Hello.
I ran into a similar situation as you did, and according to D. Bates,
this can be due to the inclusion of the offset variable. It appears that
the mcmcsamp does not work very well with offset variables. For more
details, have a look at this thread:
Ray Cheung wrote:
Dear All,
I've a 10 by 5 data frame like this
set.seed(1001)
a - rnorm(10)
b - rnorm(10)
c - rnorm(10)
d - rnorm(10)
e - rnorm(10)
A - cbind(a,b,c,d,e)
Each row is one datum. I want to resample within A[,5]. Fit the regression
lines lm(A[,5] ~ A[,1] + A[,2]) and
Can someone remind me how to change the columns in df.a into a two column
df.b that contains one column of data and another column of the original
column headings as levels.
Example:
a=1:3
b=4:6
c=7:9
df.a=data.frame(a,b,c)
Should become in df.b:
dat lev
1 a
2 a
3 a
4 b
5
This is exactly what I need
Thank's a lot!!
Guazzetti Stefano wrote:
you could try mapply
mydata2-mapply([, mydata, lapply(mydata, function(x) !x %in% A))
mydata2[[1]]-A #to replace the obviously deleted elements of A
mydata2
mydata2[[1]]
mydata2[[2]]
mydata2[[3]]
On Wed, 2007-03-14 at 03:53 -0500, Robert Baer wrote:
Can someone remind me how to change the columns in df.a into a two column
df.b that contains one column of data and another column of the original
column headings as levels.
Example:
a=1:3
b=4:6
c=7:9
df.a=data.frame(a,b,c)
Robert Baer wrote:
Can someone remind me how to change the columns in df.a into a two column
df.b that contains one column of data and another column of the original
column headings as levels.
Example:
a=1:3
b=4:6
c=7:9
df.a=data.frame(a,b,c)
Should become in df.b:
dat lev
1
Erik,
I haven't seen an answer to your question, so I'll try to answer it. The
problem is that you switched the degrees of freedom. You had:
1 - pf(qf(.95, Vl, 1, ncp = 0), Vl, 1, ncp = Dl)
[1] 0.05472242
But it should be:
1 - pf(qf(.95, 1, Vl, ncp = 0), 1, Vl, ncp = Dl)
[1] 0.532651
Cheers,
Hi,
I am looking for a way to compare if every element of a vector is 0.
i.e.
while(abs(U) 0)
{
..
}
is there a function for this or do I have to write one?
I'd appreciate your help!
Benjamin
__
R-help@stat.math.ethz.ch mailing list
Benjamin Dickgiesser wrote:
Hi,
I am looking for a way to compare if every element of a vector is 0.
i.e.
while(abs(U) 0)
{
..
}
is there a function for this or do I have to write one?
I'd appreciate your help!
Benjamin
Hi,
If I understand you correctly, you are not far, is
try: all(U 0)
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
Thx for all your responses!
while(all(abs(U) 0))
{
..
}
was what I am looking for.
On 3/14/07, Benjamin Dickgiesser [EMAIL PROTECTED] wrote:
Hi,
I am looking for a way to compare if every element of a vector is 0.
i.e.
while(abs(U) 0)
{
..
}
is there a function for this or do I
On 3/13/2007 7:02 PM, Kevin R. Coombes wrote:
Hi,
Consider the following (much simplified) Sweave example:
--
First, we set the value of $x$:
chunk1,eval=FALSE=
x - 1
@
Then we set the value of $y$:
chunk2,eval=FALSE=
y - 2
@
Thus, the overall algorithm has this
Benjamin Dickgiesser wrote:
I am looking for a way to compare if every element of a vector is 0.
i.e.
while(abs(U) 0)
{
..
}
Notice that abs(U) [and, in general, most functions that are
defined on scalars, like sin, cos, exp, ...], when U is a vector,
operates on the _elements_ of
On Mar 14, 2007, at 7:05 AM, Alberto Monteiro wrote:
prod(U 0)
But this is not the most elegant solution, because there is
a function to check if all [and another to check if any] component
of a vector of booleans are [is] true: it's all(V) [resp. any(V)].
So:
all(U 0)
Just for the
Hi,
is there a package available which lets me generate random data for
the geometric distribution with density:
p(x) = p (1-p)^(x-1) ?
rgeom uses the density p(x) = p (1-p)^x.
Thank you,
Benjamin
__
R-help@stat.math.ethz.ch mailing list
On Mar 14, 2007, at 8:44 AM, Benjamin Dickgiesser wrote:
Hi,
is there a package available which lets me generate random data for
the geometric distribution with density:
p(x) = p (1-p)^(x-1) ?
rgeom uses the density p(x) = p (1-p)^x.
