On Mon, 1 Dec 2008, Gabor Grothendieck wrote:
Use this:
lm(database[c(variable[i], "INCOME")])
On Mon, Dec 1, 2008 at 7:45 PM, Raphael Saldanha
<[EMAIL PROTECTED]> wrote:
Hi!
I had a database with some variables in sequence. Let me say: TX01, TX02,
TX03 and TX04.
But I need to run some regr
How about doing something like:
x <- 1:100
y1 <- 1 + 2*x + rnorm(x)
y2 <- 2 + 3*x + rnorm(x)
lm(cbind(y1,y2) ~ x)
This is much faster.
Yours sincerely / Venlig hilsen
Frede Aakmann Tøgersen
Statistician, M.Sc., Ph.D.
Modeling, Statistics and Risk Analysis
Wind and Site Competence Centre
T
Use this:
lm(database[c(variable[i], "INCOME")])
On Mon, Dec 1, 2008 at 7:45 PM, Raphael Saldanha
<[EMAIL PROTECTED]> wrote:
> Hi!
>
> I had a database with some variables in sequence. Let me say: TX01, TX02,
> TX03 and TX04.
>
> But I need to run some regressions changing the variables... so:
>
Hi Raphael,
If you truly only need to run 4 regressions you might be less confused
if you just do
test1 <- lm(TX01 ~ INCOME, data = database)
test2 <- lm(TX02 ~ INCOME, data = database)
test3 <- lm(TX03 ~ INCOME, data = database)
test4 <- lm(TX04 ~ INCOME, data = database)
If you need to do t
Hi!
I had a database with some variables in sequence. Let me say: TX01, TX02,
TX03 and TX04.
But I need to run some regressions changing the variables... so:
variable <- paste("TX0", 1:4, sep="")
for(i in 1:4){
test[i] <- lm(variable[i] ~ INCOME, data=database)
}
But doesn't work... lm tries t
