, add this:
m <- m[order(m$siteid,m$date),]
--- On Mon 09/29, < [EMAIL PROTECTED] > wrote:
From: [mailto: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Date: Mon, 29 Sep 2003 13:15:36 -0400
Subject: [R] Data frame transpose
Hi All,I want to ask if there is a transpose function for data
Assuming that the data frame is called m, you can - split the data frame by the
values of siteid and date- apply a function to create the new data frame for each such
group and - use rbind to put it back together like this: fn <- function(x) { y
<- t(x[,4:5]) data.frame( siteid=x[1,1], date=x[1
Dave -
I'm not sure whether there is already a function which does
exactly what you want, because this is kind of a special case.
The functions I wold look at are: "by", "aggregate", "tapply",
"mapply", and, in the package "nlme" one I didn't know about
before called "gapply".
But, in your case,
On Mon, 29 Sep 2003 [EMAIL PROTECTED] wrote:
>
> Hi All,
>
> I want to ask if there is a transpose function for data frame like the
> procedure of transpose in SAS? Because I want to partially transpose a
> data frame which contains 5 columns (siteid, date, time, obs, mod), what
> I want to do is t
Hi All,
I want to ask if there is a transpose function for data frame like the
procedure of transpose in SAS? Because I want to partially transpose a
data frame which contains 5 columns (siteid, date, time, obs, mod), what
I want to do is to put time as the column variables along with siteid,
