.4, F), (7.4, S),
> (7.4, MF)
> I am a beginner level in R and I have no idea how to
> do this. Could any one please help me. Thanks a
> lot!!!
>
> Best regrards
> Hsin Ya Lee
>
I don't understand exactly what you want but perhaps
efficient, so you may have
trouble if your data set is large.
Stephen P. Ellner ([EMAIL PROTECTED])
Department of Ecology and Evolutionary Biology
Corson Hall, Cornell University, Ithaca NY 14853-2701
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.
e(naiveBayes)
predict(model, subset(HouseVotes84, V1 == "n"))
gives
Error in object$tables[[v]] : subscript out of bounds
One workaround is to predict for a "bigger" data set
and retain a subset of the predictions.
Hope this helps,
Stephen
--
Rochester, Minn. USA
This seems to work:
tmp <- aggregate(DF$y, list(DF$x, DF$f), mean)
tmp2 <- aggregate(DF$conc, list(DF$x, DF$f), paste,collapse=", ")
names(tmp2)[3] <- "var1"
final <- merge(tmp,tmp2)
--- Lauri Nikkinen <[EMAIL PROTECTED]> wrote:
> #Hi R-users,
> #I have an example DF like this:
>
> y1 <- rno
I'm trying to figure out how to trigger a process from within R. I have an
exectuable file that runs a Fortran model, but ideally, would like to run it
from R. Note that I'm not talking about importing the function at all, passing
variables, or anything complicated like that. I basically just wa
I think you want to use the 'density' argument. For example:
barplot(1:5,col=1)
legend("topleft",fill=1,legend="text",cex=1.2)
par(new=TRUE)
barplot(1:5,density=5,col=2)
legend("topleft",fill=2,density=20,legend="text",bty="n",cex=1.2)
(if you wanted to overlay solid colors with hatching)
Here's
my own shortcoming). But seeing everything as vectors
(again, in the sense of "contiguous cells") with mutable attributes,
made everything more transparent - that if a specific method does
not exist for, say a "data.frame" object, you can still call a
function on it if you treat
I think that's the standard presentation for polar plots (theta measured from
positive x-axis) - that I've seen, anyway. But for customization you can
shift your origin for theta and define your own labels. For example, here is
a modification to the example in the help page for polar.plot():
testl
I think you're looking for
parse(text=paste(letters[1:3], collapse="+"))
--- Jarrod Hadfield <[EMAIL PROTECTED]> wrote:
> Hi Everyone,
>
> I would simply like to coerce a character string into an expression:
> something like:
>
> as.expression(paste(letters[1:3], collapse="+"))
>
> but I c
try
grep(paste("^",b[2],"$",sep=""),a)
your version will match "b2":
> grep("^b[2]$",c("b","b2","b3"))
[1] 2
--- Shao <[EMAIL PROTECTED]> wrote:
> Hi,everyone.
>
> I have a problem when using the grep.
> for example:
> a <- c("aa","aba","abac")
> b<- c("ab","aba")
>
> I want to match the w
x27;tag' does not get value of 1 when
> error occurs. How can I make it work?
>
> Thanks,
> Gang
>
>
> On Aug 6, 2007, at 1:44 PM, Stephen Tucker wrote:
>
> > ?try
> >
> > or
> >
> > ?tryCatch
> > http://www.maths.lth.se/help/R/Ex
?try
or
?tryCatch
http://www.maths.lth.se/help/R/ExceptionHandlingInR/
for example...
tryCatch(lme(Y ~ X1*X2, random = ~1|subj, Model[i]),
error=function(err) return(0))
(you can do something with 'err' or just return 0 as above)
--- Gang Chen <[EMAIL PROTECTED]> wrote:
> I run a li
Not sure exactly what 'results' is doing there or 'barplot(table(i),...)'
does [see ?table]
but I think this is sort of what you want to do?
