Please, is there any R-list about survival package ?
Thanks
Mauricio
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Is it possible to make disappear the id numbers from scatter.dudi (mc
analysis) ?
a - as.factor(c(1, 2, 3, 2, 1))
b - as.factor(c(3, 2, 3, 1, 1))
x - as.factor(c(1, 2, 2, 1, 3))
y - as.factor(c(2, 2, 3, 1, 1))
dat - data.frame(a=a, b=b,x=x,y=y)
summary(dat)
dat
require(ade4)
dat.acm -
Hi ! Wonder if I have this code below:
a - c(1, 2, 3, 2, 1)
b - c(3, 2, 3, 1, 1)
d -as.factor(a)
e -as.factor(b)
table(d,e)
is.factor(a)
is.factor(b)
is.factor(d)
is.factor(e)
de - factor(c(d,e))
is.factor(de)
require(MASS)
mca(de)
I'd like to perform a correspondence analysis, but I can't
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
Hi everone !
I know its not a epidemiologic or statistic list, but since I´m using R
to solve related problems ... here it goes:
This is a code to solve the rate problem, but the real question is:
what´s the correct way to calculate the period rate (3 years period put
together)
The third
Hi
Does anyone know where is the package: npmc (Nonparametric Multiple
Comparisons).
I found the reference on R Site Search, but not the package itself on
CRAN as suggested.
Thanks
Mauricio
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R-help@stat.math.ethz.ch mailing list
So, is there another package to substitute those functions described on
ORPHANED npmc package ?
Regards,
Mauricio
Brazil
Uwe Ligges escreveu:
Carlos Mauricio Cardeal Mendes wrote:
Hi
Does anyone know where is the package: npmc (Nonparametric Multiple
Comparisons).
I found
Ok Petr, I run your suggestion and I got this message:
age-sample(seq(10,50,10), 20, replace=T)
if (age =10) {group - 1} else if (age 10 age = 20) {group -
2} else {group - 3}
Warning message:
the condition has length 1 and only the first element will be used in:
if (age = 10) {
What
Hello reid ! About your third explanation, could you please write the
complete code including that option: a loop ?
Forgiveme, I'm trying to learn R and my mind is full of other
statistical program syntax. And I'd like very very much to improve my
knowledge using R and maybe contribute to
Hello.
I asked before and it was great, cause as a beginner I learned a lot. But, if I have
this in R (1 and 2 are codes for sex):
sex-c(1,2,2,1,1,2,2,2)
sex
[1] 1 2 2 1 1 2 2 2
I´d like to obtain the proportion according to sex.So I type:
prop.table(sex)
[1] 0.07692308 0.15384615
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