Kartik Pappu kartik.pappu at gmail.com writes:
Essentially, I want to make a union of the two data frames. I hope
this question makes sense.
See merge(...), and have a look at R intro. Also check documentation for
Design package. Anupam.
__
Hi,
I have two data frames each with 5 columns and different number of
rows. some of the row names in one data frame are the same as the row
names in the other. I want to be able to merge the two data frames to
get a new data frame in which the duplicated row names are only shown
once with the
How about,
uxy - union(row.names(x), row.names(y))
ixy - intersect(row.names(x), row.names(y))
rbind(x[is.element(row.names(x),uxy),],
y[!is.element(row.names(y),ixy),])
Note, simple rbind'ing of the two frames changes
common row.names.
Gamal
__
Try either of these:
rbind(DF1, DF2[setdiff(rownames(DF2), rownames(DF1)),])
rbind(DF1, DF2[!(rownames(DF2) %in% rownames(DF1)),])
On 9/19/06, Kartik Pappu [EMAIL PROTECTED] wrote:
Hi all,
I have two data frames each with 5 columns and different number of
rows. some of the row names in one
Can't you turn the lists into data frames issue unique and
force them back to lists. Here's the code:
L - list(c(a1,a3,a4), c(a1,a4,a5), c(a1,a5,a6))
M - list(c(a1,a3,a4), c(a2,a4,a5), c(a1,a5,a6), c(a7,
a1, a4))
LL - as.data.frame(I(L))
MM - as.data.frame(I(M))
X -
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Hi,
First of all, let me thank you all for replying so rapidly to my first
question on this list. It was very very helpfull... and I'm learning R
faster and faster.
I just encountered a second problem, which may also have a simple solution.
Here it is:
In my program, a vector is a set of
From: Gabor Grothendieck
Pat Meyer paterijk at hotmail.com writes:
:
: Hi,
:
: First of all, let me thank you all for replying so rapidly
to my first
: question on this list. It was very very helpfull... and I'm
learning R
: faster and faster.
:
: I just encountered a second
Thank you Gabor.
But I have a problem with the beginning of my algorithm, where the list
you call L is empty... then the code breaks down... It says:
Error in any(...,na.rm = na.rm) : incorrect argument type
How can I handle this?
Thank you very much for your help
Patrick
Andy, I don't think that you should be so quick to put yourself down.
Your solution just needs a 'sort' put in it so that order doesn't matter.
With Andy's solution the object can now be a character vector rather
than a list and 'match' can be used for testing new items:
newitems -
Initialize the list with the first vector, instead of an emtry list, if you
can.
Andy
From: Patrick Meyer
Thank you Gabor.
But I have a problem with the beginning of my algorithm,
where the list
you call L is empty... then the code breaks down... It says:
Error in any(...,na.rm =
Patrick Meyer patrick.meyer at internet.lu writes:
:
: Thank you Gabor.
:
: But I have a problem with the beginning of my algorithm, where the list
: you call L is empty... then the code breaks down... It says:
:
: Error in any(...,na.rm = na.rm) : incorrect argument type
:
: How can I
Patrick Meyer patrick.meyer at internet.lu writes:
:
: It does not exactly do what it is meant to... Instead of breaking down,
: my code is looping forever now... I think I will have a deeper look at
: it tomorrow...
:
: In fact, I have two lists: let's say L and N.
:
: An elements (or set)
Thanx to all of you who helped me with my sets problem. ;-)
Patrick
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Hi,
I have a problem, can you help?
When i type:
library(RODBC)
a-odbcConnect(oracle)
sqlQuery(a,(select VALFACT500 from EPISGDHS) UNION (select
VALFACT1000 from EPISGDHS))
Comes the error:
[1] S1000 923 [unixODBC][Easysoft][Oracle]ORA-00923: FROM keyword not
found where expected at
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