## Variable assignment
G01_01 <- 1:10
G01_02 <- 2:6
## Combine to list*
varnames <- paste("G01_",substring(100+1:2,2),sep="")
vars <- lapply(`names<-`(as.
methods(plot)
--- Edna Bell <[EMAIL PROTECTED]> wrote:
> Hi R Gurus:
>
> I know that "plot" has extra things like plot.ts, plot.lm
>
> How would i find out all of them, please?
>
> Thanks,
> Edna
>
> __
> R-help@stat.math.ethz.ch mailing list
> htt
I think you need
predict(mod,newdate)
instead of
predict(y,newdate)
--- "Maja Schröter" <[EMAIL PROTECTED]> wrote:
> Hello everybody,
>
> I'm trying to predict a linear regression model but it does not work.
>
> My Model: y = Worktime + Vacation + Illnes + Bankholidays
>
> My modelmatrix
?cumsum
--- zahid khan <[EMAIL PROTECTED]> wrote:
> I want to calculate the commulative sum of any numeric vector with the
> following command but this following command does not work "comsum"
> My question is , how we can calculate the commulative sum of any numeric
> vector with above comma
try
par(las=1)
plot(0,0,xaxt="n",type="n", ylim=c(0,100))
mtext("35",side=2,at=35)
you can use 'las=1' in par(), plot(), axis(), etc.
more generally, you can use 'srt' in text() to rotate tick labels:
plot(1:10,1:10,xaxt="n",type="n", yaxt="n",ylim=c(0,100))
axis(1); axis(2,lab=FALSE)
text(x=pa
>
> Please let me know if I have made any mistakes.
> Thanks ../Murli
>
>
>
> -Original Message-
> From: Richard M. Heiberger [mailto:[EMAIL PROTECTED]
> Sent: Thu 8/2/2007 10:25 AM
> To: Nair, Murlidharan T; Stephen Tucker; r-help@stat.math.ethz.ch
> Subj
Thanks to all for the response - the grid.points() solution works well.
Stephen
(oddly I missed when this thread and its response actually got posted... was
starting to get worried)
--- Deepayan Sarkar <[EMAIL PROTECTED]> wrote:
> On 7/31/07, Uwe Ligges <[EMAIL PROTE
p <- seq(0.001,0.999,,1000)
x <- qt(p,df=9)
y <- dt(x,df=9)
plot(x,y,type="l")
polygon(x=c(x,rev(x)),y=c(y,rep(0,length(y))),col="gray90")
Hope this helps.
ST
--- "Nair, Murlidharan T" <[EMAIL PROTECTED]> wrote:
> Indeed, this is what I wanted, I figured it from the function you and
> Mark poi
Hi Conor,
I hope I interpreted your question correctly. I think for the first one you
are looking for a conditioning plot? I am going to create and use some
nonsensical data - 'iris' comes with R so this should be reproducible on your
machine:
library(lattice)
data(iris)
x <- iris
# make some fac
see ?rect, or, for more general shapes, ?polygon
## EXAMPLES
plot(c(0,500),c(0,500),type="n",las=1)
rect(par("usr")[1],200,par("usr")[2],300,col="grey90")
points(seq(0,500,length=3),seq(0,500,length=3))
plot(c(0,500),c(0,500),type="n",las=1)
polygon((par("usr")[1:2])[c(1,1,2,2)],
(c(200,3
"no")
the argument is not passed to the R process.
11.Rout only shows processing time and 13.out does not have the value.
Thank you all.
stephen
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://s
e widths.
I've tried looking through the documentation for xyplot, panel.points,
trellis.par.set, and the R-help archives. Maybe it goes by another name?
Thanks in advance,
Stephen
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mail
I think you are looking for append(), though it won't modify the object
in-place like Python [I believe that is a product of R's 'functional
programming' philosophy].
might want to check this entertaining thread:
http://tolstoy.newcastle.edu.au/R/help/04/11/7727.html
in this example it would be l
Sorry, just got back into town.