Why not just use rgeom, and then add 1 to all the
Kevin R. Coombes [EMAIL PROTECTED] writes:
[2] You are also correct that there is no advantage if I just call
them chunk1 and chunk2. But if I call them something more
interesting, like perform.quantile.normalization or
truncate.and.log.transform,
then I can use this structure to explain the
Hi,
I don't know of a standard way to indicate this; I would have suggested
combined,expand=FALSE
(with expand=TRUE the default), except for the fact that Seth Falcon
already suggested the same notation in his response...so I can only
second the motion.
Kevin
Duncan Murdoch wrote:
This morning I tried to see if I could find the r-help mailing list on
Google Groups, which has an interface that I like. I found three
Google Groups (The R Project for Statistical Computing, rproject,
and rhelp) but none of them are connected to the r-help list.
Is there perhaps some reason why
I use tune.svm to tune gamma and cost for my training dataset.
I use PC, it runs very slowly. Does anyone know how to make it faster?
Aimin
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
I know nothing about Google Groups, but FWIW, I think it would be most
unwise for R/CRAN to hook up to **any** commercially sponsored web portals.
Future changes in their policies, interfaces,or access conditions may make
them inaccessible or unfreindly to R users. So long as we have folks willing
Fast is a relative term. Tell us more about your version, system, data
and the kernel that you are using (I'm guessing it is a RBF).
If you are building a classification model and there are two classes,
the svmpath package can be used to get quick predictions over the
cost/regularization
Hi,
I am trying to restrict a data set so as not to included outliers.
Specifically, I would like to specify a percentage where a fraction of
observations are eliminated from the data set, much in the same way that the
trimmed mean function works - but leaving the restricted data set intact.
Well, I don't see what danger could arise from the fact that Google
Groups is owned by a company. Google Groups provides access to all of
usenet, plus many mailing lists (e.g. the ruby-talk mailing list for
Ruby programmers). They don't control any of the newgroups or mailing
lists that they
On Wed, Mar 14, 2007 at 11:48:15AM -0400, Paul Lynch wrote:
This morning I tried to see if I could find the r-help mailing list on
Google Groups, which has an interface that I like. I found three
Google Groups (The R Project for Statistical Computing, rproject,
and rhelp) but none of them are
Hello, R experts,
I have a list called dataHP which has 30 elements (m1, m2, ..., m30).
Each element is a 7x6 matrix holding yield data from two factors
experimental design, with treatment in column, position in row. For
instance, the element 20 is:
dataHP[[20]]
col1 col2
If it is precise enough for you, you can use
trim - function(x,prop=.05) {
trimx - x[x quantile(x,prob=(1-prop))]
return(trimx)
}
Petr
Jonathan Morse napsal(a):
Hi,
I am trying to restrict a data set so as not to included outliers.
Specifically, I would like to specify a percentage
In plot.tune, default color for contour plot is lightblue.
If I want to set several different colors for contour plot, How can I do this?
Thanks,
Aimin
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
Hi Josh,
Consider what follows to convert your data and estimate the models.
I am not sure however, what do you want to do after the models are
estimated, so my suggestions stop at this point.
HTH,
Michal
# -b-e-g-i-n---R---c-o-d-e-
# first i make some data that is similar to yours so i can
Aimin,
Please see color.palette in ?plot.tune.
Sorry to be a broken record, but if you want people to help you, you
should:
- read the help pages before sending an email
- run sessionInfo() and send it in the email
You run the risk of people ignoring your emails. These steps will help
Jiho.han,
I wonder if there's a way to replicate SAS rank procedure where it ranks a
variable by a certain number of groups. For example, it's very easy to
calculate quintile rank in SAS, but I couldn't find the similar function in
R.
Does anyone know how to do this?
There are some
I have installed Hmisc and Design. When I use ols, I get the
following error message:
Error in if (!length(fname) || !any(fname == zname)) { :
missing value where TRUE/FALSE needed
The model that I am running is:
ecools - ols(eco$exp ~ eco$age + eco$own + eco$inc + inc2, x=TRUE)
I
I have the model below, for which I run a logistic regression including the
interaction term (NSAID*Diuretic)
fit1=glm(resp ~ nsaid+diuretic+I(nsaid*diuretic), family= binomial,data=w)
NSAID DiureticPresent Absent
0 0 185 6527
0 1
A simple example follows. The file is called Test.R
# Example
rm(list=is(all=TRUE))
cat(Enter file name)
fn-scan(what=)
I execute the following:
@C:\PROGRA~1\R\R-2.4.1\bin\Rterm.exe --no-restore --no-save Test.R Rout.txt
I do not see the Enter file name or have the opportunity to enter the
Hi I installed package rJava but .jinit() gives an error Cannot create
Java Virtual Machine.
