I'm a relative R novice, and sometimes the simple things trip me up.
Suppose I have
a <- c("apple", "pear")
and I want a logical vector of whether each of these strings contains
"ear" (in this case, F T). What is the idiom?
Quizzically,
Mark Lindeman
_
On Behalf Of [EMAIL PROTECTED]
Sent: Saturday, January 20, 2007 1:31 PM
To: r-help@stat.math.ethz.ch
Subject: [R] simple q: returning a logical vector of substring matches
I'm a relative R novice, and sometimes the simple things trip me up.
Suppose I have
a <- c("apple", "pe
On Sat, 2007-01-20 at 13:30 -0500, [EMAIL PROTECTED] wrote:
> I'm a relative R novice, and sometimes the simple things trip me up.
>
> Suppose I have
>
> a <- c("apple", "pear")
>
> and I want a logical vector of whether each of these strings contains
> "ear" (in this case, F T). What is the i
try 'regexpr'
> a <- c("apple", "pear")
> regexpr('ear',a)!=-1
[1] FALSE TRUE
>
On 1/20/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
>
> I'm a relative R novice, and sometimes the simple things trip me up.
>
> Suppose I have
>
> a <- c("apple", "pear")
>
> and I want a logical vector of w
Using the builtin month.abb try this:
regexpr("ov", month.abb) > 0
Although not needed here, if "ov" were a character string that could have
special characters such as . and * that have special meaning in a regular
expression then do this to prevent such interpretation:
regexpr("ov", month.a