I wonder if AIC, BIC, or cross-validation scoring couldn't also be used as
criteria for model selection - I've seen it mostly in the context of variable
selection rather than 'form' selection but in principle might apply here?
--- Dieter Menne <[EMAIL PROTECTED]>
around that.
--- Stephen Tucker <[EMAIL PROTECTED]> wrote:
> ## Data input
> input <-
> "Year Count
> 1999 3
> 2000 5
> 2001 9
> 2002 30
> 2003 62
> 2004 154
> 2005 245
> 2006 321"
>
> dat <- read.table(textConnection
Well spoken. And since log transformations are nonlinear and 'compresses' the
data, it's not surprising to find that the fit doesn't look so nice while the
fit metrics tell you that a model does a good job.
--- [EMAIL PROTECTED] wrote:
> On 24-Jul-07 01:09:06, Andrew Clegg wrote:
> > Hi folks,
>
I think your way is probably the easiest (shockingly). For instance, here are
some alternatives - I think in both cases you have to calculate the
coefficient of determination (R^2) manually. My understanding is that
multiple R^2 in your case is the usual R^2 because you only have one
predictor vari
I don't know why it doesn't work but I think people generally recommend that
you use wireframe() in lattice rather than persp(), because wireframe is more
customizable (the pdf document referred to in this post is pretty good):
http://tolstoy.newcastle.edu.au/R/e2/help/07/03/12534.html
Here's an e
Here are two simple ways:
=== method1 ===
cat("line1","\n",file="output.txt")
cat("line2","\n",file="output.txt",append=TRUE)
=== method2 ===
sink("output.txt")
cat("line1","\n")
cat("line2","\n")
out <- lm(y~x,data=data.frame(x=1:10,y=(1:10+rnorm(10,0,0.1
print(out)
sink()
And then there is
names(dat)
[1] "Mydata" "S.sharif" "A.site"
Which, in the case of the data set, Monsoon, I don't know how it was created
originally but may be convenient to reassign names by
names(Monsoon) <- make.names(names(Monsoon))
--- Gavin Simpson <[EMAIL PROT
: num [1:60] 32.5 81.5 28.7 ...
>
> when I attach the data file and access the site "S-Sharif" or D-I Khan" or
> "Mian Wali" then error messages occur.
>
> Please help in this regard.
>
> Thank You
>
>
> On 7/23/07, Stephen Tucker <[EMA
Very close... Actually it's more like
savecol2=sapply(test, function(x) x[,1])
to get the same matrix as you showed in your for-loop (did you actually want
the first or second column?).
"when I have multiple complex lists I am trying to manage"...
for this, you can try mapply() which goes someth
Could you post the output from
str(data)
?
Perhaps that will give us a clue.
--- amna khan <[EMAIL PROTECTED]> wrote:
> Sir the station name "S.Sharif" exists in the data but still the error is
> ocurring of being not found.
> Please help in this regard.
>
>
> On 7/22/07, Gavin Simpson <[EM
7 0.1681777 -0.6932731 0.1707946 0.702454
mat2col3 -0.5147084 0.1467148 -0.7226387 -0.1144475 -0.01997228
mat2col4 -0.7977480.8139768 -0.7929604 -0.8213577 0.371248
mat2col5 -0.001457972 0.03998203 0.4273667 0.526239 0.4390378
--- Stephen Tucker <[EMAIL PROTECTED]> wrot
737 0.01699978
[4,] 0.26353316 -0.1873564 0.2121154 0.88784766 -0.02257890
[5,] -0.03771225 -0.4250040 0.3795558 -0.03372794 -0.05874675
Hope this helps,
Stephen
--- "Bernzweig, Bruce (Consultant)" <[EMAIL PROTECTED]> wrote:
> In trying to get a better understanding of
You could try
par(mar=c(0,5,0,2), mfrow = c(6,1), oma=c(5,0,2,0))
##...then, your plots...##
--- Mr Natural <[EMAIL PROTECTED]> wrote:
>
> I would appreciate suggestions for removing the white spaces the graphs in
> a
> stack:
>
> par(mar=c(2,2,1,1), mfrow = c(6,1))
> mydates<-dates(1:20,origi
I think you can still read as a table, just use argument fill=TRUE.