Currently, I am running Win XP, with JRE and JDK 1.5 installed. I am not
quite familiar with java configuation. Can anyone give some ideas on the
error mentioned above? Thanks.
- - - - - - - - - - - - - -
I think that inc2 should be eco$inc2 in your call.
If not let me know and I will dig deeper.
- Original Message -
From: Charles Evans [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Wednesday, March 14, 2007 12:48 PM
Subject: [R] ols Error : missing value where TRUE/FALSE needed
First I think you should have 'ls(' instead of 'is('. Second, your standard
input if from the Test.R file so you scan won't be reading from the
console. Here is what I got when I changed 'is' to 'ls':
/cygdrive/c/progra~1/r/r-2.4.1/bin: ./rterm --no-save c:/test.r
R version 2.4.1 (2006-12-18)
Dear R members,
I am new in using frailty models in survival analyses and am getting
some contrasting results when I compare the Wald and likelihood ratio
tests provided by the r output.
I am testing the survivorship of different sunflower interspecific
crosses using cytoplasm (Cyt),
I agree with Bert on this one! Any commercial entity's future policies will not
be decided by some group's past understanding. Everything can be explained in
terms of shareholder value.
I don't see any advantages with tying up to Google groups. We get enough posts
every day here to keep us all
Hi,I'm just wondering if there is any package for testing cointegration with
ADL model. I saw a bunch of packages and list of email thread. There seemed to
be no such a specific method. I am following this paper on how to test using
ADL but I don't have a tool.
Hi There,
I have two questions about how to understand well about the
interaction efffect.
1) Suppose two factors, A and B.
A has n levels, B has m levels.
Why the degree of freedom of interaction effect of A and B ( here I
mean A:B not A*B) is (n-1)*(m-1) not n*m-1?
2) can Lard:Gender be
I've seen how to replace the NA's in a single column with a data frame
* mydata$ncigs[is.na(mydata$ncigs)]-0
*But this is just one column... I have thousands of columns (!) that I need
to do this, and I can't figure out a way, outside of the dreaded loop, do
replace all NA's in an entire data
This should work.
test.df - data.frame(x1=c(NA,2,3,NA), x2=c(1,2,3,4),
x3=c(1,NA,NA,4))
test.df
x1 x2 x3
1 NA 1 1
2 2 2 NA
3 3 3 NA
4 NA 4 4
test.df[is.na(test.df)] - 1000
test.df
x1 x2 x3
1 1000 11
22 2 1000
33 3 1000
4 1000 44
The following search
Charles Evans wrote:
I have installed Hmisc and Design. When I use ols, I get the
following error message:
Error in if (!length(fname) || !any(fname == zname)) { :
missing value where TRUE/FALSE needed
The model that I am running is:
ecools - ols(eco$exp ~ eco$age + eco$own
Dear Friends,
I saved a matrix - which contans values 0 and 1 - using following command:
writeBin (as.integer(mymatrix), myfile.raw, size=1).
It is working fine and I can see the matrix using photoshop. But now I need
read the matrices again (in fact I have a thousand of them) as matrix into R
On Wed, 14 Mar 2007 18:45:53 -0700 (PDT) Milton Cezar Ribeiro [EMAIL
PROTECTED] wrote:
Dear Friends,
I saved a matrix - which contans values 0 and 1 - using following command:
writeBin (as.integer(mymatrix), myfile.raw, size=1).
It is working fine and I can see the matrix using
Since you can index a matrix or dataframe with
a matrix of logicals, you can use is.na()
to index all the NA locations and replace them
all with 0 in one command.
mydata.df - as.data.frame(matrix(sample(c(as.numeric(NA), 1), size = 30,
replace = TRUE), nrow = 6))
mydata.df
V1 V2 V3 V4 V5
1
On Wed, 14 Mar 2007 10:39:43 -0500,
Kevin R Coombes (KRC) wrote:
Hi,
I don't know of a standard way to indicate this; I would have suggested
combined,expand=FALSE
(with expand=TRUE the default), except for the fact that Seth Falcon
already suggested the same notation in his
Hi,
Thanks so much in advance for your help!
I just started using 'timeDate' object to manipulate daily time
series data. After reading some documents, I created an object
'bizday' to do some business-day computation. E.g.
bizday = timeSequence
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