On Tue, 2006-05-16 at 14:37 -0400, Guenther, Cameron wrote:
Hello everyone,
I have a large dataset (x) with some rows that have duplicate variables
that I would like to remove. I find which rows are the duplicates with
X1-which(duplicated(x)). That gives me the rows with duplicated
On Tue, 2006-05-16 at 14:54 -0400, Guenther, Cameron wrote:
Marc,
I have tried unique but unique looks at the entire row.
Right, as I noted in the last line of my reply.
I have a data
set with a variable TRIPID. The dataset has 469,000 rows. In most
cases TRIPID is a unique value.
On Tue, 2006-05-16 at 17:49 -0300, Rolf Turner wrote:
Duncan Murdoch wrote (amongst other things):
Statistical computing is not easy, so how could R be? Who has ever
claimed it is? Any package that makes statistical computing appear to
be easy is probably giving you wrong answers half
On Fri, 2006-05-12 at 11:41 -0500, Nameeta Lobo wrote:
Hello all again,
I want to do bitwise addition in R. I am trying to generate a matrix
0001
0010
I know the other ways of generating this matrix but I need to look at bitwise
addition.
Any suggestions???
On Fri, 2006-05-12 at 14:05 -0500, Marc Schwartz (via MN) wrote:
On Fri, 2006-05-12 at 11:41 -0500, Nameeta Lobo wrote:
Hello all again,
I want to do bitwise addition in R. I am trying to generate a matrix
0001
0010
I know the other ways
A search for the list2ascii() function, led me to this post by Mike
Prager:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/66335.html
in which Mike specifically notes:
To write it to a file that can be read by R, I would suggest using
dput instead.
Thus, instead of using list2ascii() on
On Wed, 2006-05-10 at 13:19 -0500, Marc Schwartz (via MN) wrote:
A search for the list2ascii() function, led me to this post by Mike
Prager:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/66335.html
in which Mike specifically notes:
To write it to a file that can be read by R, I would
On Tue, 2006-05-09 at 16:50 +0100, Filipe Almeida wrote:
Hi,
I want to remove all punctuation characters in a string. I was trying it use
a regular expressions but it doesn't work.
Here is a sample os what i want:
str - 'ABD - remove de punct, and dot characters.'
str -
On Tue, 2006-05-09 at 15:35 -0500, Robert Citek wrote:
On May 5, 2006, at 11:54 AM, Marc Schwartz (via MN) wrote:
Robert Citek wrote:
$ uname -sorv ; rpm -q R ; R --version
Linux 2.6.11-1.1369_FC4smp #1 SMP Thu Jun 2 23:08:39 EDT 2005 GNU/
Linux
snip
On Mon, 2006-05-08 at 16:32 -0500, Nameeta Lobo wrote:
Hello all,
I am trying to create a matrix of 1s and -1s without any repetitions for a
specified number of columns.
e.g. 1s and -1s for 3 columns can be done uniquely in 2^3 ways.
-1 -1 -1
-1 -1 1
-1 1 -1
-1 1 1
1 -1 -1
1 -1
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Marc
Schwartz (via MN)
Sent: Monday, May 08, 2006 2:50 PM
To: Nameeta Lobo
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Non repetitive permutations/combinations of elements
On Mon, 2006-05-08 at 16
On Fri, 2006-05-05 at 17:56 +0200, Uwe Ligges wrote:
Robert Citek wrote:
Why am I getting the error Error: cannot allocate vector of size
512000 Kb on a machine with 6 GB of RAM?
1. The message means that you cannot allocate *further* 512Mb of RAM
right now for the next step, but not
On Wed, 2006-05-03 at 10:46 -0400, Farrel Buchinsky wrote:
How does one create a vector whose contents is the list of variables in a
dataframe pertaining to a particular pattern?
This is so simple but I cannot find a straightforward answer.
I want to be able to pass the contents of that list
On Tue, 2006-05-02 at 17:21 +0200, Albert Sorribas wrote:
Library gmodels include a function CrossTable that is useful for
crosstabulation. In the help, it is indicated that one can call this
function as CrossTable(data), were data is a matrix. However, when I try
to use this option, it
On Mon, 2006-05-01 at 17:21 -0400, Brian Quinif wrote:
Forgive my ignorance, but how I can take a look at the code for the
latex function in the Hmisc library?