Reading from Excel in general: you can save data as 'csv' or tab-delimited
file and then use read.csv or read.delim, respectively, or use one of the
packages listed in the following post (for some reason lines breaks are
messed up
What's wrong with lattice? Here's an alternative:
library(ggplot2)
ggplot(data=data.frame(x,y,grps=factor(grps)),
mapping=aes(x=x,y=y,colour=grps)) + # define data
geom_identity() +# points
geom_smooth(method="lm") # regression line
My apologies, I read the post over too quickly (even the second time).
It's been a while since I've played around with anything other than box
constraints, but this one is conducive to a brute-force approach (employing
Berwin suggestions). The pseudo-code would look something like this:
delta <-
f <- function(x)
(sqrt((x[1]*0.114434)^2+(x[2]*0.043966)^2+(x[3]*0.100031)^2)-0.04)^2
optim(c(0,0,0),f)
see ?optim for details on arguments, options, etc.
--- "massimiliano.talarico" <[EMAIL PROTECTED]> wrote:
> I'm sorry the function is
>
> sqrt((x1*0.114434)^2+(x2*0.043966)^2+(x3*0.100031
icular audience it's sometimes necessary to speak their language...
So, hope you don't mind, but I may ask some more 'can ggplot do this'
questions in the future. But keep up the good work,
Stephen
--- hadley wickham <[EMAIL PROTECTED]> wrote:
> Hi Stephen,
>
>
My apologies, didn't see the boundary constraints. Try this one...
f <- function(x)
(sqrt((x[1]*0.114434)^2+(x[2]*0.043966)^2+(x[3]*0.100031)^2)-0.04)^2
optim(par=rep(0,3),f,lower=rep(0,3),upper=rep(1,3),method="L-BFGS-B")
and check ?optim
--- "massimiliano.talarico" <[EMAIL PROTECTED]> wrote
ents thus far...
but very good to know (and cool demonstrations btw). Thanks!
Stephen
--- Deepayan Sarkar <[EMAIL PROTECTED]> wrote:
> On 7/14/07, Stephen Tucker <[EMAIL PROTECTED]> wrote:
> >
> > I wonder what kind of objects? Are there large advantages for allowing
&g
t.info)
> }
> }
>
> xyplot(runif(30) ~ runif(30) | gl(3, 10),
> panel = panel.qrect(rectInfo))
>
>
>
> On 7/14/07, Stephen Tucker <[EMAIL PROTECTED]> wrote:
> > This is very interesting - but I'm not entirely clear on your last
> sta
unction analogous to panel.qrect is existing since using
> scoping then involves manipulation of environments in the closure
> approach.
>
> On 7/11/07, Stephen Tucker <[EMAIL PROTECTED]> wrote:
> > In the Trellis approach, another way (I like) to deal with multiple
> pieces
I wonder what kind of objects? Are there large advantages for allowing
lattice functions to operate on objects other than data frames - I
couldn't find any screenshots of flowViz but I imagine those objects
would probably be list of arrays and such? I tend to think of mapply()
[and more recently m
This should do it:
allData <- sapply(paste("Sim",1:20,sep=""),
function(.x) read.table(paste(.x,"txt",sep=".")),
simplify=FALSE)
see ?read.table for specification of delimiters, etc.
allData will be a list, and you can access the contents of each file by
any o
sire for size and color scales as well).
Of course, I can always try to fool the system by (1) applying the scaling a
priori to create a new variable, (2) plotting points from the new variable,
and (3) creating a new axis w
Regarding your earlier statement,
"I tend to think in very data centric approach, where you first generate the
data (in a data frame) and then you plot it. There is very little data
creation/modification during the plotting itself..."
