 33
Hi,
I would like to realize in R a structure like the fortran common ie a way to
declare some variable that can only be accessed by all the functions which
need to.
Browsing the archive it seems that the simplest way is to declare the
variables and the functions in a big function which wraps all.
Mauricio Cardeal wrote:
> Hi all
>
> # I have this data set and how can I assign NA´s in just one command ?
is.na(dat[dat==9]) <- TRUE
> And why the summary(dat) function preserves the value 9 as real. ?
>
Because you have not changed the contents of dat at all, only the
contents of x,y,z, an
Hi all
# I have this data set and how can I assign NA´s in just one command ?
And why the summary(dat) function preserves the value 9 as real. ?
x <- c(1,2,3,9,4)
y <- c(3,6,9,2,3)
z <- c(9,9,2,2,8)
w <- c(6,5,3,0,9)
dat <- cbind(x,y,z,w)
summary(dat)
x[x==9] <- NA
y[y==9] <- NA
z[z==9] <- NA
Dear Paul,
The argument y is the response variable and group is a factor defining
groups (as ?levene.test says). If you have more than one factor, then you
can use interaction() to create from them a factor with levels given by the
product set of the levels of the individual factors. Here's an exa
Try something along these lines assuming that the current
directory is \Program Files\R\R-2.3.1pat. Note use
of paste to create the command line to pass to pipe:
# search for indicated string in each of the files and
# for each match output the file name
Files <- c("CHANGES", "COPYING", "NEWS", "
Hi folks
I wonder if anyone can help me. I want to run some simulations to see
how big a sample size might be necessary to distinguish a curved
bivariate relationship (e.g. something that might be best described
by a quadratic model) from a relationship that is two straight lines
with a su
Hi all,
I have the following problem.
Inside R, I am trying to run a loop on several files.
The data are stored in these files in a peculiar way, thus, at the same time I
load the data, I would like to invoke a utility. I do this with "pipe". (The
utility I am using is gbget from the package gb
Dear All
I am trying to use Levene's test (of package car), but I do not
understand quite well how to use it. '?levene.test' does not
unfortunately provide any example. My data are in a data frame and
correspond to 4 factors plus response. Could someone please give me an
example about how to use t
Have you tried fitting the model with "verbose=TRUE" and possibly
also "control=nlmeControl(msVerbose=TRUE)"?
Also, have you consulted Pinheiro and Bates (2000) Mixed-Effects
Models in S and S-PLUS (Springer)? That book contains several examples
of use of lme and nlme. R s
The examples in the book were run in 2001, using S-PLUS (as it says).
The R package e1071 has changed since then, and hence the results it gives
have changed. However, the S-PLUS version (which has not been updated)
still gives the results in the book.
The `problem' is your expectation that R
Can anyone explain the root of my problem?
When I type the following code into R, I receive 42 support
vectors insted of the 21 stated in the book 'Modern Applied
Statistics with S':
library(MASS);
library(e1071);
library(class);
lcrabs <- log(crabs[,4:8]);
(svm(crabs$sp ~ ., data = lcrabs, cost
I'm not familiar with the correlation adjustment to Bonferroni you
mention below, though it sounds interesting. However, I think there is
something not right about it or about how you have interpreted it. Your
code produced the following for me:
p.value.raw p.value.bon p.va
data.frame(x = with(df1, rep(x, freq)))
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax : 33 (0)3.20.87.10.31
http://www-good.ibl.fr
-
Thanks for the resources, Berton. but unfortunately, that rpad link fails,
and I still do not know where to get leaps or regsubsets functions.
Sincerely, Boris.
--
Hello, dear r team. Please help the newbie. My r is not finding leaps or
regsubsets finctions. What should I do? Any na
Dear friends,
my question is how to aggregate dataset and the inverse manipulation.
e.g.My dataset
data structure1:
x
1
1
2
3
3
data structure2:
x freq
1 2
2 1
3 2
Then how to generate dataset2 from dataset1 and generate dataset1 from
dataset2?
e.g. dataset2 from dataset1 :
x<-c(1,1,2,3,3)
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