My problem is as follows:
i is a list of integers of variable length. Now I want to compute a new
vector/array that contains 1's at the positions indicated in i. For
example:
c(2, 4) - c(0, 1, 0, 1)
Using something like
i = i - c(0, i[2:length(i) - 1]);
sapply(i, function(x) c(rep(0, x - 1),
Dear all,
can anybody help me with the program below? The function predict.lda
seems to be defined but cannot be used by errortest.
The R version is 1.7.1
Thanks in advance,
Stefan
library(MASS);
library(ipred);
data(iris3);
tr - sample(1:50, 25);
train -
On Tue, 2003-11-25 at 12:09, Robin Hankin wrote:
Hello List
does anyone have an R function for the Lambert W function? I need
complex arguments.
[the Lamert W function W(z) satisfies
W(z)*exp(W(z)) = z
but I could'nt even figure out how to use uniroot() for complex z]
There
Thank you all for the quick responses.
However, I'm not sure I unterstand the scaling matrix (denote S
henceforth) correcty. An observation x will be transformed by Sx into a
new vector space with the properties given by the description. What is
now the direction perpendicular to the seperating