Is the data generation and plotting truly separate and sequent
t2 is very appealing
- in an hour I picked up enough to do quite a bit, just by going through
examples in the author's book <http://had.co.nz/ggplot2/>. Will be
interesting to see how this package will be received by the community.
Stephen
--- Stephen Tucker <[EMAIL PROTECTED]> wrote:
In the Trellis approach, another way (I like) to deal with multiple pieces of
external data sources is to 'attach' them to panel functions through lexical
closures. For instance...
rectInfo <-
list(matrix(runif(4), 2, 2),
matrix(runif(4), 2, 2),
matrix(runif(4), 2, 2))
panel
Not that Trellis/lattice was entirely easy to learn at first. :)
I've been playing around with ggplot2 and there is a plot()-like wrapper for
building a quick plot [incidentally, called qplot()], but otherwise it's my
understanding that you superpose elements (incrementally) to build up to the
gra
Hi David,
I'm not an expert in 'rgl', but to determine data-dependent color for points
I often use cut().
# using a very simple example,
x <- 1:2; y <- 1:2; z <- matrix(1:4,ncol=2)
# the following image will be a projection of my intended 3-D 'rgl' plot
# into 2-D space (if we don't consider col
I'm not able to make out your data but something like this?
df <- data.frame(A=rnorm(10),B=rnorm(10),C=runif(10))
stripchart(df,method="jitter")
--- Tavpritesh Sethi <[EMAIL PROTECTED]> wrote:
> Hi all,
> I have 205 rows with measurements for three categories of people. I want to
> generate str
Hi Lars,
I haven't tried this, but I believe there were a couple of messages on
the list recently on reading large files that basically used scan with
connections, and reading in by blocks.
see ?scan, ?connections
HTH
steve
Lars Modig wrote:
> Hello
>
>
> I’ve got a large CSV file (>500M) wit
You do not have matching parentheses in this line
returnlow <- gpdlow(var[,i][var[,i]<(p[,i][[2]])
most likely there is a syntax error that halts the execution of the
assignment statement?
--- livia <[EMAIL PROTECTED]> wrote:
>
> Hi All, I am trying to make a loop for a function and I am us
start=list(beta1=1,beta2=1,beta3=1),
lower=list(beta1=1,beta2=1,beta3=1))
Thanks in advance!
Stephen
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-proj
Actually, I believe attach() and detached() is discouraged nowadays...
x <- read.delim("Filename.txt", header=TRUE)
You can access your data by column:
x[,1]
x[,c(1,3)]
or if your first column is named "Col1" and the third "Col3",
x[,"Col1"]
x[,c("Col1","Col3")]
and you can do the same to acces
You can just create another variable which contains the "names" you want:
## let
Year <- c(rep(1999,2),rep(2000,2),rep(2001,3))
## one alternative
getYearCode1 <- function(yr) {
# yr can be a vector
ifelse(yr==1999,"Year1",
ifelse(yr==2000,"Year2",
ifelse(yr==2001,"Y
I think you are looking for paste().
And you can replace your for loop with lapply(), which will apply regexpr to
every element of 'mylist' (as the first argument, which is 'pattern'). 'text'
can be a vector also:
mylist <- c("MN","NY","FL")
lapply(paste(mylist,"$",sep=""),regexpr,text="Those fro
Dear John,
Perhaps I am mistaken in what you are trying to accomplish but it seems like
what is required is that you call lstfun() outside of ukn(). [and remove the
call to lstfun() in ukn()].
nts <- lstfun(myfile, aa, bb)
results <- ukn(dd1, "a", "b", nts$cda)
Alternatively, you can eliminate t
This zooming function on the R-Wiki page was very neat:
http://wiki.r-project.org/rwiki/doku.php?id=tips:graphics-misc:interactive_zooming
Also, to answer question (a), maybe these examples might help?