I tried just typing latex but all I got was this:
latex
function (object, title = first.word(deparse(substitute(object))),
On Fri, 2006-04-28 at 11:17 -0700, Sachin J wrote:
Hi,
I am trying to use rm.outlier method but encountering following error:
y - rnorm(100)
rm.outlier(y)
Error:
Error in if (nrow(x) != ncol(x)) stop(x must be a square matrix) :
argument is of length
why I am unable to understand the cause of error. Any
further thoughts? I will take a look at the robust analytic methods as
suggested.
Thanx
Sachin
Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:
On Fri, 2006-04-28 at 11:17 -0700, Sachin J wrote:
Hi
On Thu, 2006-04-27 at 08:43 -0400, John Kane wrote:
I have a simple barplot that looks fine in the R
graphics device window. However when I export it to
png I am losing the x-label. It must be an obvious
problem but I cannot see it. Trying to resize the plot
does not seem to help. Code is
On Wed, 2006-04-26 at 18:13 +0100, Florian Nigsch wrote:
[Please CC me for all replies, since I am not currently subscribed to
the list.]
Hi all,
I have the following problem/question: Imagine you have a two-
dimensional plot, and you want to select a number of points, around
which
On Wed, 2006-04-26 at 11:05 -0700, John McHenry wrote:
Does anyone know where the code for the graphics on:
http://www.r-project.org/screenshots/screenshots.html
lives?
demo(graphics)
demo(image)
demo(persp)
These should cover each of the screen shots and then some.
If
to work with Exceed.
Also I haven't checked any docs to see whether this is a known problem but
suspect that Marc could be surprised by the behavior.
Clint
On Wed, 26 Apr 2006, Roger Bivand wrote:
On Wed, 26 Apr 2006, Marc Schwartz (via MN) wrote:
On Wed, 2006-04-26 at 18:13 +0100, Florian
On Tue, 2006-04-25 at 11:07 -0400, Chuck Cleland wrote:
I am attempting to produce crosstabulations between two variables for
subgroups defined by a third factor variable. I'm using by() and
CrossTable() in package gmodels. I get the printing of the tables first
and then a printing of
=TRUE
On 4/25/06, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:
On Tue, 2006-04-25 at 11:07 -0400, Chuck Cleland wrote:
I am attempting to produce crosstabulations between two variables for
subgroups defined by a third factor variable. I'm using by() and
CrossTable
On Mon, 2006-04-24 at 16:31 -0400, Doran, Harold wrote:
I have what I'm sure will turn out to be straightforward. I want to
store the results of a loop for some operations from a patterned vector.
For example, the following doesn't give what I would hope for
ss - c(2,3,9)
results -
On Fri, 2006-04-21 at 07:37 -0700, Thomas Lumley wrote:
On Fri, 21 Apr 2006, Federico Calboli wrote:
Hi All,
I am (almost) successfully using apply() to apply a function recursively
on a data matrix. The function is question is as.genotype() from the
library 'genetics'
On Thu, 2006-04-20 at 11:46 -0700, Sachin J wrote:
Hi,
How can I accomplish this in R. Example:
R1 R2
3 101
4 102
3 102
18102
11101
I want to find Sum(101) = 14 - i.e SUM(R1) where R2 = 101
Sum(102) = 25- SUM(R2)
On Wed, 2006-04-19 at 17:02 +0200, Paul wrote:
Dear R-helpers,
I am dealing with an Oracle database (using package RODBC). I use
R in order to transform some Oracle tables into .txt files (using
function sqlFetch from package RODBC and then function write.table).
However, I cannot do
On Wed, 2006-04-19 at 16:39 +0200, Fredrik Karlsson wrote:
Dear list,
I am trying to create a three-way table with percent occurrence
instead of raw frequencies. However, I cannot get the results I
expected:
I have the following table:
ftable(table( mannerDF$agem, mannerDF$target,
On Wed, 2006-04-19 at 17:14 +0100, Prof Brian Ripley wrote:
On Wed, 19 Apr 2006, Marc Schwartz (via MN) wrote:
On Wed, 2006-04-19 at 17:02 +0200, Paul wrote:
Dear R-helpers,
I am dealing with an Oracle database (using package RODBC). I use
R in order to transform some Oracle
On Wed, 2006-04-19 at 15:25 -0400, Doran, Harold wrote:
Dear List
I apologize for the multiple postings. After being in the weeds on this
problem for a while I think my original post may have been a little
cryptic. I think I can be clearer. Essentially, I need the following
a - c(2,3)
b
On Tue, 2006-04-18 at 16:40 +0300, Antti Arppe wrote:
Dear colleagues in R,
Has anybody implemented the
1) (Goodman Kruskal) lambda
or the
2) (Thiel's) uncertainty coefficient
statistics (in the asymmetric and symmetric forms), or is anyone aware
that they might reside in some
On Tue, 2006-04-18 at 10:30 -0500, Marc Schwartz (via MN) wrote:
On Tue, 2006-04-18 at 16:40 +0300, Antti Arppe wrote:
Dear colleagues in R,
Has anybody implemented the
1) (Goodman Kruskal) lambda
or the
2) (Thiel's) uncertainty coefficient
statistics
On Tue, 2006-04-18 at 17:52 +0200, Daniele Medri wrote:
Dear R-users,
i need to store in a variable a string made from levels of a factor
e.g.
