:25 AM
To
Gabor Grothendieck <[EMAIL PROTECTED]>
cc
Jesse Albert Canchola <[EMAIL PROTECTED]>,
r-help@stat.math.ethz.ch
Subject
Re: [R] Rgui.exe fix for "console not found" buffer overflow problem
On 10/29/2006 9:55 AM, Gabor Grothendieck wrote:
> On 10/29/06, Gabor Grot
I'm using R on Windows XP Professional SP2.
I figured out the fix for my buffer overflow problem that did not allow me
to use Rgui.exe for about two weeks. I would keep getting "console not
found" and even when I uninstalled and re-installed got the same problem.
Here's how the problem start
My apologies, I forgot to CC: to the list on my previous communication
with Daniel.
Jesse
- Forwarded by Jesse Albert Canchola/EMVL/DIAG/US/BAYER on 08/21/2006
10:50 AM -
Jesse Albert Canchola/EMVL/DIAG/US/BAYER
08/21/2006 09:36 AM
To
"Daniel Nordlund" <[EMAIL PROTECTED]
lt;[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
08/18/2006 05:16 PM
To
"'Jesse Albert Canchola'" <[EMAIL PROTECTED]>, "'r-help'"
cc
Subject
Re: [R] Permutations with replacement
> -Original Message-----
> From: [EMAIL PROTECTED]
[ma
For the larger one I want (i.e., 8^8), I will take a random sample of
10,000 from the 16,777,216 possibilities.
Regards,
Jesse Canchola
<[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
08/18/2006 01:33 PM
To
"Jesse Albert Canchola" <[EMAIL PROTECTED]>, "r-help"
Is there a simple function or process that will create a matrix of
permutations with replacement?
I know that using the combinat package
## begin R code ##
> library(combinat)
> m <- t(array(unlist(permn(3)), dim = c(3, 6)))
# we can get the permutations, for example 3!=6
# gives us
>
Is there a simple function or process that will create permutations with
replacement?
I know that using the combinat package
## begin R code ##
> library(combinat)
> m <- t(array(unlist(permn(3)), dim = c(3, 6)))
# we can get the permutations, for example 3!=6
# gives us
> m
[,1]
Thanks, Gabor. Since the data stacking components are independent, that
didn't matter much but I am grateful for your follow-up code to match the
desired output specifically.
Regards,
Jesse
"Gabor Grothendieck" <[EMAIL PROTECTED]>
07/18/2006 10:36 AM
To
"Jess
Many thanks, Gabor. That worked great! I'm ecstatic.
Best regards,
Jesse
"Gabor Grothendieck" <[EMAIL PROTECTED]>
07/18/2006 10:12 AM
To
"Jesse Albert Canchola" <[EMAIL PROTECTED]>
cc
r-help@stat.math.ethz.ch
Subject
Re: [R] Reconfiguring wide frame
Greetings, fellow R'ers.
How can I get this frame in R:
ID meas ID.1 meas.1
1 1.13 1.2
2 2.14 2.2
to look like this (stacking):
ID meas
1 1.1
2 2.1
3 1.2
4 2.2
It's not really the reshape function (or is it?) because we can consider
the additional colum
Great. I will work on the problem with those definitions in mind. Thanks
for your help, Gabor. I'll post the final solution when it is ready.
Best,
Jesse
"Gabor Grothendieck" <[EMAIL PROTECTED]>
07/14/2006 11:59 AM
To
"Jesse Albert Canchola"
ODE
DF <- rbind(a,b,c)
DF
for(index in as.data.frame(combn(3,2))) print(DF[,index])
END CODE
Regards,
Jesse
"Gabor Grothendieck" <[EMAIL PROTECTED]>
07/14/2006 11:01 AM
To
"Jesse Albert Canchola" <[EMAIL PROTECTED]>
cc
r-help@stat.math.e
he same length: a, b and c
how do we loop over pairs of them. In the following each iteration
displays
one pair:
library(combinat)
DF <- data.frame(a = 1:4, b = 5:8, c = 9:12)
for(idx in as.data.frame(combn(3,2))) print(DF[,idx])
On 7/13/06, Jesse Albert Canchola <[EMAIL PROTECTED]&
I have a problem where I need to loop over the total combinations of
vectors (combined once chosen via combinatorics). Here is a
simplification of the problem:
STEP 1: Define three vectors a, b, c.
STEP 2: Combine all possible pairwise vectors (i.e., 3 choose 2 = 3
possible pairs of vectors:
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