Petzoldt
Cc : [EMAIL PROTECTED]
Objet : Re: [R] years from as.POSIXlt
On Wed, 10 Mar 2004, Thomas Petzoldt wrote:
(without copying me)
Prof Brian Ripley wrote:
See ?julian, which says
Note:
Other components such as the day of the month or the
year are very
Prof Brian Ripley wrote:
See ?julian, which says
Note:
Other components such as the day of the month or the year are very
easy to computes: just use 'as.POSIXlt' and extract the relevant
component.
Hello,
unfortunately not all mentioned functions work on all machines. Where
as.numeric(format(x, f=%j))
which is the right code, works perfectly, too.
Thomas P.
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---
Date: Wed, 10 Mar 2004 00:04:30 +0100
From: Thomas Petzoldt [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Re: [R] years from as.POSIXlt
Prof Brian Ripley wrote:
See ?julian, which says
Note:
Other components such as the day of the month
On Wed, 10 Mar 2004, Thomas Petzoldt wrote:
as.numeric(format(x, f=%j))
which is the right code, works perfectly, too.
but the recommended procedure is on the help page ?julian, and of course
works perfectly. Just use 1+x$yday if you want 1-based day of the year.
--
Brian D. Ripley,
On Wed, 10 Mar 2004, Thomas Petzoldt wrote:
(without copying me)
Prof Brian Ripley wrote:
See ?julian, which says
Note:
Other components such as the day of the month or the year are very
easy to computes: just use 'as.POSIXlt' and extract the relevant
Hi,
how it's possible to extract the year and the number
of days from Julian date. i'm little confused about the last two
functions and ?years .
EDATE comes from sqlQuery with as.is=T
EDATE - as.POSIXlt(datvears$ENROLLDAY)
Many thanks, Christian
EDATE[1:5]
[1] 2000-06-30 11:25:01
