Jim Lemon jim at bitwrit.com.au writes:
Hi John,
You might have a look at toNA in the prettyR package. Wait for version
1.0-4, just uploaded, as I have fixed a bug in that function.
There is also a set of generic functions exactly for such cases: unknownToNA(),
NAToUnknown() and isUnknown()
--- Gregor Gorjanc [EMAIL PROTECTED]
wrote:
Jim Lemon jim at bitwrit.com.au writes:
Hi John,
You might have a look at toNA in the prettyR
package. Wait for version
1.0-4, just uploaded, as I have fixed a bug in
that function.
There is also a set of generic functions exactly for
--- Petr Pikal [EMAIL PROTECTED] wrote:
Hi
Strange. It works for me without any problem.
The problem is that my dataframe has 1,s in about 50%
of the columns and I only want it to apply to a few
specified columns. My explanation may not have been
clear enough.
Using your example,I want all
Once again I forgot to reply to the whole list
On Feb 9, 2007, at 8:39 AM, Charilaos Skiadas wrote:
On Feb 9, 2007, at 8:13 AM, John Kane wrote:
The problem is that my dataframe has 1,s in about 50%
of the columns and I only want it to apply to a few
specified columns. My explanation may
Hi
but you can easily extend it to only several columns
data[, col.selection] [data[, col.selection]==1]-NA
so in my case
zeta[,2] [zeta[,2] == 1] - NA
shall change only 1 in column 2 to NA (not tested)
HTH
Petr
On 9 Feb 2007 at 8:13, John Kane wrote:
Date sent: Fri, 9 Feb
--- Jim Lemon [EMAIL PROTECTED] wrote:
John Kane wrote:
This is probably a simple problem but I don't see
a
solution.
I have a data.frame with a number of columns where
I
would like 0 - NA
Hi John,
You might have a look at toNA in the prettyR
package. Wait for version
John Kane wrote:
This is probably a simple problem but I don't see a
solution.
I have a data.frame with a number of columns where I
would like 0 - NA
Hi John,
You might have a look at toNA in the prettyR package. Wait for version
1.0-4, just uploaded, as I have fixed a bug in that
Hi
Strange. It works for me without any problem.
zeta
tepl tio2 al2o3 iep
1 601 3.5 5.65
2 601 2.0 5.00
3 601 1.0 5.30
4 600 2.0 4.65
5 401 3.5 5.20
6 401 2.0 4.85
7 400 3.5 5.70
8 400 2.0 5.25
zeta[zeta==1]-NA
zeta
tepl
This is probably a simple problem but I don't see a
solution.
I have a data.frame with a number of columns where I
would like 0 - NA
thus I have df1[,144:157] - NA if df1[, 144: 157] ==0
and df1[, 190:198] - NA if df1[, 190:198] ==0
but I cannot figure out a way do this.
cata - c(
John -
Your initial problem uses 0, but the example uses 1 for the value that
gets an NA. My solution uses 1 to fit with your example. There may be
a better way, but try something like
data1[3:5] - data.frame(lapply(data1[3:5], function(x) ifelse(x==1, NA,
x)))
The data1[3:5] is just a
Works beautifully. I modified it a bit to handle the
discontinous ranges to:
a - c(3:4, 8)
data1[a] - data.frame(lapply(data1[a], function(x)
ifelse(x==1,
NA,
x)))
There may be a prettier way to handle the disconituity
but this works so it looks like I'm in good shape.
I had looked at
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