Hi R-spatialists,
I'm working with a big list of polygons (imported into R with package
sp as a SpatialPolygonDataFrame, and I am trying to calculate minimum
distances between each pair of polygons. For this, I need to get the
lines for each polygons. At the moment I can't seem to find a way to
do
I have managed to create several SpatialPoygonsDataFrame objects in
which the polygons have duplicate vertices. That is, there are
duplicate rows in the matrix in "coords" slot of the object.
In most cases, the object has just one polygon, but in at least one
case it has an outer polygon and a
On Fri, 15 Jun 2007, Agustin Lobo wrote:
> Hi r-sig-geos,
>
> I'm starting to use package sp
> and can't figure how to subscript an sp grid
> object by coordinates. This is what I do:
>
> First, I read the raster image of the example:
>
> x <- GDAL.open(system.file("pictures/erdas_spnad83.tif", pa
Hi r-sig-geos,
I'm starting to use package sp
and can't figure how to subscript an sp grid
object by coordinates. This is what I do:
First, I read the raster image of the example:
x <- GDAL.open(system.file("pictures/erdas_spnad83.tif", package =
"rgdal")[1])
erdas_spnad83 <- asSGDF_GROD(x, out
When filled.countour returns, the coordinate system does not match the
plot (part of drawing the scale). One of the easiest ways to add to the
plot is using the plot.axes argument. For example:
> library(maps)
> data(ozone)
>
> fit <- loess(median ~ x+y, data=ozone)
>
> tmp.x <- seq( min(ozone
On Thu, 14 Jun 2007, Thomas Szegvary wrote:
> I am using the RNetCDF package to extract data from netcdf files. I've got a
> nc file (from an atmospheric model) with coordinates as the following:
>> dim(lon)
> [1] 67 46
>> dim(lat)
> [1] 67 46
>
> I suppose the lon and lat values are given to grid
Hi there
I have a filled.contour and want to add a the contours of a shapefile (i.e.
European boarders). I tried to do this with the map library, but didn't
succed using par(new=TRUE) to add the boundaries, the filled.contour is not
a plot says R.
What else can I do?
Thanks,Thomas
__
Thomas Sz