## add elements to plot
plot(1:10,1:10)
lines(1:10,(1:10)/2)
points(1:10,(1:10)/1.5)
## add s
Here are two ways:
## method 1
plot(1:100,y1)
par(new=TRUE)
plot(1:100,y2,xlab="",ylab="",col=2,axes=FALSE)
axis(4,col=2,col.axis=2)
## method 2
plot.new()
plot.window(xlim=c(1,100),ylim=range(y1))
points(1:100,y1)
axis(1)
axis(2)
title(xlab="x",ylab="y1")
plot.window(xlim=c(1,100),ylim=range(y2)
If by 'position' you mean the distance from the axes, I think 'mgp' is the
argument you are looking for (see ?par)-
You can set this in par(), plot() [which will affect both x and y labels], or
title():
par(mar=rep(6,4))
plot(NA,NA,xlim=0:1,ylim=0:1,xlab="X",ylab="")
title(ylab="Y2",mgp=c(4,1,0))
My mistake... last alternative should be:
c<-subset(c,regexpr("\\.1|\\.5|\\.6|\\.9",rownames(c)) < 0)
--- Stephen Tucker <[EMAIL PROTECTED]> wrote:
> You can list them together using "|" (which stands for 'or'):
>
> c<-subset(c
You can list them together using "|" (which stands for 'or'):
c<-subset(c,!rownames(c) %in% grep(".1|.5|.6|.9",rownames(c),value=T))
but "." means any character for regular expressions, so if you meant a
decimal place, you probably want to escape them with a "\\":
c<-subset(c,!rownames(c
There are also some notes about this in the R Data Import/Export manual:
http://cran.r-project.org/doc/manuals/R-data.html#Reading-Excel-spreadsheets
But I've gathered the following examples from the R-help mailing list
archives [in addition to the option of saving the spreadsheet as a .csv file
ither why 'whereis' does not identify this-- or why it
lists the file 3 times?.
I'm also puzzled why they chose to call the file exactly the same thing.
I will next try rpm --force as you suggest.
Stephen
-Original Message-
From: Peter Dalgaard [mailto:[EMAIL PROTECTED]
32bit file? Or do I need to edit
something in the rpm file?
Thanks
-Original Message-
From: Peter Dalgaard [mailto:[EMAIL PROTECTED]
Sent: Thu 6/21/2007 6:34 PM
To: Stephen Henderson
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] FW: Suse RPM installation problem
Stephen Henderson
.
However reading the Installation manual I noted that libpng is mention
in the context of a source build. I therefore downloaded "libpng-1.2.18"
(v-1.2.8 or later is specified in the manual) and succesfully compiled
this. This did not however help with my problem.
Any suggestions?
Than
Here is one way:
Vector1 <- c("20080621.00","20080623.00")
Vector2 <- c("20080620.00","20080622.00")
do.call(difftime,
c(apply(cbind(time1=Vector1,time2=Vector2),2,
function(x) strptime(x,format="%Y%m%d.00")),
units="hours"))
see ?strptime, ?difftime and
http://cra
u have an issue with missing data. It looks like dsvdis does not
like the NA's - so you must make a decision about what to do. Delete that
species, delete that site, or whatever...
Finally - the warning over symbol.For is an issue with the labdsv library itself
- nothing you are doing wrong. The
Hi Ana,
There are two ways in which I imagine this can be done:
(1) create a layout [using layout()] and printing the text on a blank plot;
(2) using Sweave.
