Hi,
I use lme to fit models like
R res1 - lme(y~A+B, data=mydata, random=~1|subject)
R res2 - lme(y~B+A, data=mydata, random=~1|subject)
(only difference between these two models are the
sequence in which the indep variables are written in
formula)
where y is continuous and A, B, and subject
Yes. One way is to use anova(res1, type=marginal). Read the help page
and the book (or any decent linear models book).
Andy
-Original Message-
From: Mahbub Latif [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 21, 2003 12:51 PM
To: [EMAIL PROTECTED]
Subject: [R] anova(lme object
On Thu, 21 Aug 2003, Mahbub Latif wrote:
Hi,
I use lme to fit models like
R res1 - lme(y~A+B, data=mydata, random=~1|subject)
R res2 - lme(y~B+A, data=mydata, random=~1|subject)
(only difference between these two models are the
sequence in which the indep variables are written in
The different answers reflect a lack of symmetry in the data set.
The standard A+B anova evaluates the effect of A by itself and B given
A. The other evalutes the effect of B by itself plus A given B. They
answer different questions. If you want the same answer from A+B as
from B+A, you
It is documented in ?anova.lme:
anova(res1, type=marginal)
and
anova(res2, type=marginal)
should give equivalent tables.
--
Bjørn-Helge Mevik
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You need to say library(nlme) first. Without that, ?anove.lme [in R
1.7.1 under Windows 2000] and produced for me the following:
Error in help(anova.lme, htmlhelp = FALSE) :
No documentation for `anova.lme' in specified packages and libraries:
you could try `help.search(anova.lme)'
