Here is another (simpler?) solution:
# your 1 column data is actually a vector
myvalues <- 1:10
names(myvalues) <- LETTERS[1:10]
# use the QCA package
library(QCA)
aa <- createMatrix(rep(2, length(myvalues)))
# set the number of combinations: 2, 3, 4 or whatever
combinations <- 2
sub.aa <- aa[ro
Here is how to do it for 2; you can extend it:
> # test data
> n <- 100
> x <- data.frame(id=sample(letters[1:4], n, TRUE), values=runif(n))
> # get combinations of 2 at a time
> comb.2 <- combn(unique(as.character(x$id)), 2)
> for (i in 1:ncol(comb.2)){
+ cat(sprintf("%s:%s %f\n",comb.2[1,i],
Lots of ways. Here is a simpler one.
start by reading
?combn
?subset
?Subscript
?is.element
?apply
?paste - note the 'collapse' arg
?names - note the 'names(x) <- value' usage
?list
?unlist
then write a function that calc's
Hello!
I have a regular data frame (DATA) with 10 people and 1 column
('variable'). Its cases are people with names ('a', 'b', 'c', 'd',
'e', 'f', etc.). I would like to write a function that would sum up
the values on 'variable' of all possible combinations of people, i.e.
1. I would like to wri