a-(a,a,b,b)
The above should be:
a - c(a,a,b,b)
^
af-factor(a)
mylevels- ...a string with all the levels(af)
Thanks
--
DM
On Tue, 2006-04-18 at 18:07 +0200, Daniele Medri wrote:
Il giorno mar, 18/04/2006 alle 11.00 -0500, Marc Schwartz (via MN):
mylevels- ...a string with all the levels(af)
mylevels - levels(af)
mylevels
[1] a b
I don't need to store these two levels, but a string with the values
On Tue, 2006-04-18 at 20:53 +0200, Daniele Medri wrote:
Il giorno mar, 18/04/2006 alle 11.29 -0500, Marc Schwartz (via MN):
paste(levels(af), collapse = )
[1] ab
See ?paste.
:) more simple: toString(levels(x))
Thanks,
Cheers
--
DM
Actually, you don't quite get the same
On Mon, 2006-04-17 at 10:17 -0400, Gong, Yanyan wrote:
Hi, I am trying to runn a age-period-cohort model, but here is what I am
having problem with, hope you can help me!
This is what I am trying to do:
sumzero_a-((A-min(A))/5+1) - mean((A-min(A))/5+1) where A is my age
variable (numeric,
On Thu, 2006-04-13 at 15:11 -0500, Chad Reyhan Bhatti wrote:
Hello,
I have been looking for a way to print output to a file from the command
line. I have looked at write(), dump(), dput(), etc and none of these
seem to have the capability I am needing. Imagine that you have the
output of
On Thu, 2006-04-13 at 16:28 -0400, Gong, Yanyan wrote:
Hi,
I am a new user of R, I am trying to read my data in.. Cervixhc.dat used
to be in a different directory, now it has been moved to O:\Es\APC cervix
FINAL (YG,MC,MD)\Manuscript\Data, but when I ran the following program (in
red) I got
On Thu, 2006-04-13 at 15:04 -0500, Chad Reyhan Bhatti wrote:
Hello,
I am creating a number of objects that I wish to have a common name with
an index such as x1, x2, x3, ... I would like to do everyting in a loop to
make the code compact and minimize the probability of an error by typo.
A
On Sat, 2006-04-01 at 06:45 +1000, Bob Green wrote:
I have been trying for a year to get approval to install R on a work
computer and am not optimistic of a positive reply in the near future. I
was considering whether an option might be to run R from a CD/USB stick. I
looked through the
On Fri, 2006-03-31 at 22:26 +0100, Prof Brian Ripley wrote:
On Fri, 31 Mar 2006, Marc Schwartz (via MN) wrote:
On Sat, 2006-04-01 at 06:45 +1000, Bob Green wrote:
I have been trying for a year to get approval to install R on a work
computer and am not optimistic of a positive reply
On Fri, 2006-03-24 at 15:29 -0500, Dan Chan wrote:
Hi,
I have a dataframe with many columns, including date and I want to keep
only a few of the columns including date column.
I used the following command:
with(FireDataAppling, cbind(STARTDATE, County, TOTAL, CAUSE)
It works, but the
On Tue, 2006-03-21 at 14:26 -0500, mark salsburg wrote:
I am getting an error message, which I do not know the source to.
I have a matrix SAMPLES that has preexisting rownames that I would like to
change.
SAMPLES is not a matrix, it is a data frame, as your output shows below.
GENE_NAMES
On Mon, 2006-03-20 at 17:33 -0500, [EMAIL PROTECTED] wrote:
Hi,
This is a very fundamental question. I want to export graphical results
so that I can place them in an openoffice document.
