i386, mingw32
status
major 2
minor 4.1
year 2006
month 12
day18
svn rev40228
language R
version.string R version 2.4.1 (2006-12-18)
Juli
On 03/02/07, Marc Schwartz [EMAIL PROTECTED] wrote:
On Sat, 2007-02-03 at 19:06 +0100, juli g
that was only 1/4th done after 25
h!
Many thanks
Juli
On 02/02/07, juli g. pausas [EMAIL PROTECTED] wrote:
Hi all,
I have a large file (1.8 GB) with 900,000 lines that I would like to read.
Each line is a string characters. Specifically I would like to randomly
select 3000 lines. For smaller
Hi all,
I have a large file (1.8 GB) with 900,000 lines that I would like to read.
Each line is a string characters. Specifically I would like to randomly
select 3000 lines. For smaller files, what I'm doing is:
trs - scan(myfile, what= character(), sep = \n)
trs- trs[sample(length(trs), 3000)]
:
aov(H ~ B * A %in% B * Time + Error(id) )
where id is the factor coded for the repeated subjects.
But my question is how to include the random factor C ?
Any help would be appreciated. Thanks
Juli
--
Juli G. Pausas
CEAM UA
http://www.ceam.es/lass/pausas.htm
Dear all,
I don't understand the following behaviour: Running compar.gee (in
library ape ) with and without the option 'data', it give me different
results
Example:
Start R
load(eiber.RData)
ls()
[1] gee.na mydata mytree
library(ape)
# runnig with the option data= mydata
Dear all,
I'd like to subset a df within a function, and use select for choosing
the variable. Something like (simplified example):
mydf - data.frame(a= 0:9, b= 10:19)
ttt - function(vv) {
tmpdf - subset(mydf, select= vv)
mean(tmpdf$vv)
}
ttt(mydf$b)
But this is not the correct way. Any
for setting
the 2 plots at the same scale?
I have unsuccessfully tried:
plot(t, data, type=b, xlim=c(0,7))
plot(t, data, type=b, xlim=c(min(t),max(t)))
(R 1.8.1, for Windows)
Thanks
Juli
--
Juli G. Pausas
Centro de Estudios Ambientales del Mediterraneo (CEAM)
C/ Charles R. Darwin 14, Parc
),
axes=F, xlab=, ylab=)
axis(4); mtext(Number of fires, side=4, line=3, col=1)
legend(2, 155, Number, lty= 1, pch= 19, bty=n, cex=0.8)
legend(2, 163, Area, fill= 2, bty=n, cex=0.8)
Cheers
Juli
Martin Maechler wrote:
juli == juli g pausas [EMAIL PROTECTED]
on Thu, 18 Dec 2003 10:54:08 +0100
Dear colleges,
I do not understand the following behaviour:
aa - data.frame(a1= 1:10, a2= c(rep(NA, 5), 1:5) )
aa
a1 a2
1 1 NA
2 2 NA
3 3 NA
4 4 NA
5 5 NA
6 6 1
7 7 2
8 8 3
9 9 4
10 10 5
aa[!aa$a2==1, ] # removing rows with a2==1
a1 a2
NA NA NA
NA.1 NA NA
NA.2 NA NA
Dear collegues,
How can I get the name of a variable (and not the variable) within a
function ?
For instance, in the following function, I'd like to create a variable
in the dataframe df with the same name to the variable passed in var:
prova - function( var )
{
df -
Dear all,
I have a problem which I'm not sure if it is due to my machine or if I'm
doing something wrong.
I'm ploting a little map using plot(val, type=l, asp=1) where val is
the object with the latitude/longitude data.
In the screen the figure is perfect, and I can copy to the clipboard and
Dear all,
I've seen that there are some maps, or at least costlines in R. The oz
package is the map of Autralia and in the fields package there is a US
map and a world map. This world map allows to select smaller sections
such Europe:
library(fields)
world(xlim=c(-10,18),ylim=c(36,60))
Hi,
Given a correlation matrix, how can I know which variables have certain
correlation values?
aa - matrix( rnorm(25, 1,1), 5,5)
colnames(aa) - c(v1, v2, v3, v4, v5)
aacor - cor(aa)
For instance, which variables are negatively correlated?
aacor[aacor0] # provide the r values, but how I get
Hi,
This is a very basic question, but I would like to undestand hist(). I
thought that the hist( , freq=FALSE) should provide the relative
frequencies (probabilities), and so they should sum 1, however:
set.seed(2)
ah - hist(rnorm(100), freq=F)
sum(ah$intensities)
[1] 2
set.seed(2)
bh -
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