I have a data set like this
I want to assign outward to Y if sc 90 and assign inward to Y if sc=90.
then cbind(p1982,Y) to get like these
p aa as ms cur sc Y
1 154l_aa ARG 152.04 108.83 -0.1020140 92.10410 inward
2 154l_aa THR 15.86 28.32 0.2563560 103.67100inward
3 154l_aa ASP 65.13
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982, Y=ifelse(p1982[,'sc']90, 'inward', 'outward'))
On 12/8/06, Aimin Yan [EMAIL PROTECTED] wrote:
I have a data set like this
I want to assign outward to Y if sc 90 and assign
Hopefully it is a dataframe or else you matrix will be converted to
character; forgot that when I sent it.
On 12/8/06, jim holtman [EMAIL PROTECTED] wrote:
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982,
Hi R users,
Maybe the question is too simple.
In a IF ... ELSE ... statement if(cond) cons.expr else alt.expr, IF and
ELSE should be at the same line?
For example,
if (x1==12)
{
y1 - 5
}else
{
y1 - 3
}
is right, while
if (x1==12)
{
y1 - 5
}
else # Error: syntax error
{
y1 - 3
}
is wrong?
On Tue, 2005-07-12 at 16:22 +0200, ecoinfo wrote:
Hi R users,
Maybe the question is too simple.
In a IF ... ELSE ... statement if(cond) cons.expr else alt.expr, IF and
ELSE should be at the same line?
For example,
if (x1==12)
{
y1 - 5
}else
{
y1 - 3
}
is right, while
if
Marc,
I see. Thanks.
Xiaohua
On 7/12/05, Marc Schwartz (via MN) [EMAIL PROTECTED] wrote:
On Tue, 2005-07-12 at 16:22 +0200, ecoinfo wrote:
Hi R users,
Maybe the question is too simple.
In a IF ... ELSE ... statement if(cond) cons.expr else alt.expr, IF
and
ELSE should be at the
Today is a good day for asking question, I guess.
c()
NULL
length(c())==0
[1] TRUE
r = ifelse(length(c())!=0, c(), c(1,2)) ### OK
r = c() ### OK
r = ifelse(length(c())==0, c(), c(1,2)) ### why this is not OK (given
the previous two)?
Error in
You need to (re-)read ?ifelse. In ifelse(L, v1, v2), L is suppose to be a
vector of logicals (or an expression that evaluates to one), and v1 and v2
are vectors of same length as L; i.e., ifelse() vectorizes if ... else
In the first case:
r = ifelse(length(c())!=0, c(), c(1,2))
ifelse() has three arguments, named 'test', 'yes', and 'no'.
In both of your two examples, you gave it a test argument of length equal to 1.
That is, both
length(c())!=0
and
length(c())==0
are expressions which when evaluated have length equal to 1.
Therefore, the ifelse() function wants to