I use Fedora 5.
That was quick... ;-)
The best way to do this under Linux is to use the R
On Wed, 2006-03-15 at 06:03 -0500, tom wright wrote:
Can someone please give me a pointer here.
I have two matrices
matA
A B C
1 5 2 4
2 2 4 3
3 1 2 4
matB
A B C
1 TRUEFALSE TRUE
2
On Wed, 2006-03-15 at 17:54 +0100, jia ding wrote:
Hi,
I have a file named:
test_R.txt
aaa 2
bbb 5
ccc 7
sss 3
xxx 8
I want to have a plot:
test-read.table(test_R.txt,col.name=c(Name,Score))
par(mfrow=c(1,2))
It's not clear what the purpose is here, at least in this example.
On Wed, 2006-03-15 at 11:32 -0800, Fred J. wrote:
Hi
Is there a function which determines the location, i.e., index of
the all minimums or maximums of a numeric vector.
Which.min(x) only finds the (first) of such.
x - c(1:4,0:5, 4, 11)
x
[1] 1 2 3 4 0 1 2 3
On Wed, 2006-03-15 at 21:45 +0100, Philippe Grosjean wrote:
What Fred is looking for is local minima/maxima, also known as turning
points, or pits/peaks in a series. You can look at ?turnpoints in
pastecs library.
x - c(1:4,0:5, 4, 11)
x
[1] 1 2 3 4 0 1 2 3 4 5 4 11
On Tue, 2006-03-14 at 18:45 +0100, Arnau Mir wrote:
Hello.
I have a vector of length 2771 but it has only 87 different values.
How can I obtain them?
Thanks,
Arnau.
If you just want the unique values themselves, you can use:
unique(vector)
For example:
v
[1] b b c a a a c c c c
On Tue, 2006-03-14 at 14:07 -0500, Sean Davis wrote:
Does anyone know of an implementation in R of the Hodges-Lehmann
nonparametric difference between two groups? I am interested in the
estimate of the difference and the CI or significance of that difference. I
did some quick searching and
On Wed, 2006-03-08 at 14:02 -0500, Jamieson Cobleigh wrote:
I have a barplot I have created using barplot2 and I have been able to
add points and lines (using the points and lines methods,
respectively). I now need to add some polygons (triangles in
particular), that I want to be shaded to
On Wed, 2006-03-08 at 16:53 -0500, Lisa Wang wrote:
Hello there,
I would like to plot a graph with the x axis's label displayed at a 45
angle to the x axis instead of horizontal to it as the label is very
long. What should I do?
Thank you for your help in advance
See R FAQ 7.27 How can
On Mon, 2006-03-06 at 15:40 +0100, Roland Kaiser wrote:
How can i set a rotation for the names.arg in barplot?
See R FAQ 7.27 How can I create rotated axis labels?:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f
That provides the basic concept, which
On Mon, 2006-03-06 at 15:10 -0800, Michael wrote:
Hi all,
I want to substract vector B from A's each column... how can R do that
smartly without a loop?
A=matrix(c(2:7), 2, 3)
A
[,1] [,2] [,3]
[1,]246
[2,]357
B=matrix(c(1, 2), 2, 1)
B
[,1]
[1,]
On Wed, 2006-03-01 at 12:01 -0500, Jamieson Cobleigh wrote:
I'm using barplot2 to plot some data. Is there any way to determine
the width of the bars in the generated plot? I know that barplot2
returns a list of the coordinates of the center of each bar, but since
there is some white space
On Tue, 2006-02-28 at 17:14 +, Federico Calboli wrote:
Hi All,
I have a list of matrices:
x
[,1] [,2]
[1,]14
[2,]25
[3,]36
y
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 18 21 24 27 30 33
[2,] 19 22 25 28 31 34
[3,] 20 23
On Tue, 2006-02-28 at 16:10 -0600, Erin Hodgess wrote:
Dear R People:
When using the jpeg function for plotting,
is there a way to set the size in inches, please?
There is an option for width and height in pixels, but
not inches.
Any suggestions would be welcome!
