Dear R-users,
I don't know if there is a problem in wtd.quantile (from library Hmisc):
x - c(1,2,3,4,5)
w - c(0.5,0.4,0.3,0.2,0.1)
wtd.quantile(x,weights=w)
---
The output is:
0% 25% 50% 75% 100%
3.00 3.25 3.50 3.75 4.00
The
Perhaps you're looking for this?
?wtd.quantile
wtd.quantile(x,weights=w, normwt=TRUE)
0% 25% 50% 75% 100%
12235
Andy
From: Jing Yang
Dear R-users,
I don't know if there is a problem in wtd.quantile (from
library Hmisc):
x -
Certainly an improvement, but probably not what is really
wanted... I get:
rq(x ~ 1, weights=w,tau = c(.01,.25,.5,.75,.99))
Call:
rq(formula = x ~ 1, tau = c(0.01, 0.25, 0.5, 0.75, 0.99), weights = w)
Coefficients:
tau= 0.01 tau= 0.25 tau= 0.50 tau= 0.75 tau= 0.99
(Intercept)
Actually, I am looking for this result:
0% 25% 50% 75% 100%
11235
---
y - c(1,1,1,1,1,2,2,2,2,3,3,3,4,4,5)
quantile(y)
---
Since x with weights w is equivalant to y.
=== At 2006-03-16, 14:34:14 you wrote: ===
Perhaps
I don't know why using the fractional weights and normwt=TRUE gives that
answer, but:
wtd.quantile(x, 5:1)
0% 25% 50% 75% 100%
11235
Andy
From: Jing Yang
Actually, I am looking for this result:
0% 25% 50% 75% 100%
11235
Thanks. But that's interesting.
=== At 2006-03-16, 15:15:49 you wrote: ===
I don't know why using the fractional weights and normwt=TRUE gives that
answer, but:
wtd.quantile(x, 5:1)
0% 25% 50% 75% 100%
11235
Andy
From: Jing Yang
Actually, I am looking for