## === Method 1 example... ===
pdf()
layout(matrix(c(1,1,2,3),ncol=2,byrow=TRUE),widths=c(1,1),heights=c(3,2))
par(mar=c(0,0,5,0))
plot.ne
Hi Paul,
Hope this is what you're looking for:
## reading in text (the first 13 rows of cc from your posting)
## and using smaller indices [(3,8) instead of (10,40)]
## for this example
> cc <- "mode<-"(do.call(rbind,
+strsplit(readLines(textConnection(txt))[-1],"[ ]{2,}"))[,-1],
+
ersion of MASS;
this was in the days of S-PLUS dominance and perhaps less applicable now to R
as you mentioned... But old habits die hard; my amygdala still invokes a fear
response at the thought of a loop... (and as of recently, I have been
infatuated with the notion of adhering, albeit loosely, to th
Hi Horace,
I have also thought that it may be useful but I don't know of any Object
Explorer available for R.
However, (you may alread know this but)
(1) you can view your list of objects in R with objects(),
(2) view objects in a spreadsheet-like table (if they are matrices or data
frames) wit
[x for x in enumerate(L)]
## returns index of list along with the list element
[(0, 'a'), (1, 'b'), (2, 'c')]
## a dictionary
D = {'jack': 4098, 'sape': 4139}
[x for x in D.iteritems()]
## returns element key (name) along with element contents
Maybe substring() is what you're looking for? Some examples:
> substring("textstring",1,5)
[1] "texts"
> substring("textstring",3)
[1] "xtstring"
> substring("textstring",3,nchar("textstring"))
[1] "xtstring"
--- Tim Holland <[EMAIL PROTECTED]> wrote:
> Is there a way in R to select certain cha
,","),
function(x) gsub("^\\.$","",x)))
> m
[,1] [,2] [,3] [,4]
[1,] "1" "2" "" "4"
[2,] "2" "" "4" "5"
[3,] "3" "4" "" &qu
Since R is supposed to be a complete programming language, I wonder
why these tools couldn't be implemented in R (unless speed is the
issue). Of course, it's a naive desire to have a single language that
does everything, but it seems that R currently has most of the
functions necessary to do the t
plot(x=1:10,y=1:10,xlim=c(0,5),ylim=c(6,10))
a lot of the arguments descriptions for plot() are contained in ?par
--- Patrick Wang <[EMAIL PROTECTED]> wrote:
> Hi,
>
> How to specify the start position of Y in plot command, hopefully I can
> specify the range of X and Y axis. I checked the ?pl
There's also this approach
plot(runif(10), ylab=list("Red, Bold?", col = "red", font = 2),
xlab="Black, standard?")
On 5/31/07, Greg Snow <[EMAIL PROTECTED]> wrote:
> Try this:
>
> > plot(runif(10), ylab="", xlab="Black, standard?")
> > mtext('Red, Bold', side=2, line=3, col='red', font=2)
>
> H
You can also use type.convert() if you did want to convert your characters to
numbers and "NA"'s to NA's so that you can use na.omit().
> x <- matrix("0",5,5)
> x[1,3] <- x[4,4] <- "NA"
> newx <- apply(x,2,type.convert)
> newx
[,1] [,2] [,3] [,4] [,5]
[1,]00 NA00
[2,]0
looking,
> either in str(mymod) or in the help files, but it's a huge problem for
> me.
>
>
Try
coef(mymod$model$corStruct,
unconstrained = FALSE)
Stephen
--
Rochester, Minn. USA
__
R-help@stat.math.ethz.ch mailing list
http
- Girth)
+ 0.72 * pmax(0, Height - 76)
Number of cases: 31
Selected 4 of 5 terms, and 2 of 2 predictors
Number of terms at each degree of interaction: 1 3 (additive model)
GCV: 11 RSS: 213 GRSq: 0.96 RSq: 0.97
Regards,
Stephen Milborrow
___
R
Actually I am not sure what you want exactly, but is it
df1 <-data.frame(b=c(1,2,3,4,5,5,6,7,8,9,10))
df2 <-data.frame(x=c(1,2,3,4,5), y=c(2,5,4,6,5), z=c(10, 8, 7, 9, 3))
df1 <- cbind(df1,
"colnames<-"(sapply(with(df2,(x+y)/z),
function(a,b) a/b,b=df1
Sometimes I just overlay a blank plot and annotate with text.
