--- Begin Message ---
> boxplot(data.frame(1:10, 2:11), at = 1:2,
+ pars=list(staplelty=0, whisklty=0), at=1:2)
Error in boxplot.default(data.frame(1:10, 2:11), at = 1:2, pars =
list(staplelty = 0, :
formal argument "at" matched by multiple actual arguments
a<-array(dim=c(3,8))
a[1,
BJ wrote:
Hmm ok, that seems to work with that example, but when I add an "at="
option i get graphs that are only verticle lines. Sorry to be difficult.
He? So you need to pe much more precisely in this message as well!
boxplot(data.frame(1:10, 2:11), at = 1:2,
pars=list(staplelty=0, whisk
Hmm ok, that seems to work with that example, but when I add an "at="
option i get graphs that are only verticle lines. Sorry to be difficult. ~BJ
Uwe Ligges wrote:
BJ wrote:
I searched the archives, but couldnt find any way to do this with
boxplot. Is there a way? Thanks again ~BJ
See ?b
BJ wrote:
I searched the archives, but couldnt find any way to do this with
boxplot. Is there a way? Thanks again ~BJ
See ?boxplot and its argument par which points you to ?bxp:
Now, you can do stuff like
boxplot(1:10, pars=list(staplelty=0, whisklty=0))
Uwe Ligges
_
I searched the archives, but couldnt find any way to do this with
boxplot. Is there a way? Thanks again ~BJ
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