Hello,
I have a list with n numerical components of different length (3, 4 or 5
values in each component of the list); I need to export this as a text
file where each component of the list will be a row and where missing
values should fill in the blanks due to the different lengths of the
compone
Biscarini, Filippo wrote:
> Dear Mark,
>
> If you have time you can try directly into R this excerpt from my list.
>
This is horrible code, and I should be shot! I would appreciate any
better ways of doing this, but I think this works!
l = list(c(1,2,4),c(4,5,2,1),c(3,4,6,3),c(3,1,76,4,2))
f
dimitris.htm
- Original Message -
From: "Biscarini, Filippo" <[EMAIL PROTECTED]>
To:
Sent: Tuesday, April 03, 2007 11:28 AM
Subject: [R] converting a list to a data.frame
> Hello,
>
> I have a list with n numerical components of different length (3, 4
> or
You can concatenate a series of NA's to match the length of your longest
element.
(1) exampDat is example data
(2) max(rapply(exampDat,length)) is length of longest element
(3) function(x,m) will do the concatenation
(4) sapply() will return each list element as a column of a data frame
(5) t() wi
On Tue, 03-Apr-2007 at 01:55PM +0200, Dimitris Rizopoulos wrote:
|> try something like this:
|>
|> lis <- list(c(1,2,4), c(4,5,2,1), c(3,4,6,3), c(3,1,76,4,2))
|> ##
|> n.max <- max(sapply(lis, length))
|> val <- NA # what to fill in
|> fill <- function(x) c(x, rep(val, n.max - length(x))
