On 10/25/07, Agustin Lobo <[EMAIL PROTECTED]> wrote:
> Hi,
>
> Is image() able to display a color composite?
The displayDataset() function should use the colormap. You will need
to open with GDAL.open().
THK
>
> I've made an 8 bit color composite (with another software), saved it as
> geotif and
By default, image() displays the first band of a SpatialGrid*DataFrame -
controlled by the second argument - column number or name.
You can display a 3-band RGB image by creating a new band and lut -
check out the example in ?SGDF2PCT
Agustin Lobo wrote:
> Hi,
>
> Is image() able to display
Hi,
Is image() able to display a color composite?
I've made an 8 bit color composite (with another software), saved it as
geotif and then, in R:
t1pcs <- readGDAL("G:/PERU/imorm2007/test1TNT/PC1_3s8.tif")
image(t1pcs)
but the color table seems wrong. I've checked with other programs, i.e.,
Irfa
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Agus:
I don't konw the structure of "delme.cl.im", but with the
SpatialGridDataFrame example of meuse:
data(meuse.grid) # only the non-missing valued cells
coordinates(meuse.grid) = c("x", "y") # promote to SpatialPointsDataFrame
gridded(meuse.grid) <- TRUE # promote to SpatialPixelsDataFrame
x
Is it possible to display a SpatialGridDataFrame object
and use identify() to check values? I've tried after displaying
with image() and always get
warning: no point with 0.25 inches
This is what I do:
image(delme.cl.im, col = bpy.colors(n=10))
identify([EMAIL PROTECTED])
If I use
identify(delme