par(mfrow=c(1,2), oma=c(2,0,2,0))
plot(1:10)
plot(1:10)
oldpar <- par()
par(mfrow=c(1,1),new=TRUE,mar=rep(0,4),oma=rep(0,4))
plot.window(xlim=c(0,1),ylim=c(0,1),mar=rep(0,4))
text(0.5,c(0.98,0.02),c("Centered Overall Title","Centered Su
Thanks guys for the suggestions guys- I come across this problem a lot but
now I have many solutions.
Thank you,
Stephen
--- Peter Dalgaard <[EMAIL PROTECTED]> wrote:
> Peter Dalgaard wrote:
> > Stephen Tucker wrote:
> >
> >> Dear R-helpers,
> >>
&
ve not been able to find anything
> else that would help or why these errors are occuring.
> Jacquie
>
Good luck,
Stephen
--
Rochester, Minn. USA
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
ot;,x)
if(length(iexclude) > 0) x2 <- x[-iexclude] else x2 <- x
# do stuff with x2 <...?
}
But this is embedded in a much larger function and I am trying to minimize
intermediate variable assignment (perhaps a futile effort). But if anyone
knows of an easy solution, I&
My apologies. Second line should be
title(main="Histogram of ...",cex.main=0.5)
Actually I just realized you can also do
hist(rnorm(100),xlab="Data",ylab="Count",cex.main=0.5)
...this way you don't have to call title() separately.
--- Stephen Tucker <[
hist(rnorm(100),xlab="Data",ylab="Count",main="")
title(main="Histogram of ...",cex=0.5)
see ?par for details on xlab, ylab, main, and cex arguments.
You can call these from title() or include them in hist().
I called title(main=..) separately to control its size separately
from the rest of the te
Edward Tufte seems to have some opinions on this topic.
In The Visual Display of Quantitative Information (Chapter 6: Data-Ink
Maximization and Graphical Design -> Redesign of the Scatterplot), he
presents several alternatives
(1) "non-data-bearing frame" in conventional scatterplots (equivalent
You can also set this option globally with options(stringsAsFactors = TRUE)
I believe this was added in R 2.4.0.
--- Gabor Grothendieck <[EMAIL PROTECTED]> wrote:
> Try this:
>
> DF <- data.frame(let = letters[1:3], num = 1:3, stringsAsFactors = FALSE)
> str(DF)
>
>
> On 4/19/07, John Kane
you have to use "POSIXct" classes to include date-time objects into data
frames. strptime() returns an object of class of "POSIXlt". when you do the
cbind(), it automatically converts test2 into "POSIXct"
you probably want
bsamp$spltime<-as.POSIXct(strptime(test,format="%d-%B-%y %H:%M"))
(but ple
## making data up
# make matrix with some equal values
> mat <- cbind(x=rnorm(10),y=rnorm(10),z=rnorm(10))
> mat[c(8,9),"y"] <- mat[c(1,7),"x"]
> mat
x y z
[1,] 0.26116849 0.5823529 -0.96924020
[2,] -0.21415406 0.1085396 2.00542549
[3,] 0.56890081 -1.25263
s are getting
close to the truth
Good luck,
Stephen
Rochester, Minn. USA
On 4/18/07, Deepankar Basu <[EMAIL PROTECTED]> wrote:
> As part of carrying out a complicated maximum likelihood estimation, I
> am trying to learn to program likelihoods in R. I started with a simple
> probit mo
...is this what you're looking for?
donedat <- subset(data,ID < 6000 | ID >= 7000)
findat <- donedat[-unique(rapply(donedat,function(x)
which( x < 0 ))),,drop=FALSE]
the second line looks through each column, and finds the indices of negative
values - rapply() ret
1 - 100 of 298 matches
Mail list logo
