This may be of help
dat -
data.frame(dbh = c(30,
29 , 28, 27, 26, 25, 24, 23, 22,
21, 20, 15, 14, 13, 12, 11, 10,
9, 8, 7, 6, 5, 30, 29, 28, 27,
26, 25, 24, 23, 22, 21, 20),
form = c( tree, tree, tree, tree, tree, tree,
tree, tree, tree,
You can fit negative binomial using the 'zicounts' package
library(zicounts)
data(teeth)
names(teeth)
## c) fit negative binomial regression model
nb.zc - zicounts(resp = dmft~.,x =~gender + age,data=teeth, distr = NB)
nb.zc
Even,
library(zicounts)
library(Fahrmeir) # use
Jiang,
This example could help:
A - matrix(rbinom(20,1,.8),ncol=2)
B - cbind(rnorm(20,-1,0),rnorm(20,1,0))
B - ifelse(A==0,NA,B)
B
A
S M Mwalili.
Lei Jiang [EMAIL PROTECTED] wrote:
Hi, there.
I have two matrix with identical dimentions. matrix A contains
information of 0 and 1, and matrix
Dear Larry,
dat - data.frame(CAT=sample(c(a,b,c,d),100,rep=T), x=rnorm(100))
tapply(dat[,2],dat[,1, drop = FALSE], mean)
tapply(dat[,2],dat[,1, drop = FALSE], sum)
I hope this helps,
Samuel.
Larry White [EMAIL PROTECTED] wrote:
At the risk of being wacked for asking what should be