The problem is
On Fri, 2006-02-24 at 08:18 -0800, Matt Crawford wrote:
I am having trouble doing the following. I have a data.frame like
this, where x and y are a variable that I want to do calculations on:
Name Year x y
ab 2001 15 3
ab 2001 10 2
ab 2002 12 8
ab 2003 7 10
dv 2002 10 15
On Fri, 2006-02-24 at 12:54 -0600, mtb954 mtb954 wrote:
I'm trying to sort a DATAFRAME by a column ID that contains
alphanumeric data. Specifically,ID contains integers all preceeded
by the character g as in:
g1, g6, g3, g19, g100, g2, g39
I am using the following code:
On Thu, 2006-02-23 at 15:35 +, michael watson (IAH-C) wrote:
Hi
Hopefully this one isn't in the manual or I am about to get shot :-S
Bang ;-)
One of my colleagues wants a slightly strange graph. We basically have
a data matrix, and she wants to plot, for each row, the values in the
On Wed, 2006-02-22 at 14:31 +0100, jia ding wrote:
Hello,
I have a very simple question about 2 barplots in the same graph.
It seems quite easy, but I searched google for long time, haven't find
solution.
For example, I want one graph like:
x1=seq(0,2,by=0.3)
x2=seq(3,0,by=-0.1)
On Wed, 2006-02-22 at 11:57 -0500, Kevin E. Thorpe wrote:
Thank you Spencer and Steve for your helpful comments. If I may, I
would like to elaborate on some of the points you raise.
Kevin,
I am not sure if you received any offlist replies to your post. Given
the subject matter, I had
On Mon, 2006-02-20 at 20:27 +, Alex Park wrote:
R helpers
I am getting to grips with R but came across a small problem today that I
could not fix by myself.
I have 3 text files, each with a single column of data. I read them in
using:
myData1-scan(C:/Program Files/R/myData1.txt)
In follow up to Harold's thought of using LaTeX, I have an approach when
the use of nicely formatted tables is required in a document where LaTeX
is not being used for the entire document. In other words, where you
need to use Word, OO.org's Writer or similar application for the
majority of the
On Thu, 2006-02-09 at 17:18 +0100, Thomas Steiner wrote:
I want to write some text in a corner of my plot.
Is it possible to get the xlim and ylim of an open window?
Or is there anything similar like
legend(x=bottomright, inset=0.01,legend=...)
for
text(x=1,y=2, test)
Thomas
Try this:
There is some documentation online at:
http://www.latex-project.org/guides/
which would be a good starting place.
If you prefer a good book, The LaTeX Companion (aka TLC) is the place to
begin:
http://www.amazon.com/gp/product/0201362996
There is also a boxed set (expensive) of several books
On Fri, 2006-02-03 at 10:41 -0500, tom wright wrote:
Please excuse the lack of a complete dataset here, if its needed I'll be
happy to provide it.
Can anyone show me how to rewrite this?
Browse[1] time(data)[24210:24220]
[1] 24.209 24.210 24.211 24.212 24.213 24.214 24.215 24.216 24.217
On Wed, 2006-02-01 at 12:16 -0800, array chip wrote:
Does anyone know how I can generate a 2x2 table in a
format where in each cell of the table, it contains a)
count (frequency) b) total percentage c) row
percentage d) column percentage. SAS can generate this
format easily, is there a R
On Wed, 2006-02-01 at 17:10 -0500, Vivek Satsangi wrote:
This one is an easy question. I am looking for the idiomatic way to do it.
I have two large data frames. I want to merge them. What is the
idiomatic way to say match the rows from dataframe 1 to the rows in
dataframe2 which have the
Perhaps you guys should try to benchmark that test on an nVidia GPU?
;-)
Best regards,
Marc
On Thu, 2006-01-26 at 15:55 +0100, Uwe Ligges wrote:
Philippe Grosjean wrote:
Excellent, but...
x - rnorm(100)
y - rnorm(100)
system.time(x%*%y)
[1] 0.03 0.00 0.03 NA
On Wed, 2006-01-25 at 09:50 -0500, Farrel Buchinsky wrote:
Power calculations two sample test for proportions is very useful. Is there
a way however, to get away from the two samples being of the same size. What
would happen if one had n=15 in the one sample and n=45 in the other sample.
See
On Mon, 2006-01-23 at 10:52 -0800, Thomas Lumley wrote:
On Mon, 23 Jan 2006, Linda Lei wrote:
Thank you guys.
