Try this:
DF <- data.frame(
col1 = factor(c("31*", "0", "102*", "71*", "31", "66", "47")),
col2 = factor(c("66", "0*", "66", "80", "2*", "31*", "38"))
)
replace(DF, TRUE, as.numeric(sub("*", "", as.matrix(DF), fixed = TRUE)))
On 2/6/07, Dale Steele <[EMAIL PROTECTED]> wrote:
> G
I'm sorry, I forgot my definition of dat.
dat in code of previous post is:
> dat<-data.frame(col1=c("31*","0","102*","71*","31","66","47"),col2=c("66","0*","66","80","2*","31*","38*"))
> dat
col1 col2
1 31* 66
20 0*
3 102* 66
4 71* 80
5 31 2*
6 66 31*
7 47 38*
On 2/7/07
I think several ways can do that.
my code is:
data.frame(t(apply(dat,1,function(x)as.numeric(sub("\\*","",x[sort(1:2,grep("\\*",x)==2)])
HTH
On 2/7/07, Dale Steele <[EMAIL PROTECTED]> wrote:
> Given two columns of type character in a dataframe of the form:
>
> col1col2
> 31* 66
> 0
Given two columns of type character in a dataframe of the form:
col1col2
31* 66
0 0*
102*66
71* 80
31 2*
66 31*
47 38*
How do I generate the following dataframe? Ie. col1 contains row item
with "*" and col2 contains row member without "*"
col1col
