#DEFININING AN EMPTY VECTOR TO HOLD ZK VALUES
> for(x in 1:nrow(xk)) {
> k <- intersect(i1[x,], i2[x,])
> zk[x] <- mean(unlist(k), na.rm = TRUE)
> }
> xk$zk <- zk
> data <- na.omit(xk)
--
Andris Jankevics
Assistant
Department of Medicina
this:
1 2 3 4 5 6 7 8 9 10
1 0 3 0 5 0 7 0 9 0
How can I do this in R?
Thank you.
--
Andris Jankevics
Assistant
Department of Medicinal Chemistry
Latvian Institute of Organic Synthesis
Aizkraukles 21, LV-1006, Riga, Latvia
__
R-help@stat.math.ethz
major 2
minor 4.1
year 2006
month 12
day18
svn rev40228
lan
[1] "$\\Delta$"
Gives a latex aoutput like: \$$\backslash$Delta\$
Thank You in advance
Andris Jankevics
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://ww
If you want get a username of user currently running R on Linux,you can use a
system command and read enviroment variables:
paste("/home/",system ("whoami",intern=TRUE),sep="")
Andris Jankevics
On Piektdiena, 23. Marts 2007 14:30, Alberto Monteiro wrote:
> I
Hi,
You can take a look at GNU screen programm:
http://www.gnu.org/software/screen/
Andris Jankevics
On Pirmdiena, 19. Februāris 2007 15:56, Nils Höller wrote:
> Hi,
>
> I have some big calculations in R to be done.
> Since I can use R on a server with ssh, i was wondering if I can
Hi,
I wrote some simple rpanel package script for visual spectral data comparison.
At this example i have a three samples and i want to zoom through x and y
axis to compare differences between samples. With my script below I can zoom
to some data region and add some other spetra to the plot, th
t;S3","S4","S5")
I want to normalize all samples to same sum of variables:
NormFun <- function (i) {(i*(1/sum(i)))}
Dnorm <- apply(DATA,1,NormFun)
Why I am getting tranposed matrix Dnorm? And with my experimental data (with
32k variables) i am getting a slighty diffe
- (IrisPC1+IrisPC2),3)
EPC3 <- round(Data - (IrisPC1+IrisPC2+IrisPC3),3)
EPC4 <- round(Data - (IrisPC1+IrisPC2+IrisPC3+IrisPC4),3)# 0
Andris Jankevics
On Piektdiena, 10. Novembris 2006 05:58, Renaud Lancelot wrote:
> See ?rconst in package ade4. You will need to fit the PCA with
> dudi.p
Hello,
You can try to merge network$wieght in the data frame, and the plot a first
row from it.
DataF <- do.call (rbind,network$weight)
Andris
On Ceturtdiena, 2. Novembris 2006 12:53, Wee-Jin Goh wrote:
> Hello,
>
> I know this must be a very simple problem, but I can't work it out
> from th
Also you can take a look on Partial Least Squares (PLS) regression.
http://www.statsoft.com/textbook/stpls.html
R-package: http://mevik.net/work/software/pls.html
Andris Jankevics
On Sestdiena, 28. Oktobris 2006 06:04, Ritwik Sinha wrote:
> You can use gee (
> http://finzi.psych.upenn
(DATAY) <- c("respone_1","response_2")
KAL <- data.frame (N = rownames(DATAX))
KAL$Y <- DATAY
KAL$X <- DATAX
KAL$X
KAL$Y
DATAX is a matrix of testing data, but DATAY is a matrix of responses.
Andris Jankevics
On Pirmdiena, 31. Jūlijs 2006 05:45, [EMAIL PROTECTED]
This should work:
data[seq(1,nrow(data),10),]
Andris
On Piektdiena, 30. Jūnijs 2006 14:45, yohannes alazar wrote:
> Dear mailing list I have a data that have 20,000 rows and 20 columns. Io
> wonted to extract the 10th row only. Example the 10th, 20th, 30th
> 40th�..2 th. can you please hel
5
But how can I find a break points for vector with random values and random
number sequence intervals? Why result for interval (1,2) is 4, if there is
only 3 values of "1"?
Can I get from vector Z a smal vector Zs 1,2,3,4,5 ?
Thanks a lot
I am sorry. It was my fault. My example is wrong. I need also rearrange a
validation data set too.
But I have a sligthy different results with my real data. Where can the
problem be?
Andris Jankevics
On Otrdiena, 18. Aprīlis 2006 17:55, Andris Jankevics wrote:
> Hello useRs,
>
> I am
0.1)
VAL <- data.frame(num=c(1:10))
VAL$X <- as.matrix(cbind(X1v,X2v,X3v,X4v,X5v))
predict (PLS,VAL,4)
predict (PLS2,VAL,4)
Thank You,
Andris Jankevics
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RED[,2]
Y1x <- Y1 - PRED[,1]
SSEY1 <- sum(Y1x[1:length(V[,2])]^2)
SSEY2 <- sum(Y2x[1:length(V[,2])]^2)
RES <- data.frame (Vars = structure(dimnames(as.matrix(D))[2],dim
=1),SSEY1 =
SSEY1, SSEY2 = SSEY2)
print (RES) }
lapply (1:(length(Z)-1),
Hello useRs,
I can't figure out how can I store a data frame of values of X and D from
this loop:
Z <- c(1:10)
for (i in 1:(length(Z)-2))
{D <- x[1:(2+i)];
X <- paste("x",sep="",i)
print (X)
print (D)
You have to install Xserver (x.org or XFree86) devel packages before
compiling.
On Piektdiena, 10. Marts 2006 17:31, M Senthil Kumar wrote:
> Hello there,
>
> I had been learning to use R for some time and I am trying to install it
> on Ubuntu 5.04 Linux. I downloaded the tarball, there was some
In my opinion line in /etc/apt/sources.lst shoud be similar like this:
deb http://cran.r-project.org/bin/linux/debian/stable ./
On Trešdiena, 1. Marts 2006 10:13, Florence Débarre wrote:
> On Mer 1 mars 2006 8:58, Prof Brian Ripley a écrit :
> > Maybe you need to spell cran.R-project.org in Engli
Hello,
As a root users type a command like this:
rpm -iU R-2.2.1-1.rh4AS.i686.rpm
On Pirmdiena, 27. Februāris 2006 08:02, Erin Hodgess wrote:
> Dear R People:
>
> I downloaded the RPM for Red Hat Linux.
>
> How do I install this, please? When I looked
> at the R Intallation manual, it seemed to
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