But I tried the commands and I still get:
aml1-aml[aml$group==1,]
aml1
[1] time status x
0 rows (or 0-length row.names)
esf.fit - survfit(Surv(aml1$weeks,status) ~ 1)
On Fri, 2006-01-20 at 18:55 +0100, Michael Reinecke wrote:
Hi! I suspect there must be an easy way to access components of a data
frame by name, i.e. the input should look like name1 name2 name3 ...
and the output be a data frame of those components with the
corresponding names. I ve been
One of the distinct advantages of using subset() with a large number of
columns is that given it's support for standard vector indexing in the
'select' argument, you can do something like:
subset(dframe, select = c(name1, name5:name235, name437))
Here, by using the syntax name5:name235, you
On Wed, 2006-01-18 at 17:09 +0100, Knut Krueger wrote:
Marc Schwartz schrieb:
On Wed, 2006-01-18 at 13:04 +0100, Knut Krueger wrote:
One of the first things to do is to use 'onefile = FALSE', 'horizontal =
FALSE' and paper = special'.
I am afraid the problem is on the journals
On Wed, 2006-01-18 at 20:48 +0100, Knut Krueger wrote:
Marc Schwartz (via MN) schrieb:
Unfortunately, it may have precluded my being able to replicate exactly
what you are seeing, despite being intimately familiar with one of the
functions (barplot2 ;-) that you are using.
I did
On Thu, 2005-12-29 at 17:20 +0100, Florent Bresson wrote:
I'm dealing with a matrix like :
x y z
[1,] 24 1
[2,] 61 2
...
[n,] 73 1
For each row I would like to know the header of the
column which corresponds to the minimum value. In the
case of my
On Thu, 2005-12-29 at 22:06 +0100, Martin Maechler wrote:
Marc == Marc Schwartz (via MN) [EMAIL PROTECTED]
on Wed, 28 Dec 2005 15:46:37 -0600 writes:
Marc On Wed, 2005-12-28 at 20:15 +,
Marc [EMAIL PROTECTED] wrote:
Dear All,
Apologies for this simple
On Wed, 2005-12-28 at 20:15 +, [EMAIL PROTECTED] wrote:
Dear All,
Apologies for this simple question and thanks in advance for any help
given.
Suppose I wanted to plot 1 million observations and produce the
command
plot(rnorm(100))
The labels of the xaxis are 0, e+00 2 e+05
On Tue, 2005-12-27 at 16:16 -0600, Erin Hodgess wrote:
Dear R People:
Please excuse the off topic question.
What are the dimensions of A-4 Paper, please?
Actually, the question should read, how do I set up a LaTex file
to fix A-4 paper, please?
Thanks much!
Set the documentclass in
On Thu, 2005-12-22 at 16:58 +0100, Albert Vilella wrote:
Hi all,
I would like to factorize the entries in a dataframe given some
groupings. E.g:
mydf = data.frame(
a = rnorm(100,10),
b = rnorm(100,10),
c = rgamma(100, 1, scale=1))
group = hist(mydf$c, breaks=FD)
group$breaks
On Thu, 2005-12-22 at 10:08 -0600, Marc Schwartz (via MN) wrote:
On Thu, 2005-12-22 at 16:58 +0100, Albert Vilella wrote:
Hi all,
I would like to factorize the entries in a dataframe given some
groupings. E.g:
mydf = data.frame(
a = rnorm(100,10),
b = rnorm(100,10),
c
On Tue, 2005-12-20 at 13:04 -0800, James Salsman wrote:
Dear R experts:
I need to get this plot, but also with 95% confidence interval bands:
hour - c(1, 2, 3, 4, 5, 6)
millivolts - c(3.5, 5, 7.5, 13, 40, 58)
plot(hour, millivolts, xlim=c(1,10), ylim=c(0,1000))
pm -
On Mon, 2005-12-19 at 11:17 -0200, Ruben Roa wrote:
DeaR comRades:
I have a 2D spatial binomial process as shown in the data and code below.
I am plotting the number of trials and the number of successes in the spatial
binomial experiments and would like to draw the spatial cells were the
On Tue, 2005-12-13 at 15:50 +0100, Sebastian Leuzinger wrote:
hello,
has anyone come across the following rather mysterious problem:
when pasting large bits of code (100 and more lines) into the R console with
the central mouse button (under linux), only part of the code is pasted, and
On Tue, 2005-12-13 at 10:53 +, Dan Bolser wrote:
Hi, I am plotting a distribution of (ordered) values as a barplot. I
would like to label groups of bars together to highlight aspects of the
distribution. The label for the group should be the range of values in
those bars.
