> df1
v1
1 1
2 2
3 3
4 4
> df1[,]
[1] 1 2 3 4
> df1[,1]
[1] 1 2 3 4
> df1[,,drop=F]
v1
1 1
2 2
3 3
4 4
> df1[,1,drop=F]
v1
1 1
2 2
3 3
4 4
> df1[1]
v1
1 1
2 2
3 3
4 4
> df1[[1]]
[1] 1 2 3 4
>
For transfers from Excel to R using the "[put/get] R dataframe" commands,
I thin
On Wed, 11 Jan 2006, Erich Neuwirth wrote:
> Subsetting from a dataframe with only one variable
> returns a vector, not a dataframe.
> This seems somewhat inconsistent.
Not at all. It is entirely consistent with matrix-like indexing (the form
you used).
> Wouldn't it be better if subsetting wo
> Subsetting from a dataframe with only one variable
> returns a vector, not a dataframe.
> This seems somewhat inconsistent.
> Wouldn't it be better if subsetting would respect
> the structure completely?
>
>
> v1<-1:4
> v2<-4:1
> df1<-data.frame(v1)
> df2<-data.frame(v1,v2)
> sel1<-c(TRUE,TRUE,
Subsetting from a dataframe with only one variable
returns a vector, not a dataframe.
This seems somewhat inconsistent.
Wouldn't it be better if subsetting would respect
the structure completely?
v1<-1:4
v2<-4:1
df1<-data.frame(v1)
df2<-data.frame(v1,v2)
sel1<-c(TRUE,TRUE,TRUE,TRUE)
> df1[sel1,]
