Are you using the latest version of fame? 1.05 and earlier had a bug in
tisFromCsv that was fixed in 1.08.
Below I show what I get with fame version 1.08. There is still a problem in
that the frequency-figuring logic appears to think the frequency is bwsunday
(biweekly with weeks ending on
Yes, I was using 1.05. I get the same result as you with 1.08.
On 26 Jul 2007 11:39:41 -0400, Jeffrey J. Hallman [EMAIL PROTECTED] wrote:
Are you using the latest version of fame? 1.05 and earlier had a bug in
tisFromCsv that was fixed in 1.08.
Below I show what I get with fame version
On 26 Jul 2007 09:59:31 -0400, Jeffrey J. Hallman [EMAIL PROTECTED] wrote:
zoo is nice. 'tisFromCsv()' in the fame package is nicer.
Jeff
1. What am I doing wrong here? I only get one data column.
2. I assume the regularized dates which do not exactly match the input ones
are intended
zoo is nice. 'tisFromCsv()' in the fame package is nicer.
Jeff
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
I am taking an excel dataset and reading it into R using read.table.
(actually I am dumping the data into a .txt file first and then reading data
in to R).
If you are on *windows* you could also try my xlsReadWrite package
which contains some datetime functions. Exceldates (e.g. formatted as
Alex:
I am taking an excel dataset and reading it into R using read.table.
This sets up a data.frame object. The data you have are probably more
conveniently represented as a time series, storing the date in an
appropriate format, e.g., in class Date.
(actually I am dumping the data into a
R
I am taking an excel dataset and reading it into R using read.table.
(actually I am dumping the data into a .txt file first and then reading data
in to R).
Here is snippet:
head(data);
Date Price Open.Int. Comm.Long Comm.Short net.comm
1 15-Jan-86 673.25175645 65910
Try some of the following:
head(subset(df, Yr %in% c(00,01,02,03)))
subset(df, (Yr = '00') (Yr = '03')) # same as above
subset(df, (Yr == '00') | (Yr == '01') | (Yr == '02') |(Yr == '03')) # same
On 7/19/07, Alex Park [EMAIL PROTECTED] wrote:
R
I am taking an excel dataset and reading
Hello R Experts,
I want to aggregate parameters by week. But our production week ends Friday
night instead of Sunday Night which is the default value in R.
In order to solve the problem I want to substract two days from the current
data and than use the R function
On Thu, 21 Sep 2006, Thorsten Muehge wrote:
Hello R Experts,
I want to aggregate parameters by week. But our production week ends Friday
night instead of Sunday Night which is the default value in R.
The default in ISO8601, not just in R, but that is %W, not %U as used
below.
In order to
10 matches
Mail list logo