As this is
On Tue, 2005-12-06 at 15:19 +0100, Dubravko Dolic wrote:
Hi all,
the moment you hit the 'send' button you know the answer...
I approached a solution similar to this one given by Marc. But maybe
there is a better one? Even because this operation is done in a
for-loop during which R gets
On Tue, 2005-12-06 at 16:48 -0200, Alexandre Santos Aguiar wrote:
Hi,
Found no measure of association or correlation for 2x2 contingency tables in
fullrefman.pdf or google. Can someone point to a package that implements such
calculations?
Thanx.
Alexandre,
See the assocstats()
On Thu, 2005-12-01 at 10:19 -0600, Paul Roebuck wrote:
On Thu, 1 Dec 2005, Sebastian Leuzinger wrote:
is R able to suppress tick labels (not tick marks)? i
know there is a way around this with axes=F and then
draw new axes, but it would be easier to suppress them
in the first place.
On Thu, 2005-12-01 at 19:40 +0300, Evgeniy Kachalin wrote:
Martin Maechler пишет:
Boxplots were invented by John W. Tukey and I think should be
counted among the top small but smart achievements from the
20th century. Very wisely he did *not* use mean and standard deviations.
Even
On Thu, 2005-12-01 at 18:33 +, Prof Brian Ripley wrote:
On Thu, 1 Dec 2005, Marc Schwartz (via MN) wrote:
On Thu, 2005-12-01 at 10:19 -0600, Paul Roebuck wrote:
On Thu, 1 Dec 2005, Sebastian Leuzinger wrote:
is R able to suppress tick labels (not tick marks)? i
know there is a way
Marc Schwartz (via MN) пишет:
On Thu, 2005-12-01 at 19:40 +0300, Evgeniy Kachalin wrote:
Martin Maechler пишет:
So I analize genetics data. I have some factor (gene variant, c(1,2,3))
and the quantitative variable corresponding to that factor. How do I
visualize this situation
On Thu, 2005-12-01 at 23:27 +0300, Evgeniy Kachalin wrote:
Marc Schwartz (via MN) пишет:
Marc Schwartz (via MN) пишет:
So plotmeans is incapable of: boxplot(numerical~fact1+fact2). Is there
any way further?
I think that somehow we are talking past each other here.
plotmeans
On Mon, 2005-11-28 at 13:18 -0800, Dennis Fisher wrote:
Colleagues
On occasion, I want to control either tick marks or labels in axes
different from the defaults created with axes=T in the plot
command. If I invoke axes=F and axis(n), I can do so. However,
the axes produced by
On Mon, 2005-11-21 at 16:57 +0100, Antje Döring wrote:
Hi there,
I have a question, which I thought is very easy to solve, but somehow
I can't find a solution. Probably someone could help me quickly?
Here it is:
I have two matrices:
a
[,1] [,2] [,3]
On Mon, 2005-11-21 at 09:01 -0800, Dhruti Ramani wrote:
I am trying to install R1.8. When I use make to build R, it gives me
following error,
* Installing *source* package 'foreign' ...
/usr/local/bin/R-1.8.1/bin/INSTALL: ./configure: /bin/sh: bad interpreter:
Permission denied
ERROR:
On Mon, 2005-11-21 at 11:12 +0100, [EMAIL PROTECTED] wrote:
Hi, I'm from Italy (sorry for my english...). I've two questions about
the plot function.
I've to create a simple graph for the data set n_species:
species=sqlQuery(dati, select count(distinct species), season from
On Mon, 2005-11-21 at 18:16 +0100, Matthieu Cornec wrote:
Hello,
How do you change the size of the caracters (tiny, small) using xtable?
It works out for print.xtable when typing
print.xtable(xtable(mydata),size=small)
but I do not see any results when doing
xtable(mydata,size=small)
I have a feeling that Vasu wants (mistakenly) this:
dat - read.table(clipboard, header = FALSE)
dat
V1 V2 V3 V4
1 Name Weight Height Gender
2 Anne150 65 F
3Rob160 68 M
4 George180 65 M
5 Greg205 69 M
str(dat)
On Thu, 2005-11-17 at 17:03 +0100, Florence Combes wrote:
Dear all,
We are facing this problem for long, and so ask for your help.
We are plotting 2 graphs in a postscript device (left part -layout
function-), and the common legend for these graphs on the right part.
The legend in the
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